Andrew McCutchen and Garrett Jones, hitting third and fourth respectively in the Pirates order, both had five hits Friday as part of a 10-6 win over the Cubs.
Both also homered, with Jones delivering a tie-breaking three-run shot in the eighth and McCutchen adding a solo blast in the ninth. Jones ended up driving in five runs, while McCutchen scored five times.
It’s the first time in 40 years that two Pirates have had five hits in the same game. On Aug. 1, 1970, Bob Robertson and Willie Stargell both had five hits in a 20-10 win over the Braves.
McCutchen became just the fifth Pirate in the expansion era to score five runs in game, joining Stargell (in the aforementioned contest), Rennie Stennett (in his famous 7-for-7 game), Bobby Bonillla and Brian Giles.
The last time teammates had five hits in a game was last April 15, when Ian Kinsler went 6-for-6 and Marlon Byrd went 5-for-6 in the Rangers’ 19-6 win over the Orioles.

If two Yankees had done this, it would be on SportsCenter constantly for two days and there would be a minimum of 50 comments here.
There’s a certain irony in the Pirates getting their week’s quota of hits in one game from two guys.

I was watching that game on TV, and those two were absolutely amazing!
The Pirates entered the game with a winning percentage of .412. My question is, has there EVER, in the history of baseball, been a time when two teammates, hitting back-to-back, for a team with that low of a win percentage, gotten 5 hits each in a 9 inning game?