8-bit binary into 7 segments

Our group have a project in Computer Architecture that we have to add an instruction in SAP-1, we decided to do the comparator that compares two 8-bit binary numbers. The output must be displayed using seven segments.
eg.
condition output (8 LED)
if a less than b 11110000
if a is equal to b 11111111
if a is greater than b 00001111

Our problem is we don't know how to convert it into (3) 7-segment display. Can someone please teach us how to convert 8-bit binary into 7 segments display? Your help would be greatly appreciated.

You have to convert to a decimal value for each condition. Then you will need three 7 segment displays to indicate the values. You might find it simpler to use a dedicated IC for driving the displays. Something like a CD4547 might do.

You can use three of these ICs to drive three seven segment displays as to be able to see an 8-bit number.

If the number is 10001100 split it into:

010 001 100

The rightmost three bits will drive the rightmost display, the middle three bits the middle display and the left three bits the left display. There is one extra bit on the leftmost bits as to make a group of three bits. Also, you need to add another 0 bit because the display driver has 4 inputs to show some other figures too. Thus the 8 bit value will be

doesn't sound to me like he needs 3 digits to display, rather just to display the binary combination provided out of the little logic statement.

That being said, a single character 7 segment display generally has 7 segments and a dot (i.e. 8 bits).

So output a > b you drive 8 pins into the 7 segment display as your binary 11110000. Just have other driven orientations for other conditions and make sure your logic never drives two conditions at once through enable/disable lines of any buffer ICs.

hi..i said the idea of mik3 to our professor..but unfortunately she didn't accepted it..the reason?same as alberto's reason..she needs the exact conversion of 8-bit binary to decimal and display it in 3 seven segments..
pls..can someone help me to analyze it..is there an IC that can help us?

what is the IC given by beenthere?i am not familiar of that..i tried to look its datasheet but i am not familiar of the terms..

i think what they need is a circuit design that will show 8bit binary to decimal. for example: 4bit binary that will show a decimal value using (2)7segment. 1 7segment can show a 0-9 value but a 4 bit binary have to show 0-15. In order for us to show 0-15 we have to use (2)decoder for each 7segment but we have to use a full adder to have an output from 10-15. 00-09 and 10-15 in 7segment. in binary 0000-1001 and 1011-1111. but a decoder for 7segment can only handle 0000-1001 so we have to use full adder to have an input for the second decoder(the tens digit) from 0000-0001.

darn! its really hard to explain! haha! my nose is already bleeding! i think i just have to make a picture of it.

the 2nd input must have a value of 0110(6) to have a value of 1 0000, but we have to add that six when the 1st input has the value of 1010-1111(10-15). we already solve it. but our problem is how to convert a 8bit binary to decimal?
0000 0000-1001 0000-1001 000-099(7segment)
0001 0000-1001 0000-1001 100-199(7segment)- most probably our problem will be in this part
0010 0000-0101 0000-0101 200-255(7segment)- and this one too haha