Intermediate Algebra (6th Edition)

by
Martin-Gay, Elayn

Answer

$x=-3$

Work Step by Step

If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x$ and every real number $y$.
Therefore, $log_{2}\frac{1}{8}=x$ is equivalent to $2^{x}=\frac{1}{8}$.
We know that $x=-3$, because $2^{-3}=\frac{1}{2^{3}}=\frac{1}{8}$.