This took a little lateral thinking. I'm not an expert, so anyone out there is free to double-check my working.

Q. How many different isosceles triangles are possible if the the sides must have whole number lengths and the perimeter must be 93 inches? (Note that this question doesn't ask you to state all the possible triangles, as you said in your post, but how many triangles are possible.)

So the range of possible y values is from 1 to 91 - that's 91 values. And the range of possible x values is from 1 to 46 - that's 46 possible values. Uh-oh! We can't have a ton of triangles without any x values. More trial and error required.

Let’s imagine that y = 2.93 = 2x + 291 = 2xx = not a whole number, so this is not a possible answer.

As you can see, y can only be an odd number. This slashes half of the possible triangles. Our range of possible y values is now odd numbers only from 1 to 91. That's 46 possible values. Both our x and our y are now giving us 46 possible triangles! That's great.

One final step is to exclude the values of y = 31, x = 31, because these would give us an equilateral, not isoceles, triangle.