Essential University Physics: Volume 1 (3rd Edition)

by
Wolfson, Richard

Published by
Pearson

ISBN 10:
0321993721

ISBN 13:
978-0-32199-372-4

Chapter 4 - Exercises and Problems - Page 68: 44

Answer

Please see the work below.

Work Step by Step

(a) We know that
$a=\frac{v}{\Delta t}$
Hence, the force is given as
$F=ma=\frac{mv}{\Delta t}$
(b) We know that the acceleration is given as
$a=\frac{v^2}{2\Delta x}$
Hence, the force is given as
$F=ma=\frac{mv^2}{2\Delta x}$