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|dw:1358257312264:dw| " in the figure, given that point P= point Q . AB=CD , AB=24, and PX=p . what is the length of the given radius Q?

anonymous

5 years ago

where's Q?

anonymous

5 years ago

sorry Q is where P is at on the first circle . you see how i put d twice ? well Q is where P is . get it ?

anonymous

5 years ago

hmm thought so....so u need to find out the radius QY?

anonymous

5 years ago

it just said of Q , but i guess ?

anonymous

5 years ago

can u check the question again? i didnt exactly get what u meant by point P = point Q....how can two points be equal?

anonymous

5 years ago

okay how about i just give you the answer ? , so you can understand how to get it ? ... its 15

anonymous

5 years ago

that'd be only possible if any of the following angles are given. |dw:1358258436102:dw|

anonymous

5 years ago

ready for another?

anonymous

5 years ago

sure...but dont u think we should finish solving it first?

anonymous

5 years ago

|dw:1358259367221:dw|

anonymous

5 years ago

|dw:1358258923677:dw| if point m=point N , AB-CD . QD=24 and ND=26 what is the length of LM?

anonymous

5 years ago

and yes to your last picture

anonymous

5 years ago

what was the given length of the segment that i showed in my last picture??

anonymous

5 years ago

ab=24 and px=9

anonymous

5 years ago

lol and u said PX=p :P :P
ok here's the basic theorem, lets say you draw a line from the center of a circle to any chord of the circle, and the angle formed becomes 90 degree
|dw:1358259896480:dw|
in that case, the point where the line touches the chord will bisect it, so in ur first picture, since AB=24,

anonymous

5 years ago

yay and yes . ready for the next one?

anonymous

5 years ago

okay the next one is the picture i sunt you

anonymous

5 years ago

ok let me explain the second one.
as you can see, ND=MB=26 is the radius for both the circles. QD is already given (you dont need to halve the chord like u did before, QD is already half), also. QD=LB
now use pythagorean theorem to find out LM
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