Oct 5 Related Rates Sphere Problem

MathJax TeX Test PageThe volume of a sphere is increasing at a rate of $410 \text{ ft}^3$/sec. at the instant when the volume is 16 cubic feet, calculate the length of the radius, the rate at which the radius changes, and the rate at which the surface area changes.

Before we start, he important things to initially do are to express the volume or surface area as a function of one variable: time.
$$V = 16 + 410t$$
You already know that the rate the volume changes is $410 ft^3/sec$, so you don't have to differentiate that. So, we now write volume as a function of radius, to solve the first part, and we write radius as a function of time, by rewriting the volume equation.