On a single-zero table if I bet on Low, Even and Red I can cover all numbers on the board except 0, 29, 31, 33 and 35What bets should I place on each of those 3 even chance sections so that I always end up with 1 unit profit should the ball land on any of those 32 numbers - or if that's not possible then what is the optimal bet that results in the greatest chance of profit vs. loss?For example, if I bet (Low = 3), (Even = 1), (Red = 1) I win 3-5 units of profit if it lands on 14,16,18, but lose 3 units of profit if I land on 19-28. I also get 3 units of profit on most of the low numbers and 1 unit of profit on most of the mid-section numbers. I lose 1 unit on 11,30,32,34,36. How can I modify those 3 bets so that I always get a profit??Any help would be much appreciated! I tried to figure out 3 simultaneous equations/inequalities if one chip is 10, but there's not enough information to come up with the optimal answers plus my Maths is very rusty:10 * 2 - x - y > 0x * 2 - 10 - y > 0y * 2 - 10 - x > 0Any other ideas on covering most of the board using only outside bets?

My favorite way for covering 30 numbers is 3 units on Low (1-18) and 2 units on third dozen (25-36).If Low hits, you win 1 unit, if third dozen hits you win 1 unit, if the other 7 numbers hit you lose 5 units.I have also a nice progression for this bet selection, which I will explain in the future.

That's great, kav! I saw that potential, but kept breaking even when I tried to bet on them, so couldn't even figure out the ratio was 3:2. Much obliged - kav's proved it's possible - first example I've seen of the board being mostly covered using outside bets only!

Falker there is no methode that can produce one unit profit per spin. The HE can not beaten. On the long run the scienticists will predict a loss between 1.35% and 2.7% FR of the total input. Only a strategy can beat the HE.All systemdesigners are looking for the HG of the roulette.

Kav, I appreciate this forum and all the great discussion, insight and sharing of ideas. Did you ever share your progression for this bet selection? I've had success in using a Tier et Tout progression, but I know TeT is better for a 2 to 1 bet like red or black. If you've posted your progression somewhere else on the forum I've missed it. Thanks.

Hi dgate and welcome to the forum.Nope I haven't found the time to explain the progression in detail.Roughly I would suggest a negative progression of the specific sector that doesn't hit. Say after 50 spins, Low has hit 20 times and 3rd dozen only 10 times and in total we are in LOSS. Then the betting would be something like 5 units on LOW and 5 units on 3rd dozen. So if the 7 losing numbers come you lose 10 units, if Low comes you are even and if 3rd dozen comes you win 5 units. That's very roughly the idea.

Thanks, Kav. Your suggestion of a negative progression of the specific sector that doesn't hit gives me something to work on. I'll post my experience after I try it. I look forward to hearing more when you have the time.

Someone,not me,suggested that if someone bets Black and Even or Red and Odd on the same time,it will produce small but consistent profit.Also he claimed that 60 to 70 % of the times he is on par level (no profit,neither loss)

He continues to explain that this happens because there are more Red-Odd and Black-Even numbers.As an addition to the profits,said that finding a roulette table with "en prison" or "le partage" rule will be beneficial.

A final word,if those 2 bet combinations periodically being increased (bet amounts) would help to receive more comps (free dinners,accommodation,entertainment...etc) if you are a member of your local casino.

if someone bets Black and Even or Red and Odd on the same time,it will produce small but consistent profit.

If such a bet selection would produce consistent profits, then the HG would be in front of our eyes.IMO there is no bet selection capable of producing consistent profits without the help of money management.

But there are 2 casinos online which are offering no zero roulette.Bet Voyager and BetfairIf you apply the same betting but instead of betting 3 chips on the zero,to bet 3 chips on the 19,you would get a net profit of 1 unit per spin?? is this correct??

The total input is 143 units per spin. The best and simplist way to analyze this problem is to compute the result for a true sample of 37 spins. The payout for this sample 36x144=5184 units. The input is 143x37 =5291 units. You lose 5291-5184=107 units.The loss percentage is 107x52.91= 2.022%. This is the HE for this system. The bet is a mixed bet of an EC and other chancesFor a mixed bet the HE is between 1,35% and 2,7% .

Number 19 is the cause of the loss. In another thread BlueAngel aske "what is better?". Read my commentary on this question

The result of a random sample of this system depends on the occurence of number 19. If number 19 falls more than the statistic expectation you will lose alot

Real,Maybe you have found a way to win. Maybe not.In any case being that dogmatic, doesn't show you like someone who studies roulette, but someone who has been told a recipe and narrow-mindlessly follows it. If you don't want to explain your method that's ok. Just be open-minded and patient when other people try to find their own way to beat roulette. Please stop making us look stupid. We are not.