Was there no tax before 1913 in the United States? Choose from: Unicode character set (UTF-16), default Multi-Byte character set (UTF-8) Not Set Calling functions that accept strings in the Unicode setting requires you to make Unicode string literals: "hello" Is Is it unethical to poorly translate an exam from Dutch to English and then present it to the English speaking students? When you run the code, the output (from cout or printf) seems to show that x doesn't change in the second assignment. my review here

We recommend upgrading to the latest Safari, Google Chrome, or Firefox. Because the compiler does not know the calling convention of the struct until it finishes reading the entire struct, the calling convention for the struct in the return type of get_c2 Change your code to: DetermineElapsedTime(&tm, &tm2); The & operator in this context means "get the address of" share|improve this answer answered Nov 12 '12 at 6:36 sampson-chen 22.5k44859 add a comment| Forum Today's Posts FAQ Calendar Forum Actions Mark Forums Read Quick Links View Forum Leaders What's New?

Cannot Convert 'this' Pointer From 'const Type' To 'type &'

However, you pointed out that ContainsPoint is not declared const. Therefore, the real solution is to change the design of the Line class so that methods like ContainsPoint are declared const, and only methods which clearly change the state of an Since a Person inherently has nothing to do with console I/O, one shouldn't tie the class to it. Similarly, the function pointer, which returns the struct, is defined after the struct definition so that the compiler knows that the struct uses the C++ calling convention.To resolve C2440 that occurs

What are 'hacker fares' at a flight search-engine? C++ does not supply a standard conversion from a const type to a type that is not const. int foo(const char* argv[]) { return 0; } int main(int argc, char* argv[]) { foo(argv); return 0; } Error: cannot convert parameter 1 from char** to const char** I tried using Const Method This restricts how you can use this variable.

What am i doing wrong here? A lot of these inconsistencies exist because older C and C++ code would break if the standard were strictly consistent. Browse other questions tagged c++ or ask your own question. I got it after I saw the first comment thanks –user1781382 Nov 12 '12 at 6:38 add a comment| up vote 1 down vote Your function DetermineElapsedTime expects pointers to MyTime.

A Constant Variable? Const_cast Example However, I'd like to know the difference between the above code and the following (which did compile): int goo(const int x) { return 0; } int main(int argc, char* argv[]) { You can fix it in a couple of ways: change the function to expect a const reference: int DetermineElapsedTime(const MyTime &t1, const MyTime &t2) take the address of the variables that Just to make a note, if you have a method which is conceptually constant, but still needs to change some private state, consider using the mutable keyword.

Cannot Convert This Pointer From Const To &

For example, try to put the address of x, which is const, into a normal int* so you can use it to modify the data: const int x; // x cannot http://www.possibility.com/Cpp/const.html Doesn't really matter for small programs just something to know. Cannot Convert 'this' Pointer From 'const Type' To 'type &' Just do int foo; A 32 pointer pointing to an int that is a member variable is worthless. C++ Const Int To Int There is a design problem with this code, however.

The compiler always converts to array to a pointer. this page Not the answer you're looking for? What if you want to print out the name in a Windows or X-Windows application? This would be a safer, cleaner more "C++" way. Cannot Convert From Pointer To Reference C++

In James Coplien's book, Advanced C++ Programming Styles & Idioms, I came across the following code (p. 400): char *const a = "example 1"; // a const pointer to (he claims) Error: Cannot convert char* to char.This comes up so many times and I am unable to find it why it's happening.Please find a simple code for your reference which gives the more hot questions question feed lang-cpp about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation get redirected here And I bet you didn't even notice that we forgot to delete the dynamic memory for szTheName!

Burn that book. Const Function Another way to write functionally equivalent code is to use the const_cast operator to remove the const-ness from the const int*. Like I said, the string is a const char * and the assignment is invalid, hence result in the error you see.

The C++ standard (section lex.string) states: 1 A string literal is a sequence of characters (as defined in _lex.ccon_) surrounded by double quotes, optionally beginning with the letter L, as in

Whether or not the literal strings you point to are explicitly declared const, you shouldn't try to modify them, because the standard states that they are in fact const. This is obviously a bad thing john Jul 22 '05 #3 P: n/a Brad Moore I want to thank everyone who responded. Thanks for the help Sirisian Sorry, just another quick Question to add. Const Correctness Separate each with a space.

Hopefully this article will help put you on the path of eternal bliss. Is there any known limit for how many dice RPG players are comfortable adding up? I love this little library. useful reference Has swap space a file system?

This is true. I knew fully well this was a pointer, just put the dot operator out of habit of using C# so frequently. But since it's a const member function, you can't store the cached result inside the class, because to do so, you'd have to modify a member variable (thereby violating const). If the variable is an int, & returns an int*.

In fact (and your example show this), users of Line would expect ContainsPoint to be a const method.