In other words, this:
c = (6 + 2i - 1 + 3i) / 3i;
Is so many levels better than:
c = (complex!(double)(6,2) + complex!(double)(-1,3)) / complex!(double)(0,3);
That there can't even be any sort of contest between them. The first is simply, inarguably, better. Or, at least, that's what it says. I tend to agree.
-[Unknown]
> http://digitalmars.com/d/builtin.html> > at the bottom: "? It's no contest"