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ash2326

6 years ago

substitute u as x^+x
we'll get
u^2-8u+12=0
u^2-6u-2u+12=0
u(u-6)-2(u-6)=0
(u-2)(u-6)=0
u=2 or u=6
so
x^2+x=2 and x^2+x=6
x^+x-2=0
(x+2)(x-1)-=0
x=-2 and x=1
from the other equation
x^2+x-6=0
(x+3)(x-2)=0
x=-3 and
x=2
so
the solution for x=-3.-2.1 and 2