a)The initial kinetic enrgy of the block is the product of Exerted force along the movent of the block and the velocity of the block (1/2)mv^2 = (1/2) 6*2^2 =12 J.

b)The 75 N force makes block move along the inclination for 8m inclined to the direction of force. So the work done is the product of the component of 75N along the inclination and the distance of 8meter = (75Ncos37)*8 = 479.1813 J

c)

Work done by the frictional force = (-25N)(-8m) = 200 J . The negative force worked against the direction of force, It is work done against the movement.

d)

The work done by the gravity: The gravitational force = 6kg(-g)* along 8sin37 but against the direction of gravitational force = 283.3826J.

d) The nomal force: {(6kg *cos37)+75N sin 37} * cos 90 = 0

e)

The net work done by the conservation of energy PE + KE = constant. Therefore after pushing 8 meter incline, the net energy spent is the gained potential energy by 6kg mass from ground level to a height of (8sin37) meter=mgh = 6kg*g*8sin 37 = 283.3827J