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A bullet is fired horizontally at 300 m/s from a height of 2 m. How far does it go before it hits the ground ?

Answers

The equation for freefall is vf^2 = vi^2 + 2adno initial velocity, remove it from the equation vf^2 = 2adsqrt both sidesvf = sqrt(2ad)plug in the variablesvf = sqrt(2(9.81)(2))vf = sqrt(39.24)vf = 6.26 m/sdivide v or vf by acceleration to find time it takes to accelerate to that since a= v/t, rearrange by multiplying both sides by t to get at = v, then divide both sides by a to get t = v/a6.26 / 9.81 = .64 secondsit takes .64 seconds for the bullet to reach the groundmultiply horizontal velocity by time to find distance because v = d/t, multiply t on both sides to get vt = d300 x .64 = 192 meters

to better help you find understand this, ignore the 300 m/s because the y velocity (up and down frm gravity) is unaffected by x velocity (horizontal velocity)

but the answer is still 192 meters?

yes because the x velocity stops after it touches the ground

It might have helped Naomi somewhat more if you had taken the extra effort to DEFINE your vf, vi, a, d, and t . I know it would have made it a lot easier for ME to follow, and I've been doing this stuff for 50 years.