Ex 10.5, 3 Construct an isosceles right-angled triangle ABC, where m∠ACB = 90° and AC = 6 cm.
Given Δ ABC where
∠ C = 90°
AC = 6 cm
Also, Δ ABC is isosceles
Now, in a right angle triangle,
Hypotenuse is the largest side.
So, it can’t be equal to any other side
∴ BC = AC = 6 cm
Let’s construct it
Steps of construction
1. Draw a line segment AC of length 6 cm
2. Now, we draw 90° from point C
Check Ex 11.1, 1 of Chapter 11 Class 9 NCERT to see how to draw 90°
3. Taking C as center,
6 cm as radius, we draw an arc
Let the point where arc intersects the ray be point B
4. Join BA
and label the sides
Thus, Δ ABC is the required triangle