Anti-reflecting Membrane, And Display Apparatus, Optical Storage Medium And Solar Energy Converting Device Having The Same, And Production Method Of The Membrane - Patent 8088475 by Patents-419

The present invention relates to an anti-reflecting membrane formed on a plate, various products using the same, optical member provided with the anti-reflecting membrane, and various display apparatuses, e.g., personal computers, TV sets,cellular phones and PDAs, provided with the anti-reflecting membrane on the outermost surface.BACKGROUND OF THE INVENTION When a display apparatus works in a condition of high light intensity, e.g., under bright illumination or in the open air, outside light is reflected by the surface to cause reflection of ambient objects in the display screen. This tends tomake the image hard to watch, in particular a dark portion of low light intensity. Various attempts have been made to solve these problems, e.g., coating the display screen with an anti-reflecting membrane to reduce light reflection by interference, orroughening the screen's outermost surface to reduce regular reflection intensity by scattering. However, roughened surface causes light scattering, which makes the image slightly vague. A display screen not surface-roughened tends to show a clearer image for a personal computer which frequently displays letters and TV set which frequentlyshows pictures. Plates on monitor surfaces are generally made of transparent materials, e.g., glass (refractive index: 1.5 to 1.54), acrylic resin (refractive index: 1.49) and polyethylene terephthalate resin (refractive index: 1.56). Reflectance R of these members is given by the following Equation (1): R={(n.sub.1-n.sub.0)/(n.sub.1+n.sub.0)}.sup.2 (1) wherein, n.sub.0: refractive index of air n.sub.1: refractive index of the member Equation (1) can be reduced to Equation(2), knowing that refractive index of air n.sub.0 is generally 1.0. R={(n.sub.1-1)/(n.sub.1+1)}.sup.2 (2) The transparent member of glass, acrylic resin or PET resin has a reflectance of 3.9 to 4.0, 3.9 or 4.8%, found by substituting n.sub.1 in Equation (2) by a refractive index of each material. The member coated with a