Ratio of momentum

A. Bullets from two revolvers are fired with the same velocity. The bullet from gun #1 is twice as heavy as the bullet from gun #2. Gun #1 weights three times as much as gun #2. The ratio of momentum imparted to gun #1 to that imparted to gun #2 is ?

B. Two bodies, A and B, have equal kinetic energies. The mass of A is nine times that of B. The ratio of the momentum of A to that of B is ?

2. Relevant equations
KE = 1/2*m*v2
P = m*v

3. The attempt at a solutionA. I figured if the gun weighed 3 times gun #2, and the bullet weighed twice as heavy, the answer would be 6:1?

B.
And for A: 1/2*9m*v2
So for B: 1/2*m*(3v)2

So for momentum:
A = 9m*v
B = m*3v

So the ratio is: 3:1?

I'm pretty sure Problem A is wrong, just not sure what to do. However, I think I did Problem B correctly, but I'm not positive.

Why are you only using one velocity? Both bullets have the same velocity, the question tells you that, but the two velocities for the guns are different. remember that momentum is a mass multiplied by a velocity.

Why are you only using one velocity? Both bullets have the same velocity, the question tells you that, but the two velocities for the guns are different. remember that momentum is a mass multiplied by a velocity.

Sorry, It's easier when I apply actual data into a scenario, I'm not good with understanding problems like these...