Someone wrote to me with questions about work vs pseudowork (extended system vs point-particle system). At one point he asked me to analyze a subsystem of an accelerating car, the car minus the wheels, and I learned something in the process that’s worth sharing. It’s yet another example of the need to be careful about the fact that in calculating work it’s critically important to pay close attention to the individual displacements of the points of applications of each force, not simply use the displacement of the center of mass.

A car moves with constant acceleration in the direction, with no tire slippage. Simple model: there’s a forward static friction force applied by the road to the bottom of each tire, where the instantaneous speed is zero, and therefore this force does no work on the bottom of the wheel. Total mass of car is , mass of each wheel is , each wheel is like a bicycle wheel, with all mass at the rim of radius so the moment of inertia of the wheel is . From the Momentum Principle we have . No work is done on the car, so , where , where is the translational kinetic energy of the car and includes kinetic energy of wheels, pistons, camshaft, chemical energy of gasoline, thermal energy of engine block, etc. For a point-particle system subjected to the same forces, , where is the distance the car moves, and this is also the translational kinetic energy of the actual car.

Now consider a system I’ll call “sys” consisting of the car minus the wheels, with mass . In this simple model, suppose the engine pushes on the top of each wheel. When I was a kid there were little electric motors you could mount on the top of the front wheel of a bike. The motor turned a small wheel in contact with the big wheel, to drive the big wheel. Or you could imagine an arm or arms continually pushing the top of the wheel, then being lifted and retracted. What are the energetics of “sys”?

Start by analyzing the wheel alone, which is acted upon by the force of the road, the force of the car axle on the inside of the hub of the wheel, and the force of the engine along the top of the wheel. By determining these forces we get by reciprocity of electric forces the forces the wheel exerts on “sys”. In the direction the engine exerts a force and the axle exerts a force (the engine force pushes the hub of the wheel against the car’s axle). Remember that , so .

Momentum Principle:

Angular Momentum Principle ( direction): , or , and

From the Momentum Principle we have , so , which is twice as large as (which is a bit surprising)

Summary for wheel: The wheel is acted upon by the road, in the direction, the axle, in the direction, and the engine, in the direction. The engine force is only slightly larger than , by the amount which is small compared to , since the wheel mass is very small compared to the large mass of the car. It’s interesting that the force of the axle on the wheel is so large, twice as big as . Of course if the mass of the wheel is distributed differently the values of and will be different, related to not being simply .

Now we can look at “sys”, the system consisting of the car minus the wheels, with mass . The forces in the direction acting on “sys” are the forces due to the hubs of the wheels, , and the forces due to the tops of the wheels on the engine, .

Momentum Principle: , which checks.

What about the Energy Principle for “sys”? Here’s the element in the analysis that I found particularly interesting. The forces of the hubs of the wheels are applied to the axle, which in a small time moves through a small displacement , where is the instantaneous speed of the car. But the forces of the tops of the wheels on the engine act through a distance ! The instantaneous speed of the top of the wheel is (speed of hub is , speed of bottom of wheel is zero).

Energy Principle:

As usual, real work must be calculated by integrating EACH force through ITS point of application, THEN you add up all the contributions to the total net work. Here, as in all cases of deformation or rotation, there is the possibility that different forces act through different distances. The case here is particular striking, because the force at the top of the wheel acts through twice the distance of the force at the hub.

It may at first glance seem odd that the work done by the wheels on “sys” is negative. However, note that “sys” increases the wheels’ translational and rotational motions, thereby increasing the energy of the wheels, so there must be a small decrease in the energy of “sys” associated with giving energy to the wheels. There is of course a much larger decrease in chemical energy associated with accelerating the mass of the “sys” system.

Compare with car: , so , which is negative, with

The energy of one wheel is

The rate of energy change is , and for 4 wheels we have . In a time the amount of work done on the wheels is , which is indeed what we found above.

4 Responses to Work and energy for an accelerating car

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