yeah, assuming you mean i as the square root of -1, then
i^0 = 1 (any # to the power of 0 is one)
i ^1 = i
i^2 = -1 (the square root goes away)
i^3 = -i (since the left hand side is equivalent to i^2 * i = -i )
From then on the values loop, so i^4 = 1, i^5 = i, etc. You can also make them up from the values of previous terms to verify, i.e. i^5 = i^3 * i^2 = -1*-i = i