Chemistry: The Central Science (13th Edition)

Chapter 6 - Electronic Structure of Atoms - Exercises: 6.34b

Answer

The wavelength of this light is $286.3nm$.

Work Step by Step

The wavelength of this light would be calculated according to the formula $$c=\lambda\times\nu$$
- Frequency of this light: $\nu\approx1.047\times10^{15}s^{-1}$
- Speed of light in a vacuum: $c\approx2.998\times10^8m/s$
Therefore, the wavelength of this light would be:
$\lambda=\frac{c}{\nu}=\frac{2.998\times10^8}{1.047\times10^{15}}\approx2.863\times10^{-7}m\approx286.3nm$