Simple Band-pass Filter - passband voltage drop

First, a quick thanks in advance. I am looking to have my process verified - I used the example numbers from the book to guide myself. I'm doing homework involving band-pass filters and I'm not confident I understand the voltage drop across a pass-band filter. I'm working with RC high pass and low pass filters in series, not sallen-key filters.

I edited the original post to reflect the proper frequencies. I had mistakenly noted (through poor notation) that the low pass filter cut off frequencies above 106.1kHz and the high pass cut off frequencies below 994.72kHz. It works the other way around.

You ask for comment, but I think it would be more fruitful if you asked a question.

Are you questioning the apparent discrepancy between the book's analysis giving an Av of .9, versus your value of .874?

Perhaps they are just rounding the result to one digit.

However, your value of .874 is only correct if there is a unity gain buffer between the stages. That's the implicit assumption you make when you simply multiply the Av of stage 1 times the Av of stage 2.

If the stages are cascaded without a buffer, the overall Av is .87205. You have to analyze the complete cascade of 4 components, all at once.

This value is pretty close to .874, and the impedances of the two stages are scaled in order to prevent the second stage from loading the first stage very much, but there is a small loading effect, which accounts for the correct Av of .87205 compared to your value of .874.