rate of change is 6x, actual distance travelled = 3x^2?

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I've got a car that's accelerating at 6m/sec but i want to know how much space it's ...

rate of change is 6x, actual distance travelled = 3x^2?

Is that true?

I've got a car that's accelerating at 6m/sec but i want to know how much space it's actually displaced, working backwards 6m/sec is the derivative of 3m^2 so therefore 3x^2 is the actual amount the car has travelled?

This is sort of a homework question, except the homework question doesn't ask for how far the car has travelled (and this isnt' a calculus homework question)

Didn't feel like doing this the math way so I did using the spreadsheet method

I used multiple colums.

Col 1 was the number of secs passed (0 - 40).
Col 2 was the distance traveled in that second.
Col 3 was the sum of the distances of the time elapsed.
Col 4 was the quanity of 3 times the value of col 1 to the power of 2.

If you want to use some calculus...
the derivative (with respect to time) of the formula which gives you distance will give you velocity.
the derivative of the formula which gives you velocity will give you acceleration.
the definite integral of the velocity formula will give you distance
the definite integral of the acceleration formula will give you velocity.

I think I got all those right.

edit: Those formulas are only valid for speeds very small relative to c.

>> edit: Those formulas are only valid for speeds very small relative to c.

Haha! Reminds me of a good joke.

A physicist came in to work, and recounted the story of his trip to his colleagues. He explains that he was on his way to work, and was pulled over by a cop. The cop came up to him and asked, "Sir, do you realize that you just ran a red light?" To this, the physicist replied, "No officer, it must have blue-shifted, so I thought it was green." One of the physicist's colleague then asked, "So did he give you a ticket for running the red light." The physicist replied, "No. He gave me a speeding ticket instead."