There is no way to send information FTL if that's what you're wondering. Any interaction with a particle in an entangled states tends to break the entanglement, but even then there is no possible way for the two particles to exchange information, so you can't use them for communication. You can however do some very cool things like secure signaling, teleportation, dense coding and stuff, but nothing that violates relativity in any way.

There is no way to send information FTL if that's what you're wondering. Any interaction with a particle in an entangled states tends to break the entanglement, but even then there is no possible way for the two particles to exchange information, so you can't use them for communication. You can however do some very cool things like secure signaling, teleportation, dense coding and stuff, but nothing that violates relativity in any way.

Hold on a sec, why is interaction with a particle that is entangled, breaks the entanglement?

When you just look at one particle in an entangled pair (Bell state), it appears to be in something called a maximally mixed state, which means it has a 50/50 chance of being found spin up or down along ANY axis. But a measurement projects it into a pure state, and in a pure state you can always find an axis along which the probabilities are 1 and 0 or 0 and 1 for spin up/down. So after a measurement, the particle can no longer be in a mixed state, so the entanglement is broken.

A mixed state is used to describe a system whose state is not completely determined. A mixed state is described by a positive semidefinite self-adjoint operator [tex]\hat{R}[/tex] with [tex]\text{Tr} \hat{R}=1[/tex], the Statistical operator of the system.

A pure state is a particular case of this more general situation. [tex]\hat{R}[/tex] describes a pure state if it is a projection operator with [tex]\hat{R}^2=\hat{R}[/tex]. Then there exists a normalized state ket [tex]|\psi \rangle[/tex] such that [tex]\hat{R}=|\psi \rangle \langle \psi |[/tex].