Hey guys,
So in a universal set that $\displaystyle x$ are all natural numbers and $\displaystyle x \le 12$
does $\displaystyle C = \{ x | 3|x \}$ mean all positive integers divisible by 3?
So in this case it would be 3, 6, 9, 12 ?

thanks!

Mar 20th 2010, 01:47 AM

emakarov

I would say so.

To avoid confusing notation, it is possible to replace the first vertical bar with a colon: $\displaystyle \{x:3\mathrel{\vert} x\}$.

Mar 20th 2010, 06:08 AM

jvignacio

Quote:

Originally Posted by emakarov

I would say so.

To avoid confusing notation, it is possible to replace the first vertical bar with a colon: $\displaystyle \{x:3\mathrel{\vert} x\}$.

Would I start with the brackets $\displaystyle (A\cup \overline{B})$ then get that result and work out $\displaystyle [RESULT] \cap C$ ? Also i cant figure out $\displaystyle \overline{B} $ from the B set... any help? thank you!