To determine the mass percentage of water imbibed by raisins MCQ 3| Science Practicals

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Questions:

1. While performing an experiment to determine the percentage of water absorbed by raisins, the following data was obtained:
Mass of water taken in the beaker = 50 g
Mass of raisins before soaking them in water = 5 g
Mass of raisins after soaking in water for 2 hours = 8 g
The percentage of water absorbed by raisins would be
(a) (8-5)g/3g × 100
(b) (8-3)g/3g × 100
(c) (8-5)g/8g × 100
(d) (8-5)g/5g × 100

2. Each of the three beakers A, B and C contained 50 mL of distilled water. A student placed five raisins in each beaker. The raisins for each beaker weighed the same. The beakers were kept at room temperature. The raisins were removed from beaker A after 10 minutes, from beaker B after 20 minutes and from beaker C after I hour. On calculating the percentage of water absorbed by the raisins, it was found that
(a) maximum absorption of water by raisins was in beaker C.
(b) maximum absorption of water by raisins was in beaker B.
(c) minimum absorption of water by raisins was in beaker C.
(d) absorption of water by raisins are equal for all the three beakers.

3. While conducting an experiment to calculate the percentage of water absorbed by raisins which of the following materials is not required?
(a) Blotting paper
(b) Dry raisins
(c) Weighing balance
(d) Needle

4. At the end of the experiment, ‘to determine the percentage of water absorbed by raisins’, the raisins are wiped just before weighing. This is to ensure that
(a) hands do not get wet.
(b) the raisins lose water before weighing.
(c) the weighing scale does not get wet.
(d) only water absorbed by raisins is weighed.

5. A student soaked 5 g of raisins in beaker (A) containing 25 mL of ice-chilled water and another 5 g of raisins in beaker (B) containing 25 mL of tap water at room temperature. After I hour, the student observed that
(a) water absorbed by raisins in beaker (A) was more than that absorbed by raisins of beaker (B).
(b) water absorbed by raisins in beaker (B) was more than that absorbed by raisins of beaker (A).
(c) the amount of the water absorbed by the raisins of both beakers (A) and (B) was equal.
(d) no water was absorbed by raisins in either of the beakers (A) or (B).

6. Which of the following set of materials is required to set up an experiment to determine the percentage of water absorbed by raisins?
(a) Raisins, beaker of water, blotting paper, weight box, balance
(b) Raisins, beaker, balance, weight box
(c) Raisins, water, balance, weight box
(d) Raisins, water, blotting paper, balance

7. A student soaked 5 raisins each of equal weight in three beakers A, B and C each containing 100 mL of distilled water and left them at room temperature. After 10 minutes, he removed the raisins from beaker A, after 20 minutes from beaker B and after 1 hour from beaker C. He calculated the percentage absorption of water in each case. If PA, Pa and Pc denote per cent absorption, then which of the following is correct?
(a) PA = PB = PC
(b) PA < PB > PC
(c) PA > PB < PC
(d) PA < PB < PC

8. Some raisins weighed 10 g before they were placed in water for 4 hours. The raisins were then removed, wiped and weighed again. Their weight was now found to be 12.5 g. The percentage of water absorbed by them, is
(a) 2.5%
(b) 54%
(c) 12.5%
(d) 25%

9. If x represents weight of soaked raisins and y represents weight of dry raisins then [(x-y)/y] x 100 is a way to calculate percentage of
(a) water absorbed by raisins in hypertonic solution.
(b) water absorbed by raisins in hypotonic solution.
(c) water lost by raisins in hypotonic solution.
(d) water lost by raisins in hypertonic solution.

