the field of a serias motor has a restince of 0.6 ohms and is connect to the diverter resitor(parallel) which has three steps 5 ohms 4 ohms and 2 ohms, assuming that the current is fixed at 28 amps what is the current at each step of the diverter

The answers should be a)25 b)24.4 c)21.6

how do i get the answers, what are the equations used, hepthis has been driving me nuts for days.[?]

but i'm supposed to get the amperage passing through each resitor in the parrel circuit (5,4,2 ohm restior) to the answers a)25a b)24.4a c)21.6 and whatever do it does'nt work out.where am i going wrong. ?is it a typo in my question book, help ?[xx(],

A diverter resistor is a variable resistor I think (you should be able to tell by the fact it has settings with different resistances chris!). I remember doing this last year !!! I wish we were doing this here instead of stupid Work (mutters) but anyway, I don't really remember much since it was like a whole year ago (lol) I would try and answer but I don't ever remember a question with the electricity producer (is that what a series motor is?) having resistance ... anyway, maybe you could work out the voltage with V = IR in the motor since you know its ampage there, then with the known voltage and known resistances you can work out the current. so, v = 28 x 0.6 = 16.8 = I x 5 I = 3.36 well that's not even near 25 so I guess that's not the way to do it, shouldn't have tried, lol.

The Naked Scientists® and Naked Science® are registered trademarks.
Information presented on this website is the opinion of the individual contributors
and does not reflect the general views of the administrators, editors, moderators,
sponsors, Cambridge University or the public at large.