> If you compute with infinite precision the sum of the (negative) powers of 2
> corresponding to that expansion, you should get
>
> 1261007895663739/9007199254740992
>
> Try this:
<skiped>
> Does it work?
Yes, it does.I did not jnow that 9007199254740992 is a power of 2. It
looks that it is a way that the developpers used.
However, I would not agree that one can say that it is an infinite
precision of 0.14 in usual sens. In fact the error introduced by the
transformation is about MachinePrecision.
Vlad