(v) Number of occurrence of a number less than 7 i.e. 1, 2, 3, 4, 5 and 6 = 73 + 70 + 74 + 75 + 80 + 78 = 450Probability of the occurrence of ‘a number < 7’

Number of favorable outcomesP(E) = Total number of possible outcome

= 450/450
= 1

(vi) Number of occurrence of a number greater than 6 = 0, Because when a die is thrown all the 6 outcomes are 1, 2, 3, 4, 5 and 6 so, there is no number greater than 6.Probability of the occurrence of ‘a number > 6’