mol calculation confusion

I need to use KN-93 which is a CAMKII inhibitor. I ordered from sigma and is 0.1 mg! I cannot see anything in bottle and that's ok. It's in powder form. Although i used to feel comfortable with mol calculations, here i am totally confused.

Formula : C26H29ClN2O4S · H3PO4
Molecular Weight : 599,03 g/mol

I need a working concentration of 10 micromol/litre. Can anyone guide me on this?

After some calculation, i see that 1 mg= 1.67*10-6 mol i.e. 1.67*10-3 mM.

I need guidance after that. Need to know how much solvent i need to inject in this bottle to have 10 micromol/litre working conc.

As an aside to the calculation conversation, I'm guessing your vial is probably not large enough to hold 17ml of solvent. I often create at 100x or 1000x stock from which to prepare my working solutions. If you were to make a 100x stock (1mM), you could add 170ul of solvent to your 0.1mg and then prepare a simple 1:100 dilution into your working solution when needed.