The wind chill factor represents the equivalent air temperature at a standard wind speed that would produce the same heat loss as the given temperature and wind speed. One formula for computing the equivalent temperature is
\[W(t)= 33-\frac{ (10.45+10\sqrt{v-v})(33-t }{ 2204 }\]
\[W(t)=33-1.5958(33-t)\]
\[if 0\le v <1.79\]
\[if 1.79\le v <20\]
\[if v \ge20\]

4 years ago

OpenStudy (yacoub1993):

@hartnn

4 years ago

hartnn (hartnn):

ok

4 years ago

hartnn (hartnn):

thanks for the info :P

4 years ago

hartnn (hartnn):

i'll need a question to help you answer it :)

4 years ago

OpenStudy (yacoub1993):

do you want me to capture it

4 years ago

OpenStudy (yacoub1993):

and attach it here

4 years ago

hartnn (hartnn):

you'll attach the same thing you posted?
i am asking, what do we need to find? or do ? or solve?

4 years ago

hartnn (hartnn):

i just see an incorrect expression and definition of the terms in it

4 years ago

OpenStudy (yacoub1993):

4 years ago

OpenStudy (yacoub1993):

can you see the question more clear now @hartnn

4 years ago

hartnn (hartnn):

i am able to see some information, but not the question.
what we need to do ? do we have to find W for a specific 'v' ?

4 years ago

OpenStudy (yacoub1993):

idont know what they need
that is the way they gave it and said solve

4 years ago

hartnn (hartnn):

anything after/before "solve" ?? because i cannot see 'solve' too
i can see W(t) expression though

4 years ago

OpenStudy (yacoub1993):

sory my mistake here is the other part of the question
where v represents the wind speed (in meters per second) and t represents the air temperature . Compute the wind chill for an air temperature of 15°C and a wind speed of 12 meters per second. (Round the answer to one decimal place.)

4 years ago

OpenStudy (yacoub1993):

@hartnn i made a mistake that is the rest part of the question

4 years ago

hartnn (hartnn):

no problem :)
so we have t =15
with v =12, we need to select one of the 3 expression for W

4 years ago

hartnn (hartnn):

v =12 lies in which range of v ?

4 years ago

hartnn (hartnn):

1st, 2nd or 3rd ?

4 years ago

OpenStudy (yacoub1993):

2nd

4 years ago

hartnn (hartnn):

correct!

4 years ago

hartnn (hartnn):

so just plug in v=12 and t=15
in the middle expression

4 years ago

OpenStudy (yacoub1993):

@hartnn sory i am having some connection problems but can you continue solving Please

Compute the wind chill for an air temperature of 15°C and a wind speed of 12 meters per second. (Round the answer to one decimal place.)
you have to find W(t) for v= 12 m/sec
as you know, you must use the 2nd equation.
replace v with 12 and t with 15
\[ W(t)= 33-\frac{ (10.45+10\sqrt{12}-12)(33-15) }{ 2204 } \]
now it is an "order of operations" problem.

4 years ago

OpenStudy (yacoub1993):

what do you mean by "order of operation"

4 years ago

OpenStudy (phi):

do the operations inside parens first. then exponents (or square roots)
then multiply/divide, and last add/subtract.