3 Answers
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Another way to look at this is to solve for what weight/area you are allowed to use. Assume a spherical craft. Surface area goes up in proportion to r^2. Volume (which will generate your lift) is proportional to r^3. If you do the math, you find that you are allowed to use (r x 0.4)kg/m^2, or about (r x 0.88) lbs/m^2. So the problem gets easier to solve as the craft gets bigger.

The force experienced by a totally evacuated body at sea level, would be about 14.7 psi, which is about 11.4 ~TONS~ per m^2. (Don't you just love mixing metric and English units? I do...)

At r = 1m, you can only use 0.88 lbs of material for skin and structure to hold back that massive force (good luck with that).

At r = 10m, you get 8.8 lbs/m^2. That equates to a (1/17) inch thick aluminum skin and no internal supporting structure. ---> Still a no-go.

At r = 100m, you are allowed 88 lbs/m^2. ... O.K., now we are talking. 1/8 inch aluminum plate weighs about 19lb./m^2. That leaves 69 lbs./m^2 for ridigization of the skin panels and internal structure. Something that approximated a monocoque structure (like an egg shell: able to take tremendous pressure with no deep internal bracing) might work. As an engineer, I'd be willing to take on that challenge; but... that is a H-U-G-E craft! OVER two football field lengths in diameter, and weighing in at about 5 million kg before evacuation!

Maybe someone would be able to do it for r = 50m, which would be a budget of 44lbs./m^3. My guess is that technical feasibility lies somewhere in the design area of 50m < r < 100m.

Since air weighs about 1.2 kilograms per cubic meter, if you could make your Magdeburg hemispheres strong enough and they enclosed one cubic meter and weighed less than 1.2 kilograms, they ought to float like a helium balloon