The static String.raw() method is a tag function of template literals, similar to the r prefix in Python or the @ prefix in C# for string literals (yet there is a difference: see explanations in this issue). It's used to get the raw string form of template strings, that is, substitutions (e.g. ${foo}) are processed, but escapes (e.g. \n) are not.

Return value

Exceptions

A TypeError is thrown if the first argument is not a well formed object.

Description

In most cases, String.raw() is used with template strings. The first syntax mentioned above is only rarely used, because the JavaScript engine will call this with proper arguments for you, just like with other tag functions.

String.raw() is the only built-in tag function of template strings; it works just like the default template function and performs concatenation. You can even re-implement it with normal JavaScript code.

Examples

Using String.raw()

String.raw`Hi\n${2+3}!`;
// 'Hi\n5!', the character after 'Hi'
// is not a newline character,
// '\' and 'n' are two characters.
String.raw`Hi\u000A!`;
// 'Hi\u000A!', same here, this time we will get the
// \, u, 0, 0, 0, A, 6 characters.
// All kinds of escape characters will be ineffective
// and backslashes will be present in the output string.
// You can confirm this by checking the .length property
// of the string.
let name = 'Bob';
String.raw`Hi\n${name}!`;
// 'Hi\nBob!', substitutions are processed.
// Normally you would not call String.raw() as a function,
// but to simulate `t${0}e${1}s${2}t` you can do:
String.raw({ raw: 'test' }, 0, 1, 2); // 't0e1s2t'
// Note that 'test', a string, is an array-like object
// The following is equivalent to
// `foo${2 + 3}bar${'Java' + 'Script'}baz`
String.raw({
raw: ['foo', 'bar', 'baz']
}, 2 + 3, 'Java' + 'Script'); // 'foo5barJavaScriptbaz'