Another logarithm problem

I keep getting blocked every few pages by something I cant figure out with these logarithm problems, and I apologize for posting up so many questions, but I am really struggling.

The problem is as follows:

3 * e^-2x = 10

Basically, I cant seem to figure out the order, or how to break it down correctly. I typically start off by dividing both sides by 3, but then it goes downhill from there. How do I deal with that e^-2x? I have tried all kind of stuff, and I am not finding a simple solution. The book makes it seem like it should be elementary, since it doesnt even explain it, and it is an example. Maybe it is because it is almost midnight, but I cannot for the life of me see what I am missing. Thanks.

Re: Another logarithm problem

Originally Posted by Latsabb

The book I am working in just introduced e, and has yet to introduce ln.

Yet, it asks you to solve ? Has it dealt with logarithms in general, then? If you have logarithms base 10 ("common" logarithms), you can take the logarithm of both sides to get log(3)- 2x log(e)= 1 and then solve for x: x= (log(3)- 1)/(2log(e)).