The radius of the inner cylinder is equal to $r_1 = 2.00$ cm. The inner radius of the cylindrical shell is equal to $r_2 = 4.40$ cm, and the outer radius of the cylindrical shell is equal to $r_3 = 6.20$ cm.

A surface charge density of $\sigma_1 = +4.60$ nC/cm$^2$ has been placed on the inner cylinder. Sufficient charge has been added to the outer cylindrical shell so that the electric field at a radius of $r_f = r_3 = 6.20$ cm is equal to $\vec{E}(r_f) = -2.10 \times 10^6 \text{ } \hat{r}$ N/C.