p42_033 - . 013)(4 . 7 eV) 3(8 . 62 10 5 eV / K) = 4 . 7 10...

33. The fraction f of electrons with energies greater than the Fermi energy is (approximately) given in Problem 42-32: f = 3 kT/ 2 E F where T is the temperature on the Kelvin scale, k is the Boltzmann constant, and E F is the Fermi energy. We solve for T : T = 2 fE F 3 k = 2(0

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