Re: Partition of a set

Are those sets in disjoint? Non-empty? Does their union equal the whole set (in this case, )? If so, then is a partition of

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The only potentially confusing thing here is that the original definition of had redundancies - two different names for the same set - and so that might seem to make it not a partition. However, a set with redundant (even if differently named) elements is the same as the set with unique elements.