A .6-kg mass at the end of a spring vibrates 3.0 times per second with an amplitude of .13 m. Determine a.) the velocity when it passes the equilibrium point, b.) the velocity when it is .1 m from equilibrium. c.) the total energy of the system, and d.) the equation describing the motion of the mass, assuming that x was a maximum at t=0?

b) 0.1 m from equilibrium is 0.1/0.13 = 76.92% of maximum deflection, and will have 0.7692^2 = 59.17% of maximum spring potential energy, which is 59.17% of total energy.
1-0.5917 = 40.83% of the energy will be kinetic energy at 0.1 m stretch.
Velocity wil be sqrt(0.4083)= 63.90% of maximum, or 0.521 m/s

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