Leave some vertical space and draw a horizontal line, much like down for addition problems:#-6/5__|color(white)("aaaaaa")5color(white)("aaaaaa")11color(white)("aaaaaaa")26color(white)("aaaaaaa")26##color(white)("aaaaaaaaaa")##color(white)("aaaaaaaaaa")ul(color(white)("aaaaaaaaaaaaaaaaaaaaaaaaaaaa")#

Lastly, copy down the first coefficient (5) and write it below the line:

As you can see, we began with 5, and then multiplied that by #-6/5# to get #-6#, which we wrote under the #11#. The sum #11 + (-6)# is #5#, which we write under the line. We then repeat again and again until we write the final value #2# (colored in red here for emphasis).

All that remains is writing the result. The last value (in red) represents the remainder of the division, and should be written over the divisor #5x+6#.

The other numbers under the line are all coefficients of the "whole" part of the resulting polynomial. There is one trick remaining: Since the original divisor was #5x#, each of these values are currently 5 times their final values. Reading from right to left these represent the constant term, #x# term, and #x^2# term, all of which should be divided by 5 before being written in the final result. Thus: