mekc_tr

one year ago

F(x)= ∫cos(e^t)dt top limit ln(x) bottom limit pi, what is the derivative of F(x)

When the lower limit is a constant it drops out when taking the derivative, so it doesn't matter whether it's pi or 0 or any other constant. The question is how to deal with ln(x) as the upper limit. How about this:\[\cos(e^{\ln x})\frac{ 1 }{ x }=\frac{ \cos x }{ x }\]because e^(ln x) is just x.