1 Suggested Answer

Hi,
a 6ya expert can help you resolve that issue over the phone in a minute or two.
best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.
the service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).
click here to download the app (for users in the US for now) and get all the help you need.goodluck!

Tell us some more! Your answer needs to include more details to help people.You can't post answers that contain an email address.Please enter a valid email address.The email address entered is already associated to an account.Login to postPlease use English characters only.

To identify (calculate) b, you must make use of the fact that the parallel line passes through the point (1,5).

That means that the coordinates of the point (1,5) satisfy the equation of the parallel line y=(-1/3)x+b

Substitute 5 for y, and 1 for x and solve for b.

And that is as far I will go. I leave it to you finish up the work : find b and write the equation in the functional form, then convert it to the general form (Ax+By+C=0) if that is what you are asked to produce.

This calculator is unable to factor a polynomial expression. In general there are a few factoring methods

Factor by grouping terms

Factor by completing the square (quadratic polynomial)

Factor by finding two integers such their sum is equal to the coefficient of the middle term, and their product is equal to the third (constant term). This is valid for a quadratic polynomial where the leading coefficient (of the x^2 term) is equal to 1. X^2+SX+P

A cubic equation can be solved algebraically, although two solutions may be complex. Use the Cardano formulas. A quartic equation can be solved by the formulas for the quadratic equation, if you transform the quartic equation to look like A(X^2)^2 + B(X^2) +C=0

Hi,In the Y= equation editor you can enter two functions, and graph them both or calculate a table for both. However, the two functions will be evaluated at the same values of X.

Rather than trying to guess what is happening, I will show you how to get your two tables.

If you have used one the applications Inequalz or Transform it si probably still stuck in memory, and you must unload it from the RAM before recovering the usual calculator behavio(u)r

Press the [APPS] button, find Inequalz or Transform, point to it and click [ENTER].

You will be asked to Continue or Quit the application.

Press the number corresponding to Quit (usually 2).

Press [2nd][Y=] (STAT PLOT). Press [4:PlotsOff][ENTER]

Calculator replies Done.

Open the [Y=] equation editor. Type in your equations. Press [ENTER] at the end of each equation. Verify that the [=] signs after Y1, and Y2 remain highlighted when cursor is moved away from them.Press [2nd][GRAPH] (Table) to see your 2 tables y1 and y2 calculated at the same X.

This is simple... Back up all RAM, (press second+, then 2, then 1, press enter to back up something if backed up it will have a star by it) Then clear your RAM (pull out your batteries while the calc is still on or press second+, then 7, then 1) Hope this helps!

The first solution will allow you to watch your
calculator graph two equations simultaneously rather than finishing one
before graphing the next; it won't solve the problem of having the
calculator unselect one equation when you select a second. To fix
that problem, try the following:

In order to select additional graphs, the Transformation Graphing App
will need to be uninstalled from the TI-83 Plus Family and TI-84 Plus
Family. Uninstalling the App does not erase it from the calculator, it
disables it from interfering with the normal graphing modes. Below are
the steps to successfully uninstall the App.

Use the Conics graphing: The general equation of a circle is aX^2 + aY^2 + bX+cY+d=0

Use the function graphing. But before you can do that you must transform the general equation (above) in such a way that you can write it as Y^2= X^2+EX+F. From this you can find the two branches Y1=SQRT(X^2+EX+F) and Y2=-SQRT(X^2+EX+F)