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int(h(x),x=d..b)=(b-d)/6*[h(a)+h(b)+4*h(d/2+b/2)]
h(x+y)=h(x)+h(y) // since Homer can only do one thing at a time
int(h(x),x=d..b)=(b-d)/6*[h(d)+h(b)+4*h(d/2)+4*h(b/2)]
h(x/2)=h(x)/2 // half of something gives half the satisfaction
int(h(x),x=d..b)=(b-d)/6*[3*h(d)+5*h(b)]
int(h(x),x=d..b)=1/2*(b-d)*[h(d)+h(b)]

We assume h(x)=const*x | how much Homer likes something is a constant of his general liking of things * the individual value of the thing
int(h(x),x=d..b)=const/2*(b^2-d^2)
1/2*(b-d)*[h(d)+h(b)]=1/2*(b-d)*(conts*d+const*b)=const/2*(b^2-d^2)

Also, since Homer is neither a happy nor a sad fellow, we can assume const=1;
Therefore h(x)=x

... for some reason, I think the version with the Simpson heads, doughnuts, and beer mugs is easier to read. Probably this is because they're silly and colorful.

--
Furry cows moo and decompress.

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Hello my fellow math geeks. My name is Mike and I am the creator
of Spiked Math Comics, a math comic dedicated to humor, educate
and entertain the geek in you. Beware though, there might be some
math involved :D