Yes, it is guaranteed by the standard. As per the C11 standard document, chapter 6.5.8, paragraph 6, [Relational operators] Each of the operators < (less than), > (greater than), <= (less than or equal to), and >= (greater than or equal to) shall yield 1 if the specified relation is...

In practice they are the same; in theory they are different, but only when the __bool__ method has side effects: >>> class Weird: state = False def __bool__(self): self.state = not self.state return self.state >>> x = Weird(); print(x if x else 'no x available') <__main__.Weird object at 0x0000000003513160> >>>...

&& is "short circuiting". The expression on the right is never executed if the expression on the left evaluates to false. The same is true for ||, which never executes the expression on the right if the expression on the left is true. & and | are normally used for...

The bitwise negation-operator is ~. Example: int i = 6; System.out.println(~i); // Prints -7 If you want to treat the integer as an unsigned 16-bit integer (i.e. disregard from the most significant 16 bits) you should do public static int u16neg(int i) { return ~i & 0xFFFF; } Example: System.out.println(u16neg(0b00000000_00000000_00000000_00000110));...

The issue in your code is that 'a' always evaluates to True and you are saying: "is 'a' True or is 'b' in mystring True". def is_chars_in_strings(strings, chars): answer = [] for string in strings: a = False for char in chars: if char in string: a = True break...

The expression has in the middle, outside any parenthesis: OR 1 ||. It does not matter how the left and right expressions evaluate, at the end they are combined with OR TRUE and the result is always TRUE. The printed value is A....

You cannot hook into the and and or logical operators, because they short-circuit; the left-hand expression is evaluated first and if the result of that expression determines the outcome, the right-hand expression is never evaluated even. The operation returns the value of the last expression evaluated. In your case, the...

|| is the logical or -operator. It has a short-circuiting behaviour such that if the left side is true, the right side is not evaluated (because the result of the logical or is known to be true already from the true left side). In this case it is used in...

Try this. There were a few issues with the abs(R(i,i)-R(i-1,i-1)) condition for the while loop. function [R] = romberg(f,a,b,delta,nmax) R=zeros(nmax,nmax); R(1,1)=(f(a)+f(b))*(b-a)/2; i=2; E=2*delta; while i<nmax && E>delta m=2^(i-1); R(i,1)=trapez(f,a,b,m); for j=2:i R(i,j)=R(i,j-1)+(R(i,j-1)-R(i-1,j-1))/(4^j-1); end E=abs(R(i,i)-R(i-1,i-1)); i=i+1; end ...

You want to use a Gravity Forms conditional shortcode in your notification message. It looks like this: [gravityforms action="conditional" merge_tag="{Field:1}" condition="is" value="desired value"]Show this content if the field is equal to the field value I specified earlier[/gravityforms] You can also check out this full tutorial (images included)....

Higher precedence of an operator doesn't guarantee that it will be evaluated first but it guarantees that the operands will be binds (parenthesize) to it first. ++x || ++y && ++z; will be parenthesize as ( (++x) || ( (++y) && (++z) ) ); Since || operator guarantees the evaluation...

You can add brackets around the separate operations and apply them in order. e.g. !(!(~x)) i.e. !! is 2 NOT's What happens to some value if you perform one NOT is: If x == 0 then !x == 1, otherwise !x == 0 So, if you would perform another NOT,...

The three statements inside the brackets do fundamentally different things: The first line assigns 5 to f, and then uses it to subset y.1 The second and third line compare f to 3 (either less than or greater than), and use the result of the comparison (FALSE in the first...

The expression ( a || b || c ) returns anything that is truthy on the first-come-first served basis. Here a is truthy and hence used. If a is falsey b will be used. If it is falsey too, c will be used. So, you always end up comparing "one"...

As per the Spec for Binary Logical Operators The value produced by a && or || operator is not necessarily of type Boolean. The value produced will always be the value of one of the two operand expressions. This is a feature used in javascript a lot, one common use...

First of all: do whatever you want. Secondly, here are two style conventions from two large projects, Drupal: Unary operators (operators that operate on only one value), such as ++, should not have a space between the operator and the variable or number they are operating on. and Symfony: Place...

To remove the loop, you can use bsxfun, keeping the rest of your script: res = sum(bsxfun(@lt,a',k).*bsxfun(@lt,b',k),1).'; Basically, it applies the operator less-than to the pairs of vectors (a,k) and (b,k); the transposition guarantees that you compare a column vector to a row one, leading to a matrix result. The...

In groovy, the ==~ operator (aka the "match" operator) is used for regular expression matching. != is just a plain old regular "not equals". So these are very different. cf. http://groovy-lang.org/operators.html...

|| is the equivalent to saying 'or'. So your code is returning true if any of the values are true. This is what it's saying : if ([self errorIsServerError:error] or [self errorIsBadRequest:error] or [self errorIsNetworkError:error]) If any of those are true then { return YES; } ...

The condition in the if statement is really weird: When something should execute when either the first value is greater than the second or the second is greater than the first, then that's like checking whether the values are indifferent! So if normalDegrees > degreesInACircle || normalDegrees < degreesInACircle is...

