Q-3 If we multiply 15 by a certain number then we obtain 845 . If middle one is wrong then what would be correct answer ?

(a) 815

(b) 825

(c) 865

(d) 895

Q-4 (XX4) . (XX6) = ?

(a) 444464144

(b) 334424

(c) 3324

(d) 44433404

Q-5 600 × 9999

(a) 5999400

(b) 5954400

(c) 5964400

(d) 5964600

Q-6 If n = 2 & n + (n+2) + (n+4) will be divisible by

(a) 2

(b) 8

(c) 5

(d) 9

Answers & Explanations :

1. (B) As 72A4 + 2398 = 9642 , so when we add 4 + 8 then we got 2 in unit place of answer & 9 of second value & 4 of tenth place of value of answer & 1 as carry . Then if we add them we got 9 + 4 +1 = 14 , so clearly answer is 4

2 (B) Just multiply the unit digit each of the numbers

i.e 7 × 1× 8 × 5 = 280 , therefore unit digit is 0.

3(B) First of all we know that 3 × 6 = 18 or 6 = 18 /3

As 15 = 3 × 5 , i.e the number should be divisible by 3 or 5

Here 825 is divisible by both 3 & 5 .

4 (B) Its reason is simple because when we multiply two three digit numbers then its product will be

In 5 or 6 digit .

5(A) 600 × ( 10000 – 1 )

6000000 – 600 = 5999400

6 (A) 3n + 6 & when n = 2 value will be 12

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Numerical Aptitude

Q-1 Which number is nearest to 1500 which is exactly divisible by 13 ?

(a) 1508

(b) 1495

(c) 1509

(d) 1511

Q-2 What number should be added to 121 so that it is exactly divisible by 13 ?

(a) 7

(b) 9

(c) 8

(d) 5

Q-3 What number should be subtracted from 121 to make it exactly divisible by 13 ?

(a) 5

(b) 4

(c) 15

(d) 9

Q-4 Find the number at xx place in 365xx2 , which is exactly divisible by 3 ?

1(B ) When we divide 1500 by 13 , then remainder is 5 , so the number which are exactly divisible by 13 are 1508 , 1495, so answer is 1495 . But the main question that would arise in your mind would be that from where 1508 , 1495 comes , answer is just simple , 1500 is not completely divisible by 13 , as it leaves 5 as remainder . So in order to find the number which are completely divisible by 13 , either we have to add something or subtract something . Add difference between 13 & 5 i.e 8 so it becomes 1508 . & subtract just remainder i.e 5 so number is 1495 . So nearest is 1495 .

2( B) When we divide 121 by 13 , then we got 4 as remainder therefore just subtract 13 & 4

3(B) Reason is simple, just subtract 4 from 121 because remainder is 4 .

4(a) If we take 3 , 2 , then sum of digit will be 21 which is exactly divisible by 3 .