Great, I'm working so in between patients I've come up with, 2.31g KOH(90%) will neutralize 1 ml H2SO4(99%). Does that sound about right, so 190ml H2SO4(99%), 438.9 g of KOH(90%) is ulitized, 1911.1 g KOH(90%) left for base rxn. Trying to use this to tweek my numbers, less soap. Thanks again Keelec

fuelfarmer-are you neutralizing acid after AE? if so ,after AE do a simple titration the titration amount in gr KOH or NaOH will neutralize the acid since the acid is part of the total acid number for the oil . Tom

I guess my question is... in trying to determine how successful the AE process was, how does one determine how much of the final titration is due to the acid that was added versus the remaining FFA?

So for example, if I started with 76L of oil that titrates at 20ml NaOH solution (roughly 15%FFA), then added a total of 183ml of 99% sulfuric and 10% methanol. If my final titration comes in at 8ml NaOH solution. How much of that 8ml solution is simply being used to neutralize the acid (and hence, what amount is due to remaining FFA)?

If the titration solution is 1g/L NaOH, .0036g * 1000ml/g = 3.6ml of the titration is due to the sulfuric, meaning... 8ml titration - 3.6ml to neutralize acid = 4.4ml to neutralize the FFA, meaning my final resulting FFA is around 3-3.5% FFA

(again assuming 100% purity and assuming the sample of oil to the titrated is actually 1.1ml due to added methanol.

neutralizing the drainage ONLY the acid remaining in the oil will be neutralized immeadiatly once the methoxide is introduced. an acid and a base can not co exist in the same container at the same time. Tom

My goal is to understand how much of the titration after AE is due to the added acid.

I understand that both the added acid and the remain FFA will be nuetralized by the base stage, and that the titration after AE determines the total base required to neutralize both, but my question has more to do with understanding how successful (or not) the AE stage actually was in converting FFA.

for draining from an AE stage?I just dump this mix of methanol/water/acid into my glycerin storage for methanol recover. then I don't worry about the acid..lots of excess KOH/NaOH in the glycerin. This get converted into water and a salt.

for the change in titration caused by the acid alone..that's easy..but solved in a different manner.take neutral ph water add 1ml of acid..how many mils are needed to neutralize or bring the ph back to neutral..for KOH(90%) its about 2mls( using a 1% KOH solution).

I probably should have started a new thread, as I am not looking to neutralize the acid.Again, I was just looking for a way to determine how much of the titration after AE was due to the added acid, and how much is a result of residual FFA. This thread was kinda on that track.That's all.At this point I think I understand how the determine that.Thanks!

astrorob,no problems.you might enjoy reading the 70+page sticky at the top of the AE section. its a thread that I started to learn more about AE.lots of questions are answered. Sure it'll take some time..but if you want to learn about AE..Start there.

lil'fuelfarmer, returning to your question??has it been answered well enough?