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Mass Effect: Andromeda Won't Be A Broken Port, Says Michael Gamble

With just a week separating us from Mass Effect: Andromeda, the PC gaming community is largely worried about the version of the game they'll be playing. Michael Gamble, however, reassured that they should fret.

The release is edging closer, and those with genuine concerns and who think a week is enough to turn a port from bad to good took to Twitter to kindly ask the game's producer to not "...fuck up the PC port". Gamble replied.

Stating that the PC version is not a port and, subsequently, not fucked up, another user went on to ask Gamble a hard-hitting performance questions as to whether Nvidia's new flagship GTX 1080Ti can run the game at a stable 60fps in 4K and the highest settings - to which Gamble creatively reacted to with "lol yes. 60+". Which is reassuring when you're looking at the £700 pricetag on a card of that caliber.

We can gather the worried came from the game's system requirements and performance expectations that surfaced from EA just last week that suggested those with modern-day medium-level GPUs would only be able to the run the title at 1080p 30fps - or, around console level of performance that PC gamers typically aim to surpass.

Granted, Gamble's comments don't really squash those worries, but at least we have his word that the PC version isn't an afterthought. Mass Effect: Andromeda launches March 23. You can snag a cheap pre-order on GreenManGaming.

The_Tingler

Jbumi

I would've been surprised if there was a planned ending! I've always thought of the Dragon Age franchise as having the potential to tell a million different stories. They don't center on one protagonist the way the Mass Effect series did.

TheTingler

It depends on their expectations for DA4, and how much money they pour into it. I'm worried they're going to make another Inquisition when all the players just kinda want another Origins. Anthem is the biggest risk though. If that tanks, Bioware are dead. And I'm terrified it's too close to Destiny, which already exists.