There are 2 issues here. First, your if statement will compare each entry in the string x{n,1}.Tag to each entry in the string 'Channel1'. If the dimensions are not the same, you will get an error. To fix this, you could use the string compare function, strcmp. The other issue...

&& will do a short circuit evaluation, so if the first condition is false, there is no need to check the second condition. Considering that, your second code snippet appears better since comparison for string.IsNullOrEmpty(ParentSetId) could be cheaper as compared to going through the list of items and checking using...

There can't be a function implementing the underlying functionality. Assume there is a function scor which implements this operator, then calling scor(true,B) would evaluate B before calling scor, but the operator does not evaluate B. Obviously scor could be defined [email protected](x,y)(x||y), but it will evaluate B in the upper case....

90<avg>=70 does not evaluate to "avg between 90 and 70" in C. You have to write it as: else if ((90 > avg) && (avg >= 70)) Further, it's redundant. By failing the first if you know that avg is not >= 90, so you can skip that check and...

The & operator performs a bitwise AND operation—i.e. it operates independently on each bit, and returns the resulting bits in corresponding locations. So it would, naturally, return 64 if bit 6 was the only location in which both its arguments had a 1. You may be confusing its behaviour with...

You can use set -xv to turn on debugging. It will show you the problem: bash interprets the things in [[ .. ]] as strings and tests them with -n. None of them is emtpy, so it works as 'true true' everytime. To fix it, just remove the [[ and...

If i understand this correct, you want the values in $msaArray, where $billingList contains customerIDs which are present in $msaClients but their corresponding Accounted time should not be eual to $idzero( 0 in this case) PS C:\> $msaArray = ($billingList | where {(($msaclients -contains $_.customerid)) -and ($_.'accounted time' -ne $idzero)})...

( $foo && $bar ) == $baz does not do what you think it does; it first evaluates the && operation, getting the value of $foo if $foo is true and otherwise getting the value of $bar, then compares that to $baz. You need to explicitly spell it out as...

Starting from version 2.6 you can use $anyElementTrue: db.test.aggregate({ $project: { like: { $anyElementTrue: ["$found"] } } }); See this: http://docs.mongodb.org/manual/reference/operator/aggregation/anyElementTrue/#exp._S_anyElementTrue If you use earlier version then I'm afraid that you'll have to use either map/reduce or $unwind -> $group combination. Something like that: db.test.aggregate([ { $unwind: "found" }, {...

First of all, thanks for pointing out that the spec isn't clear on the non-dynamic nullable-bool case. I will fix that in a future version. The compiler's behavior is the intended behavior; && and || are not supposed to work on nullable bools. The dynamic binder does not seem to...

... ? ... : ... is a ternary operator. It exists in a lot of languages. It's used like that: variable = test ? assignIfTrue : assignIfFalse; In your case, thisUserName will be assigned with getCurrentUserName() if empId is empty, and with empId.ToUpperCase() if not....

Instead of : if(empty($usr_details['email'])=== true && empty($usr_details['password'])=== true){ Try this : if($usr_details['email'] === NULL || $usr_details['password'] === NULL){ For empty database value, NULL is better. Edit: Your query will return empty cause you check $usr_details['email'] only, which is not found in database. So condition will be meet. If you want...

I had to guess your column names and make up a table: Use EXISTS: CREATE table FRIENDS(person_id INT, friend_id INT) go SELECT * FROM person WHERE EXISTS (SELECT * FROM friends f JOIN person per ON f.friend_id = per.id WHERE per.name ='mark' AND person.id = f.person_id) AND EXISTS (SELECT *...

Though the symbol used for it looks similar, this is not a boolean operation, it's a bitwise operation and returns an int, not a boolean. See also: http://docs.oracle.com/javase/tutorial/java/nutsandbolts/op3.html Note that you used & (bitwise AND) and not && (logical AND). ...

! is called negation operator. It is a logical operator. See the wikipedia entry here. if(!s--) The order in which it executes check the value of s is 0 or not , if s is 0, if condition is success [thanks to the ! operator], otherwise, failure. After that, decrement...

It's normal to evaluate always to True. The reason is that OR means if that one of the values is True it will take this one. Update to your new question: The answer is that "||" has a greater precedence than "or" // The result of the expression (false ||...

Directly quoting the C11 standard, chapter §6.5.3.3, (emphasis mine) The result of the logical negation operator ! is 0 if the value of its operand compares unequal to 0, 1 if the value of its operand compares equal to 0. The result has type int.... So, the result of the...

In each iteration of the loop you are effectively calculating c_i = e ^ ( p + c_(i-1) ) If you wish to reverse the loop then given a c_i you need to calculate c_(i-1) However as you said xoring twice gets you back to the original value and xor...

Unfortunately with MATLAB you need to use temporary variables. It doesn't support this kind of indexing, though it is quite natural and I would love if they supported it. You would have to do this: x = Time(something==X); y = x(1); Octave does have the ability of doing this kind...

Because of return arr;, which you have placed inside your for loop. As soon as the code runs through the first element, it hits the return and leaves the function with the array as it was after the first run of the loop. Just move the return statement outside the...

I think there's a problem in your boolean logic. If you want F & I to represent dates within the past three months, then you're ruling out any entries where F >= three months OR I >= three months. It'd be less confusing to use De Morgan’s law on your...

There are two factors at play here that make this code slow. You cannot see this from the IL, only the machine code can give you insight. First is the general one associated with the AndAlso operator. It is a short-circuiting operator, the right-hand side operand does not get evaluated...

&& is logical AND. & is bitwise. Are you sure you want a logical AND? Your storing the result in a 16, 24 and 32 bit register but logical and only ever has a 1 bit output. It is 1 bit as it is typically used in an if expression...

I guess that by "is more relevant" you mean what other people would phrase as "binds more tightly" or "has higher precedence". In XQuery, a and b or c is parsed as (a and b) or c, not as a and (b or c). This may be seen in productions...

The two sub expressions (reset = '0') and (queue_size < 1024) return a boolean value. The and operator also returns a boolean result, which you are trying to assign to a std_logic output. The solution: input_ready <= '1' when (reset = '0') and (queue_size < 1024) else '0'; Note: This...

As already mentioned in the comments: Doing this inline is madness and you are much better off using a separate function / .m file. It will be Faster Easier to read Easier to write Easier to debug You could do this for example in a similar way to this: function...

Here is the formula according to your discription: =IF(ISNUMBER(SEARCH("No",J2)),IF(E2>=DATE(2014,4,10),"Pass",IF(OR(AND(ISNUMBER(SEARCH("Cancel",G2)),ISNUMBER(SEARCH("No",K2))),AND(ISNUMBER(SEARCH("Void",G2)),ISNUMBER(SEARCH("Yes",K2)))),"Fail","Pass")),"N/A") or if you'd like, you can use this UDF: Function formulasMakeMyHeadHurt(J2 As String, E2 As String, _ G2 As String, K2 As String, _ givenDate As Date) As String Dim res As String If J2 Like "*No*" Then If CDate(E2) >=...

Well, finally I found the problem. It's not related with this line at all, but a sentence like 10 lines below in a method call where I was passing the second parameter without parameter name. By the way, that line wasn't marked as error by XCode :-( it seems that...

It just doesn't work that way, you can't compare one value against multiple other values using OR, you have to compare each value individually. The closest you'll get is using Array.indexOf if ( ['a', 'b', 'c'].indexOf(choice2) != -1 ) The reason it doesn't work is because OR and AND checks...

There are two very important tools to vectorization - bsxfun and logical indexing. Now, bsxfun does work with logical operators, so with just these two functions, you can achieve most of your vectorized code. bsxfun and logical indexing in Image Processing How and when to use logical indexing? In cases,...

If the left hand side of && evaluates as a false value, the whole expression evaluates as the left hand side. Otherwise it evaluates as the right hand side. 2 is a true value, so 2 && 3 is 3. For comparison, try console.log(0 && 1) and console.log(false && "something")....

In your code if (gameAnswer == ('H' || 'h')) does not do what you think it does. Change that to if ((gameAnswer[0] == 'H') || (gameAnswer[0] == 'h')) //gameAnswer is an array Similarly, for all other occurrences. Also, scanf(" %c", &startAnswer); should be scanf(" %c", &startAnswer[0]); and likewise Note: If...

You should never use == when comparing double precision numbers in MATLAB. The reason is, as you state in the the question, that some numbers can't be represented precisely using binary numbers the same way 1/3 can't be written precisely using decimal numbers. What you should do is something like...

if((strlen($f) < 3 || strlen($f) > 16) || (strlen($l) < 3 || strlen($l) > 16)) Replace && in the middle by || What you did only throws the error when both aren't valid. You want to throw it when one of them is....

This is due to the strength of the operator binding, as operators are applied in a very particular order. or is very loose, it has the lowest priority. The || operator is very strong, the opposite of that. Note how in that table || comes before =, but or comes...

It's simply because if (false && true || true) is equivalent to (&& has a higher precedence) if ((false && true) || true) which is if (false || true) which is... true. Note: In the expression true || true && false, the part true && false is called a dead...

If you "cmd-click" on the word "Swift" in the statement import Swift in Xcode and search for || then you'll find that it is declared as func ||<T : BooleanType>(lhs: T, rhs: @autoclosure () -> Bool) -> Bool The reason is the "short-circuiting" behaviour of the || operator: If the...

but I was under the impression that && would stop as soon as it found the first false? You are correct. But that didn't happen in your either of the examples. In your both example 'O' and 'X', are string objects, which has truthy value. In the example ('X'...

Assuming your 'c1', ... are just a single char constants, you can use: if ( strchr("12345", ch) != NULL ) ... ("12345" are c1, c2, ...) strchr() will, however, also match the implcit trailing NUL terminator ('\0'). If that is a problem, you can compare this value explicitly. As the...