In <anrkga$3v5$1 at smc.vnet.net> Allan Hayes wrote:
> Troy,
> True, interactive manipulation can be difficult.
> However, here is one way to do what you want.
> We have to do the same thing to both sides of the equation.
>
> (# - D*Sqrt[K]/C)&/@(A+B/C+D*Sqrt[K]/C\[Equal]0
>
> A + B/C == -((D*Sqrt[K])/C)
I think I have to apologize for the lack of clarity in my original post.
I had tried to word it carefully, but I deceived myself. I should have
said:
I have an expression that can be put into this form:
A + B/C + D*Sqrt[K]/C = 0
A,B,C,D, & K are all polynomials in x
I need to get it into that form and, in the end, I want it to look like
this
(D^2)*K = (A*C + B)^2
I think I gave the impression that I have polynomials A,B,C,D, & K at my
fingertips. I don't. The expression I have is given at the end of
this message.
I'm still trying to digest the respones I've garned so far. In the
meantime, I decided to post this clarification.
>
> "Troy Goodson" <Troy.D.Goodson at jpl.nasa.gov> wrote in message
> news:anp0p6$qvg$1 at smc.vnet.net...
>> I'm a newbie and, of course, the first thing I want to do is
>> apparently one of the most complicated...
>>
>> I have an expression that looks like this:
>>
>> A + B/C + D*Sqrt[K]/C = 0
>>
>> A,B,C,D, & K are all polynomials in x
>> I want it to look like this
>>
>> (D^2)*K = (A*C + B)^2
>>
>> At that point, I'll have polynomials in x on both sides. Finally, I
>> want the equation to be written out with terms grouped by powers of x,
>> but I think I can do that part :)
>>
>> I'll be very grateful to anyone who can give me some pointers. Or,
>> at least point me to some tutorial in the Mathematica documentation.
>> I've been looking over the documentation and I found Appendix A.5 in
>> The Mathematica Book, but that doesn't help me. I _need_ some
>> examples. I did find a couple of well-written posts in this newsgroup,
>> but not quite close enough to what I want.
>>
>> Thanks!
>>
>> Troy.
>>
>> =-=-=-=-=-=-=-=-=-=
>>
>> FYI, here's the expression I'm working with.
>>
>>
>> denom = Sqrt[(B^2 - r^2)^2 + 4*(r^2)*(b^2)]
>> cnu = (2*b^2 - B^2 + r^2)/denom
>> snu = -2*b*Sqrt[B^2 - b^2]/denom
>> sif = 2*r*b/denom
>> cif = (r^2 - B^2)/denom
>>
>> pdr = -Cos[ds]*Sin[q]*(snu*cif +
>> cnu*sif) - Sin[ds]*(cnu*cif - snu*sif)
>>
>> 0 == -(B^2 - b^2)*V^2/(r^2) + (((B*V)^2)/(
>> r^2) - 2*w*b*V*Cos[q]*Cos[ds] + (w*
>> r)^2 - (w*r*pdr)^2)*(Cos[qr])^2
>>
>> Although I said it's a polynomial in x, it's really a polynomial in
>> "b" that I'm after.
>>
>
>
>
>