Question

Average volume of NaOH required to titrate 10.00mL of vinegar
solution = 22.34mL

Molarity of NaOH = 0.3795 M NaOH

Molarity of HC2H3O2 = 0.8412 M HC2H3O2

Weight % of Acetic Acid in vinegar = 5% acetic acid

1. Calculate the average number of moles of NaOH used in the
titration Lab

2. Calculate or determine (giving reasoning) the number of moles
of acetic acid in the 10.0 mL sample of vinegar

3. Calculate the molarity of the acetic acid in the vinegar
solution

4. Calculate the % error. Compare your results in #3 with the
molarity of acetic vinegar as provided by the manufactor

5. Calculate the weight % of the acetic acid in the vinegar. How
does this compare with the % listed on the label? Calculate your
%error (for this calculation assume that the density of vinegar is
1.03g/mL)

I will give the points to whoever explains step by step how to
do these questions