How will overshooting the end point of an acid-base titration by adding too much base to KHP affect the calculated molarity of the base?
I would think you would need to add more KHP, then more base to bring it to the endpoint. So the molarity calculated should be the same.
Is that correct?

So you did steps 1 and 2 right but on 3 added too much L NaOH. That's in the denominator, too big number means too small M.

Answer this Question

First Name:

School Subject:

Answer:

Related Questions

chemistry - If the stockroom fails to dry the KHP to remove the waters of ...
chemistry - If the stockroom fails to dry the KHP to remove the waters of ...
chemistry - If the stockroom fails to dry the KHP to remove the waters of ...
chemistry - In standardizing a potassium hydroxide solution, a student finds ...
Chemistry(Please help, thank you!) - For a chemistry lab the experiment was to ...
Chemistry - A student titrated 1.852 g of a mixture containing potassium ...
Chemistry - 1.Describe the apparent relationship between H30+ and OH- ...
Chemistry - A Student Performing a lab weighed a 1.0993g sample, containing an ...
Chemistry - For a chemistry lab the experiment was to carry out an acid-base ...
Chemistry - For a chemistry lab the experiment was to carry out an acid-base ...