Calculate the cell potential for the following reaction as written at 25.00 °C, given that [Cr2 ] = 0.859 M and [Ni2 ] = 0.0190 M. Standard reduction potentials can be found here.
Cr+Ni(2+) ->Cr(2+) + Ni

Ecell = Eocell - (0.0592/n)log[(Cr^2+)/(Ni^2+)]
and you get Eocell by adding the OXIDATION for Cr to the REDUCTION of Ni^2+. I would do it here but the values in your text won't agree with the values in my OLD text.