If my brother and I can invite 5 friends from a class of 15 to a party how many ways can we each pick 5 friends?

What's the probability 6 different friends are invited?

What's the prob my brother and I invite the same 5 people?

Well, since this question's gone unanswered for a while, I'll stick my neck out here ....

(a) .

The reasoning: Each brother can choose 5 friends from 15 in ways. So the number of ways two brothers can choose is .

(b) .

The reasoning:

numerator = number of ways the two brothers can choose 6 different friends: one brother chooses 5 friends from the 15, then the other brother chooses 4 friends from that 5 and 1 friend from the remaining 10.

denominator = number of ways the two brothers can choose 5 friends each = answer from part (a).

(c) .

But since arrangements under restriction aren't my forte, you should probably wait for confirmation or refutation ......