Question!!!!!

heres the question

A rock is thrown vertically from the ground with a velocity of 24 meters per second and it reaches a height of 2+24t-4.9t(Squared) after t seconds. How many seconds after the rock is thrown will it reach maximum height and what is the maximum height the rock will reach in meters? how many seonds after the rock is thrown will it hit the ground? Round your answers to the nearest hundredth

First thing is I don't agree that this is thrown from the ground. At t=0, the position is 2. So I guess we can call 2 meters the origin. The rock will reach its max height at the vertex of this parabola. Have you taken Calculus?

A rock is thrown vertically from the ground with a velocity of 24 m/sec
and it reaches a height of after t seconds.

(a) How many seconds after the rock is thrown will it reach maximum height?
(b)What is the maximum height the rock will reach in meters?
(c) How many seconds after the rock is thrown will it hit the ground?
Round your answers to the nearest hundredth.

The function is a quadratic (second degree).. . Its graph is a down-opening parabola.. . The maximum height occurs at the vertex of the parabola.
The formula for the vertex of a parabola is:

Our parabola has:
The vertex is at:

(a) Therefore, the rock reaches maximum height at seconds.

If , then:

(b) Therefore, the maximum height is: m.

If the rock hits the ground, its height is zero.. . Solve the quadratic: