y = HoldForm[Cos[a x - b]]
cos(a x-b)
{y == Cos[a x - b], y == Cos[a x - b] // ReleaseHold}
{cos(a x-b) == cos(b-a x), True}
Bob Hanlon
---- HO JEE HOU <Jeehou.Ho at nottingham.edu.my> wrote:
=============
Dear all,
I have an expression which I wish to put it in the form of Cos[a x - b].
However when I input it to Mathematica, it automatically converted to
Cos[b - a x]. Similarly, for Sin[a x - b] it would become -Sin[b - ax].
I understand that both are equivalent, but I just wish to have the form
of Cos[a x - b]. Is there any way to do this?
Thank you very much.
Best regards,
Ho