TKey is the type returned by the key selectors; notice that in order to compare the equality of each key selected, they need to be of the same type. The error message refers to type arguments and the Select method because the select clause is translated into a call to a Select method which in this case is a generic asked 4 years ago viewed 3254 times active 2 years ago Upcoming Events 2016 Community Moderator Election ends Nov 22 Linked 4 LINQ: How to do JOIN using the linq extension The datatype may be the same but the names used in both are different. http://avgrunden.com/the-type/the-type-arguments-for-cannot-be-inferred.php

thank you. But I'm unable to convert the integer value to a nullable integer as both the columns have the name of varSlotId. Let's work to help developers, not make them feel stupid. Can't update using query that uses a join?0C# Linq Joining queries0Linq query using join1Linq query - Join 2 tables4Linq join query error1Getting wrong output with linq join query Hot Network Questions

The Type Arguments Cannot Be Inferred From The Usage Linq Join

Professor Lewin: "Which string will break?" / Me: "That one." / Professor Lewin: "Wrong!" Does Intel sell CPUs in ribbons? In case 4, when we bind the lambda with type Foo we get one error: test.cs(10,29): error CS1061: ‘Foo' does not contain a definition for ‘BarM' andno extension method ‘BarM' accepting The root of the problem lies in producing good error messages for lambdas even though the lambda may beboundseveral different ways through type inference. Lets change the story a little bit: Two programmers are hopelessly behind on an important software project.

Maybethe error messages are crypticbecause it is a tool written by programmers for programmers or possibly becausethe push to have more language features or better optimizations outweighs the demand for quality But how can we let them shine through? You’ll be auto redirected in 1 second. We are still working on getting the error messages right and would love to have your feedback on other problems that you notice.

Try specifying the type arguments explicitly1Linq To Entites error: The entity or complex type … cannot be constructed in a LINQ to Entities query2How do I build up a LINQ => Any help would be greatly appreciated, thanks! In case 3, when we bind the lambda with type Foo we get one error: test.cs(9,18): error CS1061: ‘Foo' does not contain a definition for ‘BazM' andno extension method ‘BazM' accepting http://stackoverflow.com/questions/13094677/the-type-arguments-cannot-be-inferred-from-the-query Re-implementation of assumed '' cannot implement '' because there is no matching on interface '' '' accessor of '' is obsolete (Visual Basic Error) '' accessor of '' is

Limit computation technology in a futuristic society Can I sell a stock immediately Polyglot Anagrams Cops' Thread Can a president win the electoral college and lose the popular vote What is It will use the normal definition of the Equals method for your object type (or if you specified a custom one in your class definition), or there is another Join extension The next two method parameters take delegates or lambda expressions that select the key value from each collection participating in the join, outer collection key selector first and then the inner Whatever the reason is, compilers tend not to be very helpful in providing good error messages.

The Type Arguments Cannot Be Inferred From The Usage Linq Select

Additional Info While reading the MSDN article on the LINQ Join method, I thought the "Remarks" section has some really great stuff about deferred execution, default equality comparison, differences from SelectMany, Your two anonymous types aren't the same, and they need to be. The Type Arguments Cannot Be Inferred From The Usage Linq Join Their condition is aggravated by the fact that they are having trouble learning to usethe new query feature in C# 3.0. The Type Arguments For Method Cannot Be Inferred From The Usage Linq Join In case 3, the lambda has an error whether x is bound having type Foo or type Bar so case 3 is an error.

Join them; it only takes a minute: Sign up LINQ Lamba Join Error - cannot be inferred from the usage up vote 14 down vote favorite 5 I had troubles joining this page How do you enchant items with Lapis Luzuli? more hot questions question feed default about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation Is there an actual army in 1984? Cannot Be Inferred From The Usage Try Specifying The Type Arguments

LINQ Query Using OR Condition in JOIN Clause How to insert statement in an inner join How to create left join query using Linq to sql Linq Query using Case statement

How does Gandalf end up on the roof of Isengard?

In both of the example queries above the intersection set is not empty and so it can be reported.

I dont really understand what this error message means.

One of them says to the other, "He must have been a professor." The other says, "Why do you say that?" The first responds, "Because what he said was totally correct

more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Ask a question Quick access Forums home Browse forums users FAQ Search related threads Remove From My Forums Answered by: The type arguments cannot be inferred from the query... It appears the "on store.Id equals wishlist.storeId" syntax is not a commutative operation.

The query represented by this method is not executed until the object is enumerated either by calling its GetEnumerator method directly or by using foreach in Visual C# or For Each

Notice the outerKeySelector needs to come before the innerKeySelector. Thanks, I hope this proves helpful to someone, as it was certainly eye-opening to me. TResult is the type returned by the projection Func resultSelector; in our case, we returned an anonymous type consisting of three properties (PersonName, StoreName, and NumItems). Treat my content as plain text, not as HTML Preview 0 … Existing Members Sign in to your account ...or Join us Download, Vote, Comment, Publish.

I keep getting an error Error 3 ‘int' does not contain a definition for ‘Text' and no extension method ‘Text' accepting a first argument of type ‘int' could be found (are After trying all the error messages, if the intersection set is not empty then we report only the error messages from that set. Fixing the Problem We can solve this by introducing two sets of error messages: the union of error messages and the intersection of error messages. http://avgrunden.com/the-type/the-type-arguments-cannot-be-inferred-from-the-usage-mvc.php Twitter: http://twitter.com/jgeurts Github: http://github.com/jgeurts Meta Log in Entries RSS Comments RSS WordPress.org Proudly powered by WordPress

Not the answer you're looking for? It was to be a simple method, that just returning a property of the objects with a separator character between each. How do I make an alien technology feel alien? Optional Password I have read and agree to the Terms of Service and Privacy Policy Please subscribe me to the CodeProject newsletters Submit your solution!

EF will handle the join and populate the child collection using the navigation property (in this case imo_no) So your entity should have a property that is defined: public class Position The problem is that no types can be inferred for the arguments such that the body does not have errors and hence we get the type inference errors. In our example, TKey is likely int or long (or maybe Guid) since we’re dealing with Id properties of all of our objects. First statement of this 'Sub New' must be an explicit call to 'MyBase.New' or 'MyClass.New' because the '' in the base class '' of '' is marked obsolete: '' First statement

Symmetric group action on Young Tableaux How do I make an alien technology feel alien? Which probably will only serve to evoke a scratch of the head and an indefinite, "Hmm…". As a monk, can I use Deflect Missiles to protect my ally? In case 2, we can use the same logic to show that x must have type Bar.