Annotated within text below:
Andy Shellam wrote:
> PJ wrote:
>> Lynna Landstreet wrote:
>> Well, it does explain things a little. Unfortunately, I have tried
>> about everything imaginable before posting except the right thing.
>> I can not visualize what it is that my query is returning. Here is
>> what the code is:
>>
>> Whatever I enter as values for pg_fetch_result, the screen output is :
>>
>> resource(3) or type (pgsql result)
>> *Warning*: pg_fetch_result() [function.pg-fetch-result
>> <http://biggie/k2/function.pg-fetch-result>]: Unable to jump to row 1
>> on PostgreSQL result index 3 in
>> */usr/local/www/apache22/data/k2/test1_db.php* on line *29*
>
> This suggests that there is no row 1 in your result-set. I believe it
> is zero-based, so try fetching row 0 if your query only returns 1 row.
Been there, done that. No change.
>
>
>> I don't understand what $resuts is returning - if it is an entire
>> row, the one that the field is in that I am looking for, then why do
>> I not get a printout of the text that is in that field? The row in
>> the table is the second row and the field I am trying to retrieve is
>> the 4th field.
> $results as explained previously is just a pointer to a recordset.
> This analogy isn't brilliant, but think of your database table as a
> book. Each row on a page within that book is a record, and the words
> in that row are the data in the table's columns.
>
> When you run a query, think of yourself looking at the book's index
> for a given word. The index will tell you the pages that word is on.
> That's your $results - simply a pointer to your data.
>
> You then need to turn to that page in the book (pg_fetch_* functions)
> to start examining the lines for the word you want. Once you've got
> your line, you can find the word (column/data, from your array) you're
> looking for.
>
> Now turn that into PHP and SQL. You run your query (looking in the
> book's index) and the PostgreSQL driver will save the results into a
> block of memory in your server's RAM, returning a resource
> identifier. This is literally just saying "resource #3 is located at
> this location in the computer's memory." When you look up a record
> from that result-set, PHP then knows where to look for the data.
>
> I never really use the "or die" syntax, I tend to explicitly check the
> return values of the functions. Try this:
>
> <?php
> $db = pg_connect("host=localhost port=5432 dbname=med user=med
> password=0tscc71");
>
> // Note: according to
> http://uk2.php.net/manual/en/language.types.boolean.php a resource
> always evaluates to true,
> // therefore !$db may not evaluate to false when connection fails.
> if ($db === false)
> {
> die("Could not open connection to database server");
> }
>
> // generate and execute a query
> $query = "SELECT description FROM glossary_item WHERE
> name='Alcohol'";
> $results = pg_query($db, $query);
> var_dump ($results);
>
> if ($results === false)
> {
> die("SQL query failed: " . pg_last_error($db));
> }
> else if (pg_num_rows($results) == 0)
> {
> // Only do this if you were expecting at least 1 row back
> die("SQL query returned no rows");
> }
>
> $results_formatted = pg_fetch_all($results);
> echo "<pre>"; // need this to show output better in a HTML page
> var_dump($results_formatted);
> echo "</pre>"; // need this to show output better in a HTML page
>
> /*
> $results_formatted will then be set out like follows:
>
> $results_formatted[row_index][column_name] = column_value
> */
> pg_close($db);
> ?>
Tried your coding - returns: resource(3) of type (pgsql result) SQL
query returned no rows
The row is there... isn't that what were asking for?
To go by the book, I even changed the description to * as noted before
below.
Something is rotten in Denmark.
This is getting ridiculous - I have followed the instructions as
specified in the Postgresql documentation and examples - and it just
doesn't work.
The db is like this..
int4 ||int4 || varchar(32)|| text
_item_id || glossary_id || name || description _
2 || 1 || Alcohol || One of thetwo
major.... blah...blah.. blah
>> Am I querying correctly? The table is "glossary_item", the row I want
>> is the one that is unique in containing the word "Alcohol" in the
>> column "name"
>>
>> I changed: $query = "SELECT * FROM glossary_item WHERE name=
>> 'Alcohol'";
>> same result
>>
>> Picture me tearing out my hair...
>>
>
> Regards,
>
> Andy
>