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Normally for a problem like this, I would just test for n>0 or n<0 but apparently this is not the case.

Any question has always to be asked , especially before going to an exam such as the GMAT ... and u are welcome

Concerning the reason, the principle is to look for the crucial "point" or value s of n,x... when those values make flip the sign of the expression in the absolute value. This is done for every absolute values of an inequation.

> The original inequation has to be studied on those 2 domains n < -2 and n > -2. Indeed, for those 2 domains, the simplified expression of |n+2| differs. That is |n+2| = n+2 when n > -2 and |n+2| = -(n+2) when n < -2.

o |n|:# n = 0

Thus,
# n > 0
# n < 0

Finally, we have to study all combined domains, from |n+2| and from |n|, in the original inequation.