anonymous

4 years ago

Which of the following is not a step used when graphing the equation y = −x + 8 using the
slope-intercept method?
Plot the x-intercept (32, 0).
Plot the y-intercept (0, 8).
Draw a line through the two points.
Count down 1 and right 4 from the y-intercept.

probably would not graph the x-intercept. The most logically thing to do would be to graph the y-intercept and then count down 1 (I'm going down 1 because of the negative sign) and go right 4. Another way to do it would be to create a "T" table, where you plug in values for x and evaluate y using -1/4x + 8. I prefer this method and I will use a minimum of three x values to plug in to make sure I am not making a mistake. Some other things to consider - whenever you have a NEGATIVE slope, the graph should be going down to the right, and a POSITIVE slope should be going up to the right.

It is asking to graph using the slope-intercept method. THis method involves obtaining the y-intercept and then following the slope. This means plot the y-intercept and then plot another point using the slope and then draw the line through it. Therefore, fo r this particular method, there is no need for an x-intercept. The fact that the form y = mx + b has y-intercept and slope, but not the x-intercept further proves the point. That being said, it is choice ?