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I figured out the solution for my own question since I had no response.

Y=X^2
X = { -1, 0, 1} and P[x=1]= 1/3 ; P[x=2]= 1/3 P[x=3]= 1/3
because all of them have the same probability and when you add them all , they are equal to one
P[x=1] = P[x=2] = P[x=3], so 3P[x=i] =1 , ► P[x=i]=1/3
Cov(x,y) = E(XY) - E(X)E(Y)