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#math trivia #133 solution

#math trivia for #May12: #133 has the form xyz where xyz is one more than a multiple of yz (133 = 4*33+1). Which other day-numbers do?

Answer: If xyz is one more than a multiple of yz, then x00 = xyz = yz is also one more than a multiple of yz. This means that yz must be a divisor of 99, 199, or 299. We should therefore look at one- and two-digit divisors of these three numbers, which are: