Pseudocode to find whether number is Armstrong Number or Not

We first take input from user and store it in variable n. Then we initialize 2 variables temp to n and sum to 0. We calculate the cube of last digit by this expression [(n%10)*(n%10)*(n%10)] and add it to value of sum and also divide n by 10. We repeat the above step until n is greater than or equal to 0. At last, we check whether sum is equal to temp, if yes Print "Number is Armstrong Number" else print "Number is Not Armstrong Number".