Two Trees are 150 m apart. From a point halfway between them, the angle of

elevation of their tops is 15°and..? 15°, and 20°.
a)How much taller is one tree than the other?
b) Where would a person have to stand in order to have the angle of elevation to the top of each tree the same?

Anyway, looking at the diagram, let the small tree's height be h, and the tall tree's height be H.

h/75 = tan 15°
h = 20.096

H/75 = tan 20°
H = 27.297

So, at what distance x from the smaller tree do they both have the same angle of elevation? At that point the tangent of both angles will be the same:

20.096/x = 27.297/(150-x)
x = 63.6

So, standing 63.6m from the shorter tree, the tops of both trees will have the same angle of elevation, 17.54°

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