I have a little article on it ,but it does not explain much.
In the article Ce+4, H20, CH2(CO2H)2 are the reactants and CO2, H+, Ce+3, HCO2H are the products.
The equation is CH2(C02H)2+2H2O+2xCe+4=(x-1)CO2+(4-x)HCO2H+2x-Ce+3+2xH+
How does one obtain the (x-1), (4-x), and the 2x?