In order to make the right border line up, I need to have the actual maximum value in the variable. (In my real example I will have column headers and multiple columns, but they are not necessary to reproduce the problem).

If it makes it easier to find a solution, I can guarantee that the data values will never contain spaces.

Yep, you need to do the adding within the loop. I'd use a List<string> as it supports LINQ: XmlNodeList skillNameNodeList=SkillXML.GetElementsByTagName("name"); List<string> skills = new List<string>(); foreach (XmlNode skillNameNode in skillNameNodeList) { skills.Add(skillNameNode.Attributes["value"].Value); } ...

As others have said, this format is truly horrible, and will break as soon as the XML embedded in the JSON will contain double quotes (because in the JSON they will be encoded as \", which will make the XML invalid). The JSON should really be embedded as CDATA. Now,...

IEnumerable<string> values = new List<string>(); values = … Probably not going to be a big deal, but why create a new List<string>() just to throw it away. Replace this with either: IEnumerable<string> values; values = … If you need values defined in a previous scope, or else just: Enumerable<string> values...

<xsl:variable name="max_a_width"> <xsl:for-each select="data"> <xsl:sort select="string-length(@a)" data-type="number" /> <xsl:if test="position() = last()"> <xsl:value-of select="string-length(@a)" /> </xsl:if> </xsl:for-each> </xsl:variable> This is the general method of picking from an ordered list of derived values in XSLT 1.0. If you want to pick the minimum/maximum from actual (natively sortable) values, you can take...

Content encoding and character encoding are not the same thing. Content encoding refers to compression such as gzip. Since getContentEncoding() is null, that tells you there's no compression. You should be looking at conn.getContentType(), because the character encoding can usually be found in the content-type response header. conn.getContentType() might return...

You can ignore pretty much all your code, the issue is just this: XDocument people = new XDocument("Persons"); You can't create an XDocument containing a string, you need to add an element: XDocument people = new XDocument( new XElement("Persons", original.XPathSelectElements(xpathFilterDups))); ...

My guess is that you make a mistake while processing the result NodeList. Try the following approach: NodeList results = (NodeList) xpath.evaluate(..); for (int i = 0; i < nodelist.getLength(); i++) { Node node = (Node) nodelist.item(i); ... } ...

You can use a key in order to count the properties in the sort instruction. A stylesheet containing the following: <xsl:key name="p" match="property" use="@agency"/> <xsl:template match="/immo"> <result> <xsl:for-each select="agency"> <xsl:sort select="count(key('p', @name))"/> <res id="{ @name }" count="{ count(key('p', @name)) }"/> </xsl:for-each> </result> </xsl:template> when applied to the following input: <immo>...

UPDATE Using an XDocument vs an XmlDocument, I believe this does what you're asking without using loops. This is dependent on the elements being in the order of <PhoneType> <PhonePrimaryYN> <PhoneNumber> string xml = "<?xml version=\"1.0\"?>" + "<Root>" + " <PhoneType dataType=\"string\">" + " <Value>CELL</Value>" + " </PhoneType>" + "...

To produce a valid output HTML document you just need to add exclude-result-prefixes="xsi xslFormatting" on the <ins:stylesheet> (root) element of your stylesheet. But indeed in your stylesheet you don't use the xsi and xslFormatting namespaces anywhere. Thus you could also modify your stylesheet by removing these namespaces declarations, leading you...

It depends on your intention. If you want to directly push part or all of the XML to an entity/document object for saving to a database then the JMSSerializerBundle can do this very smartly and is definitely the best way to do it. If however you just want to extract...

If you are using them as meta-documents and they are sent to the parser, then converted as HTML and as long as the converted HTMLs do not have any irrelevant tags, it is fine! So, if the following code: <requirement> THE REQUIREMENT HERE </requirement> Gets converted into something like: <!--...

EMI and CustomerName are elements under json so you can use .find() to find those elements and then text() to get its value. $(data).find("json").each(function (i, item) { var heures = $(item).find("CustomerName").text(); var nbr = $(item).find("EMI").text(); console.log(heures); }); .attr() is used to get the attribute value of an element like in...

You need a FrameLayout. In a FrameLayout, the children are overlapped on top of each other with the last child being at the topmost. activity_main.xml <FrameLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" xmlns:fab="http://schemas.android.com/apk/res-auto" android:layout_width="match_parent" android:layout_height="match_parent" android:fitsSystemWindows="true"> <LinearLayout android:layout_width="match_parent" android:layout_height="match_parent"...

1) Your template is applied to 3 elements, and for each of them, loops over all the parents li elements (yes, for each of them, ask all the li elements, children of the grand-father of the current content, which are all the 3 li elements, each time). 2) Because that's...

Is "User Info" and "Course Data" is a different entity. If it is so, I think you may encapsulate them in one entity. XmlTextWriter writer = new XmlTextWriter(path, System.Text.Encoding.UTF8); writer.WriteStartDocument(true); writer.Formatting = Formatting.Indented; writer.Indentation = 4; writer.WriteStartElement("My Entity"); /* It is a biggest one*/ writer.WriteStartElement("User Info"); writer.WriteStartElement("Name"); writer.WriteString(userName); writer.WriteEndElement(); writer.WriteStartElement("Tutor...

Try it this way: <xsl:key name="kFirstText" match="*[not(self::type1[not(preceding-sibling::*[1][self::type1])])]" use="generate-id(preceding-sibling::type1[not(preceding-sibling::*[1][self::type1])][1])"/> This excludes the "leader" nodes from the group retrieved by the key....

If you're happy to convert it into LINQ to XML, it's really simple: XDocument original = ...; // However you load the original document // Separated out for clarity - could be inlined, of course string xpath = "//Person[not(PersonID = following::Person/PersonID)]" XDocument people = new XDocument( new XElement("Persons", original.XPathSelectElements(xpath) )...

You are operating on the original data instead of filtered data. You should maintain a reference to original data and use the filtered data for all other purposes. So that the original data is displayed when search is cleared. Replace all usages of mData with mFilteredData as below and only...

You can't get this to work with XSD 1.0. An "all" is not allowed as part of a choice. That's actually true in 1.1 as well. But what are you actually trying to achieve? You've got a choice with only one branch, which is obviously redundant, except that it specifies...

BaseX has integration for TagSoup, which will convert HTML to well-formed XHTML. Most distributions of BaseX already bundle TagSoup, if you installed BaseX from a Linux repository, you might need to add it manually (for example, on Debian and Ubuntu it's called libtagsoup-java). Further details for different installation options are...

There are several things wrong here. (Asking questions on selecting a library is against the rules here, so I'm ignoring that part of the question). You need to pass in a file handle, not a file name. That is: y = BeautifulSoup(open(x)) You need to tell BeautifulSoup that it's dealing...