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Rodrick mixes a martini that has a volume of 'n' ounces havi [#permalink]

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28 Dec 2009, 12:18

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Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?

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Guys, please help me out. I want to know how to solve this question using the Allegation method.I know the other way(using equations) but I need to understand the Allegation method.

Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume.He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin musthe add?

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13 Jul 2010, 04:48

I want to respond to the following question appearing in this forum:_____Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume.He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin musthe add?

A) n/6B) n/3C) 3n/5D) 5n/6E) 8n/5_____

The answer C) 3n/5 for Gin is obviously not correct for the following reason. Gin's concentration is 60% which is much higher than that of Vermouth (40%). Obviously, you need less of Gin than Vermouth to make n quantity of Martin. Consequently, the answer we should be looking for must be below 1/2 of the quantity of the total (n). The correct proportional volume of Gin is 3n/10 using the Alligation Method. Make a nine cell table like the one below (Unfortunately, I can't draw the table here. I have added starred lines to space the figures to create a Table image). Obtain diagonal differences and enter them as shown in top right and bottom right boxes(always positive numbers). Add right hand column (15+35=50). Calculate amount of Gin proportion as (n/50)*15 =3/10 n. Calculate amount of Vermouth proportion as (n/50)*35 =7/10 n

By the method of allegations :If we have 2 quantities to mix ,one with higher percentage H and other with lower percentage L ,to get a desired solution R %we proceed as Percentage of Lower in final Result = H-R Percentage of Higher in final Result = R-L.

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Guys, please help me out. I want to know how to solve this question using the Allegation method.I know the other way(using equations) but I need to understand the Allegation method.

Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume.He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin musthe add?

given that after adding g ounces of gin , V should become 25% of the total volume.

=>Volume of V/total volume = 25/100

=> 0.4n /n+g = 1/4

=> 1.6n = n+g

=> g = 3n/5

Answer is C.

petrifiedbutstanding wrote:

Bunuel wrote:

gaurav05nov wrote:

Guys, please help me out. I want to know how to solve this question using the Allegation method.I know the other way(using equations) but I need to understand the Allegation method.

Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume.He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin musthe add?

Show Tags

Guys, please help me out. I want to know how to solve this question using the Allegation method.I know the other way(using equations) but I need to understand the Allegation method.

Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume.He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin musthe add?

He wants to mix a martini of 60% Gin with a liquid that is 100% Gin to give a mixture with 75% Gin (because 25% is Vermouth)Using the mixtures formula discussed here (http://www.veritasprep.com/blog/2011/03 ... -averages/), we get,w1/w2 = (100 - 75)/(75 - 60) = 5:3Martini:Pure Gin must be added in the ratio 5:3. So if martini is n, pure gin must be (3/5)n

Re: Rodrick mixes a martini that has a volume of 'n' ounces havi [#permalink]

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09 Sep 2013, 00:30

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gaurav05nov wrote:

Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?

Re: Rodrick mixes a martini that has a volume of 'n' ounces havi [#permalink]

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16 Dec 2013, 05:52

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gaurav05nov wrote:

Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?

Re: Rodrick mixes a martini that has a volume of 'n' ounces havi [#permalink]

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13 Jan 2015, 06:27

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Re: Rodrick mixes a martini that has a volume of 'n' ounces havi [#permalink]

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13 Jan 2015, 06:50

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PROBLEM:Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?

Guys, please help me out. I want to know how to solve this question using the Allegation method.I know the other way(using equations) but I need to understand the Allegation method.

Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume.He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin musthe add?

He wants to mix a martini of 60% Gin with a liquid that is 100% Gin to give a mixture with 75% Gin (because 25% is Vermouth)Using the mixtures formula discussed here (http://www.veritasprep.com/blog/2011/03 ... -averages/), we get,w1/w2 = (100 - 75)/(75 - 60) = 5:3Martini:Pure Gin must be added in the ratio 5:3. So if martini is n, pure gin must be (3/5)n