2013-03-30T23:33:30ZFluxBBhttp://www.mathisfunforum.com/viewtopic.php?id=19128Neither do I, so I would think you should have some questions about it.]]>http://www.mathisfunforum.com/profile.php?id=337902013-03-30T23:33:30Zhttp://www.mathisfunforum.com/viewtopic.php?pid=259891#p259891No, I do not.]]>http://www.mathisfunforum.com/profile.php?id=1187862013-03-30T23:32:30Zhttp://www.mathisfunforum.com/viewtopic.php?pid=259889#p259889Hmmm, not so fast! Do you recognize my formula?]]>http://www.mathisfunforum.com/profile.php?id=337902013-03-30T23:13:04Zhttp://www.mathisfunforum.com/viewtopic.php?pid=259877#p259877Hm, then the solution for n people seems to be 66*(2^n-2)/(12^6).

]]>http://www.mathisfunforum.com/profile.php?id=337902013-03-30T18:35:29Zhttp://www.mathisfunforum.com/viewtopic.php?pid=259849#p259849No I haven't; actually I wrote the solution in a Word doc, but when I copied it here, the formatting was screwed up (]]>http://www.mathisfunforum.com/profile.php?id=1799792013-03-30T17:57:52Zhttp://www.mathisfunforum.com/viewtopic.php?pid=259848#p259848Hi anna_gg;

Sorry, Bobby, I don't imply that yours is not easy to understand

No problem. I am glad to see your solution. Also, anyone who can do that problem I do not characterize as a novice.

Have you tried Codecogs?

]]>http://www.mathisfunforum.com/profile.php?id=337902013-03-30T17:11:42Zhttp://www.mathisfunforum.com/viewtopic.php?pid=259846#p259846I will try to share my solution in a more explanatory way (Sorry, Bobby, I don't imply that yours is not easy to understand - it is just that I am a novice and not very familiar with complicated solutions!!):We first must calculate all the possible ways to get 2 months out of 12, that is

Then we must calculate all the different ways by which we can arrange the birthdays of 6 people in these 2 months: Either 5 people have their birthday in the first month and 1 in the second, or 4 in the first and 2 in the second etc. Obviously we do not consider the case of 0/6 or 6/0. For the first case, we first get 1 out of 6 (for the first persons birthday) and then for the second persons it will be 5 out of 5, and so on.Here is the calculation:

The total probability is the product of the first two (66 x 62) divided by the total number of all different ways by which 6 people can have their birthdays in 12 different months, that is, 12^6.

So we have

]]>http://www.mathisfunforum.com/profile.php?id=1799792013-03-30T16:58:00Zhttp://www.mathisfunforum.com/viewtopic.php?pid=259840#p259840Better than that. With that you compute the answer to anna's problem quickly.]]>http://www.mathisfunforum.com/profile.php?id=337902013-03-29T11:33:24Zhttp://www.mathisfunforum.com/viewtopic.php?pid=259713#p259713It looks like some stuff I've seen on Wiki's distributions pages.]]>http://www.mathisfunforum.com/profile.php?id=1187862013-03-29T11:32:15Zhttp://www.mathisfunforum.com/viewtopic.php?pid=259712#p259712Looks like a formula! So you do not recognize it?]]>http://www.mathisfunforum.com/profile.php?id=337902013-03-29T11:18:03Zhttp://www.mathisfunforum.com/viewtopic.php?pid=259706#p259706What the hell is that?]]>http://www.mathisfunforum.com/profile.php?id=1187862013-03-29T10:54:19Zhttp://www.mathisfunforum.com/viewtopic.php?pid=259704#p259704This looks like some of Feller's work or maybe Rose, I am not sure.