I am trying to use VTF, to create a terrain. I have a heightmap of 1024x1024.
I have sampled this for vertex heights on a grid that is 2048x2048, stretching the heightmap so there are 2 vertices for every pixel. I want to be able to stretch it further. For the vertices that have no pixel, they will interpolate (If I'm not mistaken, HLSL handles that when you sample a texture).

To work out my texture coordinates I am taking the vertex position and dividing by the grid size.

My problem is the 1st 2 rows of vertices along 1 axis are giving me the same heights.

In theory the texture coordinates should be:
for the 1st row 0/2048 = 0.
for the 2nd 1/2048 = 0.00048828125.

I have used PIX to try and debug it but on both rows the coordinates both are calculated as 0.000
It seems to be rounding after 3 decimal places. therefore both rows sample the same pixels and the heights are identical.

Can I use better precision or is there another way to sample using exact coordinates? rather than 0.0-1.0

I'm guessing this would occur elsewhere on the terrain also, but its harder to find. at a glance it looks like its all used correct pixel samples and interpolated the ones that are in between.

Hey thanks for the reply. I have actually seen your large terrain already. Kinda what inspired what I'm doing. Im taking a mesh and moving around with the camera and snapping to the grid and then just pulling the heights from a texture.

I think that DX9 VTF only supports POINT filtering

I can specify LINEAR in the sampler and get different results when specifying POINT. with point there are clear "Steps" but linear produces a smooth slope.[source lang="plain"]Texture HeightMap_LowRes;sampler TextureSampler = sampler_state{ texture = <HeightMap_LowRes> ; magfilter = linear; minfilter = linear; mipfilter= linear; AddressU = clamp; AddressV = clamp;};[/source]from the vertex shader...[source lang="plain"]float4 VTFCoords = float4((worldPosition.x)/TerrainSize,(worldPosition.z)/TerrainSize,0,0);float height =(float)tex2Dlod(TextureSampler, VTFCoords);[/source]When the worldPosition.x is 0 or 1. the same height occurs (when the z is constant of course).

In your method you pull the 4 nearest pixels and do your own interpolation. You must work out those 4 points as texture coordinates. You said your heightmap is over 8k in one dimension. do you not get a problem with calculating the precise pixel coordinates? My issue is at the edge. So if I were to interpolate from 4 points at the edge, they would be 2 matching pairs as the coordinates seem to be the same. (I need to recheck in PIX after changing the decimal places).

Thank you for the links.

Kinda got my heart set on VTF as I have tried other LOD methods before, but am yet to try VTF. Your "pizza" method seems quite elegant. For now Im just using a square mesh, I want to try and make it quite low res, My application doesnt require showing a terrain right to the horizon, just the immediate area around it, but it needs to support larger terrains, so when you move it will show a new area instantly (from 1 heightmap). What I have so far looks great. I just need to sort out the interpolation. But even if I do I think my samples will pick the same heights.

DX9 might or might not support linear filtering, depending on the GPU. Actual DX9-era GPUs won't support it, but more modern ones might. You can check the caps at runtime to see if your code will work or not.

If your texture is 1024 pixels wide, then 0 is the left-hand boundary of the left-most pixel, 1/1024 is the right-hand boundary of the same pixel and 0.5/1024 is the centre of that pixel.So, assuming you've got the "clamp" address mode set, then it's expected that 0 and 1/2048 will return the same value.

The way texcoords work is that 0 is the left/top edge of your image, and 1 is the bottom/right edge, which is very abstract and disconnected from the notion of pixels.If you're thinking in integer coordinates for an array of 1024 pixels, then 0 is the index of the leftmost pixel and 1023 is the index of the rightmost pixel.

To reconcile the two, we can imagine a grid of 1024 squares scaled down to be 1 unit wide total. Each cell would then be 1/1024 units wide. The offset from the edge of a squares to it's centre would be 0.5/1024 units. We can pretend that these squares are pixels, even though that's not technically true (pixels are just points in 2d space with no pre-defined shape or size -- the filtering mode used gives them shape, e.g. nearest/point filtering makes them appear as squares).So to convert from an integer pixel index to a texture coordinate at the very centre of that pixel, you can use (pixel index + 0.5) / pixel count.

So, yes, 1023.5/1024 is the exact centre of the rightmost pixel.If clamp mode is used, then 1.0 is the right hand edge of the rightmost pixel. If wrap mode is used, then 1.0/0.0 are the same -- on the edge between the first and last pixels.