So I know the sum a cube gives me (1+t)(1-t+t^2) for the first part of the problem, right?
I am having difficulty with 3(1+t)^2 since I know there is no sum of squares; how am I supposed to factor/multiply this?

Thanks for your help!

Aug 24th 2008, 09:29 AM

galactus

Expand out the numerator, and it is obvious the denominator is just t.

The numerator simplifies and factors to

When we divide by t we get

Aug 24th 2008, 09:35 AM

overduex

Would you mind showing me how you got t(t^2+6t+11) ?
I keep getting way too many numbers that cannot be simplied or cancelled.

Aug 24th 2008, 09:36 AM

overduex

*simplified, sorry

Aug 24th 2008, 09:48 AM

galactus

The numerator simplifies to

Then, I just factored out a t.

Aug 24th 2008, 10:07 AM

overduex

Quote:

Originally Posted by galactus

The numerator simplifies to

Then, I just factored out a t.

I'm sorry but I really just don't understand this. Can you possibly show me what you did from the beginning of the problem? I just don't see how it comes out
Thank you, I really do appreciate your time and sorry for all the questions.