Real zeros of a polynomial function

F(x) = 4x^3 + 7x^2 - 11x - 18
The only one that I could find is -2...from what i have figured out...there is 1 positive real zero and 2 negative real zeros. I have tried everything i cant fins the other...could someone please help

F(x) = 4x^3 + 7x^2 - 11x - 18
The only one that I could find is -2...from what i have figured out...there is 1 positive real zero and 2 negative real zeros.

if you found one to be -2, you can do polynomial long division (or synthetic division) to find $\displaystyle \left( 4x^3 + 7x^2 - 11x - 18 \right) \div (x + 2)$. the result will be a quadratic, and it is easy to find the roots of that