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2 Take Home TestWhat type of collision is this?An 8.00 g bullet is fired into a 250 g block that is initially at rest at the edge of a table of height 1.00 m. The bullet remains in the block, and after the impact the block lands 2.00 m from the bottom of the table. Determine the initial speed of the bullet.Perfectly Inelastic CollisionWe must first figure out the combined Vf, how can we do that?Knowsm1= .008 kgm2 = 0.250kgV2i = 0V1f = V2fh=Δy =1.00mΔx = 2.00mUnknownsV1i = ?V1f = V2f = ?What else about this situation do we know?What else about this situation don’t we know?But wait!There’s moreCan we figure out time, then Vf?Now what?Vix = Vf, because velocity isConstant in the x-axis,no accel. In the X. Projectile

3 Take Home TestWhat type of collision is this?An 8.00 g bullet is fired into a 250 g block that is initially at rest at the edge of a table of height 1.00 m. The bullet remains in the block, and after the impact the block lands 2.00 m from the bottom of the table. Determine the initial speed of the bullet.Perfectly Inelastic CollisionKnowsm1= .008 kgm2 = 0.250kgV2i = 0V1f = V2fh=Δy =1.00mΔx = 2.00mUnknownsV1i = ?V1f = V2f = ?

4 Take Home TestWhat type of collision is this?A 1200 kg car traveling initially with a speed of m/s in an easterly direction crashes into the rear end of a 9000 kg truck moving in the same direction at 20.0 m/s. The velocity of the car right after the collision is 18.0 m/s to the east.What is the velocity of the truck right after the collision?How much mechanical energy is lost in the collision? Account for this loss in energy.Elastic Collision

5 Take Home TestWhat type of collision is this?A 1200 kg car traveling initially with a speed of 25.0 m/s in an easterly direction crashes into the rear end of a 9000 kg truck moving in the same direction at 20.0 m/s. The velocity of the car right after the collision is 18.0 m/s to the east. What is the velocity of the truck right after the collision? How much mechanical energy is lost in the collision? Account for this loss in energy.Elastic Collision

6 Take Home TestA block of mass m1 = 1.60 kg, initially moving to the right with a velocity of 4.00 m/s on a frictionless horizontal track, collides with a massless spring attached to a second block of mass m2 = 2.10 kg moving to the left with a velocity of m/s. The spring has a spring constant of 6.00 X 102 N/m. Determine the velocity of block 2 at the instant when block 1 is moving to the right with a velocity of m/s. Find the compression of the spring.Elastic CollisionNow we have solved for a).What is the next step to solving for the compression of the spring xf?Conservation of MomentumSince there is no friction, hence no loss of energy how could we simplify this?Conservation of Energy ->

7 Take Home TestA block of mass m1 = 1.60 kg, initially moving to the right with a velocity of 4.00 m/s on a frictionless horizontal track, collides with a massless spring attached to a second block of mass m2 = 2.10 kg moving to the left with a velocity of m/s. The spring has a spring constant of 6.00 X 102 N/m. Find the compression of the spring.Conservation of Xi = 0,now solve for XfDistribute the 2 canceling all ½Divide out k and √ both sides

8 Take Home TestWhat type of collision?A car with mass 1.50 x 103 kg traveling east at a speed of m/s collides at an intersection with a 2.50 x 103 kg van traveling north at a speed of 20.0 m/s. Find the magnitude and direction of the velocity of the wreckage after the collision, assuming that the vehicles undergo a perfectly inelastic collision (that is, they stick together) and assuming that frictions between the vehicles and the road can be neglected.Conservation of momentum,Expand this equation out for perfectly inelastic collisionThe pf is moving in two dimension of space, oh no!The combined velocities are 2Dpxf pyfΔp, but we don’t know the θWhat do we know?We know what cosθ isWe know what sinθ isThe definition of tangent is the ratio of sinθ to cosθ

9 Take Home TestWhat type of collision?A car with mass 1.50 x 103 kg traveling east at a speed of m/s collides at an intersection with a 2.50 x 103 kg van traveling north at a speed of 20.0 m/s. Find the magnitude and direction of the velocity of the wreckage after the collision, assuming that the vehicles undergo a perfectly inelastic collision (that is, they stick together) and assuming that frictions between the vehicles and the road can be neglected.Conservation of momentum,Expand this equation out for perfectly inelastic collisionThe pf is moving in two dimension of space, oh no!The combined velocities are 2Dpxf pyfΔp, but we don’t know the θWhat do we know?We know what cosθ isWe know what sinθ isThe definition of tangent is the ratio of sinθ to cosθ

10 Take Home TestWhat type of collision?A car with mass 1.50 x 103 kg traveling east at a speed of m/s collides at an intersection with a 2.50 x 103 kg van traveling north at a speed of 20.0 m/s. Find the magnitude and direction of the velocity of the wreckage after the collision, assuming that the vehicles undergo a perfectly inelastic collision (that is, they stick together) and assuming that frictions between the vehicles and the road can be neglected.The definition of tangent is the ratio of sinθ to cosθWhat can I do with this information?Do I know what cosθ is equal to?Do I know what sinθ is equal to?What can I do with this information?

11 Take Home TestConsider a frictionless track. A block of mass m1 = 5.00 kg is released from A. It makes a head-on elastic collision at B with block of mass m2 = 10.0 kg that is initially at rest. Calculate the maximum height to which m1 rises after the collision m2 moves to the right with a velocity of 3.3 m/s.