NCERT Solutions for Class 7th Science Chapter 13 : Motion and Time

Page No: 156

Exercises

1. Classify the following as motion along a straight line, circular or oscillatory motion:
(i) Motion of your hands while running.
(ii) Motion of a horse pulling a cart on a straight road.
(iii) Motion of a child in a merry-go-round.
(iv) Motion of a child on a see-saw.
(v) Motion of the hammer of an electric bell.
(vi) Motion of a train on a straight bridge.

Answer

(i) Oscillatory motion

(ii)Straight line motion

(iii)Circular motion

(iv) Oscillatory motion

(v)Oscillatory motion

(vi) Straight line motion

2. Which of the following are not correct?
(i) The basic unit of time is second.
(ii) Every object moves with a constant speed.
(iii) Distances between two cities are measured in kilometres.
(iv) The time period of a given pendulum is not constant.
(v) The speed of a train is expressed in m/h.

Answer

(i) Correct

(ii) Not correct

Every object may or may not moves with a constant speed.

(iii) Correct

(iv) Not correct

Time period of a given pendulum is always constant because it depends on the length of the pendulum..

5. The odometer of a car reads 57321.0 km when the clock shows the time 08:30 AM. What is the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.

Speed of the car = Total distance covered/Total time taken = 15.0/20 = 0.75 km/min

Speed of the car in km/hr =15/(1/3) = 45 km/hr
6. Salma takes 15 minutes from her house to reach her school on a bicycle. If the bicycle has a speed of
2 m/s, calculate the distance between her house and the school.

11. Suppose the two photographs, shown in Fig. 13.1 and Fig. 13.2, had been taken at an interval of 10 seconds. If a distance of 100 metres is shown by 1 cm in these photographs, calculate the speed of the blue car.

Answer

First, measure the distance with the help of scale and then proceed as given below.
Suppose the distance measured by scale is 2cm.
Multiply 2 with 100 to get the actual distance = 2 × 100 = 200 m. (1cm = 100m)
Interval time between the photos taken = 10 s.
Speed of the blue car = 200/10 m/s = 20 m/s

12. Fig. 13.15 shows the distance-time graph for the motion of two vehicles A and B. Which one of them is moving faster?

Answer

Vehicle A is moving faster because it has more slope than vehicle B. In distance-time graph, speed is measured by its slope.

13. Which of the following distance-time graphs shows a truck moving with speed which is not constant?

Answer

Option (iii) because the slope of the graph is not a straight line and hence it does not show a uniform motion.

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