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On a z day outdoor adventure expedition, 4 children consumed food cost
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03 Jan 2018, 20:18

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Difficulty:

45% (medium)

Question Stats:

67%(02:14) correct 33%(01:46) wrong based on 17 sessions

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On a z day outdoor adventure expedition, 4 children consumed food costing x dollars and supplies costing t dollars. For the same food and supply costs per child per day, what would be the total cost of food and supplies consumed by 8 children during a 10 day outdoor adventure?

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03 Jan 2018, 22:21

can be solved directly by using unitary method but giving detail method as below

Cost of z days for 4 children = x+t Cost per day per children = (x+t)/(4z) (we will divide as per day, per child cost will decrease)cost of 8 children for 10 days =( (x+t)/(4Z))* 8 *10= 20(x+t)/z (we will multiply as 10 day, 8 child cost will increase)

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03 Jan 2018, 22:38

A is the answer as per my understanding. This is how I solvedZ days, 4 Children, Total Food Cost(FC) X, Supply cost(SC) T = X+TFor 8 children total cost will be 2(X+T)Now total cost for 8 Children per day will be 2(X+T)/ZSo for 10 days will be 10*2(X+T)/Z = 20(X+t)/Z