If you take away all the edges in the diagram, and see just the points, then you can draw a single convex polygon with all those points as vertices. The pattern is the number of those vertices: 8, 6, 6, 4, 4.

Except that the resulting convex polygon doesn't use ALL the points from the original -- just the ones that conveniently fit into drawing a convex polygon. Since you said "with all those points" I'm not surprised I was the only one confused.

Would you mind to explain your guess?
For example, I would rather choose D over B simply on the basis two pentagons are offered in solutions.

Cerine explains my reasoning perfectly.

Quote:

Originally Posted by cerine

I would guess B as well. Counting the number of angles/sides, you get 12, 7, 9, 6, __. One possible pattern I see would continue 6, 5, 3, 4, 0, 3, which would make B the right answer. Of course, another possible pattern I see would continue 8, 7, 9, making A the right answer; but since this pattern kind of breaks down after that and the polygons are alternating (at least so far) between one and two per picture, I'm disinclined to go with A. Of course, it's entirely possible that the correct answer is based on a pattern I'm not seeing at all.

There are no repeating poligons in the sequence of boxes. That would eliminate answers B,D,E. And in no case outside colouring and inside colouring are the same as the previous box. That would eliminate answer C. Thus A