Can you factor these for me? Please show all steps!?

x2-x-6=0 (The 2 is an exponent)
x2+5x+4=0 (The 2 is an exponent)
x2-4x-5=0 (The 2 is an exponent, they're all going to be that way so you get the point)
x2+x-12=0
x2-3x-10=0
x2+7x+12=0
x2+2x-15=0
x2-9x+14=0
x2-7x-18=0
x2+4x-45=0
x2+9x+18=0
x2-8x+15=0
x2+6x+5=0
I might ask... show more x2-x-6=0 (The 2 is an exponent)

x2+5x+4=0 (The 2 is an exponent)

x2-4x-5=0 (The 2 is an exponent, they're all going to be that way so you get the point)

x2+x-12=0

x2-3x-10=0

x2+7x+12=0

x2+2x-15=0

x2-9x+14=0

x2-7x-18=0

x2+4x-45=0

x2+9x+18=0

x2-8x+15=0

x2+6x+5=0

I might ask questions about them so be prepared! ;)

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For problems starting with x², look at the last sign. If it is positive, find factors of the constant (the last number) that add to the middle number. If the last sign is negative, find
factors of the constant (the last number) that subtract to the middle number.

you employ what's widespread because of the fact the quadratic equation. The quadratic equation is as follows: ax^2 + bx + c = (-b +/- sqrt(b^2 - 4ac))/(2a) so to your occasion you may replace into the equation (a million)x^2 + (9)x + (14) = (-(9) +/- sqrt((9)^2 - 4(a million)(14))) / (2(a million)) The +/- area potential that one answer makes use of the + sign and the different makes use of the - sign. The sqrt potential the sq. root of it. i'm going to easily artwork with the fabulous element so which you will discover the roots (-9 +/- sqrt(eighty one - fifty six)) / (2) (-9 +/- sqrt(25)) / (2) (-9 +/- 5) / (2) Now you have 2 roots to the equation, the 1st makes use of the + image and the 2d makes use of the - image: First, (-9 + 5) / (2) = -4 / 2 = -2 2d, (-9 - 5) / (2) = -14 / 2 = -7 the top of the factoring technique makes use of the traditional sort: (x - first root)(x - 2d root) So to your occasion it would be: (x - (-2))(x - (-7)) (x+2)(x+7) So, (x+2)(x+7) is the respond. in case you circulate by the stairs and you get a damaging huge form interior the sq. root sign, this might advise something called a complicated huge form. in case you have no longer found out approximately that yet, attempt redoing the maths and spot in case you made a mistake. i'm hoping this helps.

These are basic and simple trinomial factoring problems. You should be able to do these. If you really can't do any of these, then you must go to your teacher. Obviously, the concept of using your text book is not in your repertoire !

You will have to pass tests on this material. I suggest you learn it !