Cannot Set Property Of Undefined Prototype

This forum is now read-only. Your code will look like so : Class = function(){}; Class.extend = function(obj) { var result = Object.create(this); if (obj) { for (var key in obj) { if(typeof obj[key] == 'function'){ Test failed. up vote 12 down vote You have to set d[a] to either an associative array, or an object: d[a] = []; d[a] = {}; Without setting, this is what's happening: d[a] check over here

Converting the weight of a potato into a letter grade What crime would be illegal to uncover in medieval Europe? Why is looping over find's output bad practice? keyCommands is undefined where you try to use it, thus, one of the potential problems mentioned in my answer could be matching your problem. –Lajos Arpad Mar 2 '15 at 8:31 The contents of the constructor’s prototype property. http://stackoverflow.com/questions/4584370/defining-javascript-class-prototype-methods

Remove the trailing parens if you don't need to invoke it. Draw a hollow square of # with given width Default value for date field Moving a member function from base class to derived class breaks the program for no obvious reason Is this Business or Tourism?

For b i get the username and the prototype. If you weren't in strict, then this would be the global object, and you'd have not received the error message, which wouldn't be helpful. This looks the same as the correct answers I see on this forum but I get an error message: TypeError: Cannot set property 'meow' of undefined function Cat(name, breed) { this.name Browse other questions tagged javascript or ask your own question.

Hyper Derivative definition. How do I handle this? You signed in with another tab or window. robertjd referenced this issue in stormpath/stormpath-sdk-node Apr 7, 2015 Merged Fix 0.8 tests by using npm 1.4.3 #157 Sign up for free to join this conversation on GitHub.

Why do languages require parenthesis around expressions when used with "if" and "while"? Is that what you want? Ballpark salary equivalent today of "healthcare benefits" in the US? Why do languages require parenthesis around expressions when used with "if" and "while"?

How do I handle this? We’ve called an ordinary function that doesn’t return anything. Browse other questions tagged javascript node.js prototype or ask your own question. this content You signed in with another tab or window.

Read this before you copy that code. Do Morpheus and his crew kill potential Ones? Compare elements iteratively What is with the speech audience?

Actually, it’s worse than that: _foo//=> 'Fsked Up' JavaScript sets this to the global environment by default for calling an ordinary function, so we’ve just blundered about in

So we can write: Fubar.prototype.concatenated=function(){returnthis._foo+" "+ We saw that "use strict" can help, but it’s not a panacea. Two-headed version of \Rightarrow or \implies Why is looping over find's output bad practice? See above for more details.npm ERR!

Let’s try it on the original Fubar: functionFubar(foo,bar){this._foo=foo;thishave a peek at these guys That said, the original answer you were given to that question was wrong, but has now been corrected.

asked 4 years ago viewed 2964 times active 4 years ago Upcoming Events 2016 Community Moderator Election ends Nov 22 Related 1900Detecting an undefined object property6652How do JavaScript closures work?3271What is Test failed. you just spelled 'prototype' incorrectly when you were entering the teaching protocol. 218 points Submitted by MegMartin almost 2 years ago A JavaScript Constructor Problem, and Three Solutions via raganwald.com preamble Not the answer you're looking for?

We recommend upgrading to the latest Safari, Google Chrome, or Firefox. One problem this solves is that new Fubar(...) does not compose. Why did Michael Corleone not forgive his brother Fredo? Join them; it only takes a minute: Sign up Javascript Object.prototype is undefined up vote 1 down vote favorite I'm trying to create a simple extensible "class" in javascript but when

On 1941 Dec 7, could Japan have destroyed the Panama Canal instead of Pearl Harbor in a surprise attack? Skip to content Ignore Learn more Please note that GitHub no longer supports old versions of Firefox. result.protorype[key] should be result.prototype[key] share|improve this answer answered Jun 20 '12 at 9:50 phenomnomnominal 4,31311637 corrected it give always the same error jsfiddle.net/paglia_s/z62eA –Matteo Pagliazzi Jun 20 '12 at There are aspects of associative arrays that are not true about Javacript objects that can trip up coders. (True associate arrays aren[t limited by requiring keys to be strings.