(Original post by 2kk2)
for the last question were you meant to add Hbr to the alkene so you get a haloalkane which formed the secondary alcohol - what were the regeants and how many marks would you lsoe if you missed out the regeants

Pretty that the reagent for turning the the alkene into the blank product (C4H8Br2) was Br2. Then, to turn that into a diol, you could use NaOH.

(Original post by Clintbarton)
It would be halogenation - just Br2 because you can't create -OH from the the H-C formed in nucleophilic addition. The reagents were Br2 and H2O as steam for the second part?

What did people get when it asked for the equilibrium concentration of SO3 in the question asking about yield, I got something like square root of 30 after rearranging the equation and simplified, but I'm pretty sure that's wrong?

What was the % error? My answer was something like 1.7%. And I've said that to decrease the error you have to add a bigger mass of hydrated salt so that more water would be lost which will decrease the (error / mass) fraction.

(Original post by A Sajid)
No. For that question they gave conc and vol. So you can work out the moles from that. And then using the moles, you can work out mass by doing moles x mr. That would given you the mass in g which is what you need to do q=mct