116.if a person moves 15km straight and turns 45km right and moves 15km straight then how much distance he needs to walk to reach starting point?

Take the co-ordinate of the point where he starts as (0,0)
From the sum we get the co-ordinate of the point after he has walked 15km second time as (45,30)
Distance = sqrt(45*45 + 30*30)
= sqrt(2925)
which is approx 54

If a person moves 15km straight and turns 45 km right and moves 15Km staright then how much distance he

needs to walk to reach starting point??

First refer to the 3rd diagram in the link:
http://writer.zoho.com/public/suchandra/ques
The red lines shows the path the person took. Now we can easily construct a right angled triangle as shown in the fig.By Pythagoras rule, its root of(45^2+30^2)= 54.08

assuming last 15km straight to be in similar direction with respect to the the initial straight direction.
thus he is totally 15+15=30 km away in the same direction from his initial point.
this makes the view of a triangle of base=45,edge1=30 then edge2=?
now edge2^2=edge1^2+base^2=30^2+45^2=sqrt(2925)

lets assign co-ordinates .so its starting from say(0,0). then going to the point(0,15).then to the right ay(45,15). then again straight to(45, 30). now find the distance of the points (0,0) and (45,30).its coming 54.08 km.

(#M40001056) TCS Question Keep an EYE

if a person moves 15km straight and turns 45 km right and moves 15km straight again,then how much distance does he need to walk to reach the starting point?

Solution

straight=15km,and right turn =45+15=60,
distance to the starting point = square root (15^2 + 60^2)=square root (3825)=61.85
this answer is given by KALPANA G and is the correct answer
Here it is to be informed that straight doesn't show any particular direction