10. Four beakers contain four different liquids as mentioned below.
I. Dilute sugar solution
II. Concentrated sugar solution
III. Concentrated salt solution
IV. Double-distilled water
Five raisins are put in each of these four beakers and left there for a few hours. The maximum percentage of water will be absorbed by raisins that are put in beaker
(a) I
(b) II
(c) III
(d) IV

To determine the mass percentage of water imbibed by raisins MCQ 3

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Question 1 of 10

1. Question

While performing an experiment to determine the percentage of water absorbed by raisins, the following data was obtained:

Mass of water taken in the beaker = 50 g

Mass of raisins before soaking them in water = 5 g

Mass of raisins after soaking in water for 2 hours = 8 g

The percentage of water absorbed by raisins would be

(8-5)g / 3g × 100

(8-3)g / 3g × 100

(8-5)g / 8g × 100

(8-5)g / 5g × 100

Correct

Incorrect

Question 2 of 10

2. Question

Each of the three beakers A, B and C contained 50 mL of distilled water. A student placed five raisins in each beaker. The raisins for each beaker weighed the same. The beakers were kept at room temperature. The raisins were removed from beaker A after 10 minutes, from beaker B after 20 minutes and from beaker C after I hour. On calculating the percentage of water absorbed by the raisins, it was found that

maximum absorption of water by raisins was in beaker C.

maximum absorption of water by raisins was in beaker B.

minimum absorption of water by raisins was in beaker C.

absorption of water by raisins are equal for all the three beakers.

Correct

Incorrect

Question 3 of 10

3. Question

While conducting an experiment to calculate the percentage of water absorbed by raisins which of the following materials is not required?

Blotting paper

Dry raisins

Weighing balance

Needle

Correct

Incorrect

Question 4 of 10

4. Question

At the end of the experiment, ‘to determine the percentage of water absorbed by raisins’, the raisins are wiped just before weighing. This is to ensure that

hands do not get wet.

the raisins lose water before weighing.

the weighing scale does not get wet.

only water absorbed by raisins is weighed.

Correct

Incorrect

Question 5 of 10

5. Question

A student soaked 5 g of raisins in beaker (A) containing 25 mL of ice-chilled water and another 5 g of raisins in beaker (B) containing 25 mL of tap water at room temperature. After I hour, the student observed that

water absorbed by raisins in beaker (A) was more than that absorbed by raisins of beaker (B).

water absorbed by raisins in beaker (B) was more than that absorbed by raisins of beaker (A).

the amount of the water absorbed by the raisins of both beakers (A) and (B) was equal

no water was absorbed by raisins in either of the beakers (A) or (B).

Correct

Incorrect

Question 6 of 10

6. Question

Which of the following set of materials is required to set up an experiment to determine the percentage of water absorbed by raisins?

Raisins, beaker of water, blotting paper, weight box, balance

Raisins, beaker, balance, weight box

Raisins, water, balance, weight box

Raisins, water, blotting paper, balance

Correct

Incorrect

Question 7 of 10

7. Question

A student soaked 5 raisins each of equal weight in three beakers A, B and C each containing 100 mL of distilled water and left them at room temperature. After 10 minutes, he removed the raisins from beaker A, after 20 minutes from beaker B and after 1 hour from beaker C. He calculated the percentage absorption of water in each case. If PA, Pa and Pc denote per cent absorption, then which of the following is correct?

PA = PB = PC

PA < PB > PC

PA > PB < PC

PA < PB < PC

Correct

Incorrect

Question 8 of 10

8. Question

Some raisins weighed 10 g before they were placed in water for 4 hours. The raisins were then removed, wiped and weighed again. Their weight was now found to be 12.5 g. The percentage of water absorbed by them, is

2.5%

54%

12.5%

25%

Correct

Incorrect

Question 9 of 10

9. Question

If x represents weight of soaked raisins and y represents weight of dry raisins then [(x-y)/y] x 100 is a way to calculate percentage of

water absorbed by raisins in hypertonic solution.

water absorbed by raisins in hypotonic solution.

water lost by raisins in hypotonic solution.

water lost by raisins in hypertonic solution.

Correct

Incorrect

Question 10 of 10

10. Question

Four beakers contain four different liquids as mentioned below

I .Dilute sugar solution

II. Concentrated sugar solution

III. Concentrated salt solution

IV. Double-distilled water

Five raisins are put in each of these four beakers and left there for a few hours. The maximum percentage of water will be absorbed by raisins that are put in beaker