Re: math

subject to the above constraints. Let us then rewrite the above inequalities in terms of and one of and , say .

The 1st and 2nd inequalities give

, the 1st and 3rd inequalities give , and the 2nd and 3rd inequalities give . The minimum appears to be 855  however would imply , which does not satisfy the 2nd inequality. So we must instead have . Thus the minimum cost is $870 dollars for 10 of Platter A and 60 of Platter B.