From Soumya:Is the graph of an inverse variation a RECTANGULAR HYPERBOLA? If it is, then how can be the equation of a rectangular hyperbola be xy=constant , whereas in the books it is written that the graph of a rectangular hyperbola is- x^2-y^2=a^2?Answered by Chris Fisher.

From A student:My question is about this equation 32x*2 -18y*2 -64x +72y +248 =0
explain why as x goes to the infinity the graph of the conic looks like y= (3/4)X.

What I did to try to find the solution of this problem was to graph and then I thought that maybe trying to find the equation of the asymptotes I could do it, but it was useless -because the equation of the asymptotes is y= +4/3(X-1) -2 and that does not explain why tho conic looks like y=(3/4) x . I would really appreciate your help on this.Answered by Penny Nom.

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