I tried to search some relative problems on binary operations on internet and I found this question :
if : \(\large{a\alpha b = |a-b| }\) then what will be \(\large{6\alpha 8 }\) . Of course that will be 2 but the question given is not exactly what we have in m

Don't get depressed from the help here given by me @aman07 ... we have at present many users seeing this question and I am sure that some people are still here who are aware of these type of problems. Just have patience aman... wait for them to respond

ab/4 = 9 means...
Step 1: multiply a times b
Step 2: divide by 4
the result is 9.
That means 9*4 = a*b = 36
So a and b could be 9 and 4 or 18 and 2 or 3 and 12 or any two digits that multiply to 36.
We'd need more information to narrow down the possibilities of what a and b could be. Are they both positive? Are they both positive integers? Are they both positive integers within a certain range? etc.

b*a does not neccesary means b multiply by a ,that's why i let x to identity knowing that
i will have xa/4 and assign it to a but since a*b =9 this will also means that if a take x*a i will get the same value as a*b because of the binary operator

ur questions means a*b if u take any 2 real numbers and map them the result will be in the form of multiplication of ur 2 real numbers divide by 4 and we know that tha mapping of those two numbers is equal to 9 tht's y i 've used 36 on my calculation because of the conditions i have