I'd like you to take a look at the following circuit. It is powered by 3V or 6V. With 3V on the input you get 80V out and with 6V you get 200V out. I know that the transistor (JE200, not 2N3502) produces the AC signal and amplifies the voltage, but what does the transformer do? I want to power it with a 9V battery and have an adjustable potentiometer from 200V to 0V. Can someone explain how I calculate the correct potentiometer value?

I made a mistake, with a 3V input you get 80V out and with a 6V input you get 200V out. The actual circuit only consumes 70mA at 3V and 250mA at 6V. Now that I think about it, I'll bet the transistor produces the AC and the transformer amplifies the voltage...hope i'm right. I'm still not sure how to calculate the correct pot value...

Nevermind! I figured it out once more, apparently the minimum current a person can feel is 1mA. So I'm going to use a 500K pot - 200V/500,000 = 0.4mA. This should work fine. Below you'll find the changed circuit:

You do not need a DC to DC converter and you do not need a potentiometer. Make the circuit the way it was designed and limit its output current with a resistor from its output to the person.
Use a 6V battery.

You do not need a DC to DC converter and you do not need a potentiometer. Make the circuit the way it was designed and limit its output current with a resistor from its output to the person.
Use a 6V battery.

Click to expand...

Well, I am going to put it in a compact case so i dont know... I would like the pot to adjust the shock level from 0V to max.