Edit: Or actually, will never be zero, so the denominator would have to be a root function or a fraction to be a vertical tangent line?

Oct 15th 2009, 08:37 AM

Mush

Quote:

Originally Posted by hazecraze

Find vertical tangent lines of . (how do you do square root symbols?)

, x=complex number, so there are no vertical tangent lines?

Edit: Or actually, will never be zero, so the denominator would have to be a root function or a fraction to be a vertical tangent line?

There are no verticals, you are right.

To do square roots, put backslash before the word sqrt.

Also, to do a fraction, write \frac{numerator}{denominator}

Oct 15th 2009, 09:26 AM

hazecraze

So the denominator would have to be a root function or a fraction to be a vertical tangent line?

Oct 15th 2009, 09:42 AM

Mush

Quote:

Originally Posted by hazecraze

So the denominator would have to be a root function or a fraction to be a vertical tangent line?

In order for a function to have vertical asymptotes, there must be points at which the function is not defined.

In functions like these, the most common 'cause' of a function being undefined is a divide by zero at for some value of x. Thus, yes, the denominator of such a function must be equal to zero at some value of x.

There are other reasons why a function may be undefined, but in this type of example, you'd need some sort of division by 0, and that does not occur in the real plane for this function.