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Consider the the equation \(Ax=B\), where \(A\) and \(B\) are given real numbers, and \(x\) is to be found.There are three possible scenarios:

1) \(A\neq0\). In this case, the given equation has a unique solution given by \(\frac{B}{A}\). Doesn't matter who is \(B\), it can be also 0, as 0 divided by a non-zero number is 0. 2) \(A = 0\) and \(B = 0\). In this case, the given equation has infinitely many solutions, as for any number \(x\), \(0 * x = 0\).3) If \(A = 0\), but \(B\neq0\), then the given equation has no solution, because \(Ax = 0 * x = 0 \neq{B}\).

I hope the above can help when discussing any linear equation with one unknown and parameters (letters instead of numbers as coefficients).
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23 Dec 2008, 14:18

I would say A because

If A, B, and C are known, then as long as C>B, A and y could only be one number. the trick is that A,B, and C are all known, if A was unknown then the answer would be infinite. For Example, 4y + 2 = 3, A=4 y=1/4 B=2 C=3, A B and C are known and C>B, so y is an easy calculation.

unless I am misinterpreting it, A is already known, so its value being more than one shouldnt matter.

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fromstatement 1 ; C>B , it doesn't make any sense , as it doesn't affect the value of y.

statement 2; A>0, this condition should exist since A can't be zero.

so, we can answer this question using statement 2.the Ans is B.

but this question asks about the different values of y.and, by using both these statement together or alone we cant say how many values does y have.hence, if we look from this perspective, the answer will be E.

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11 Jan 2012, 07:20

I agree that B give answer, but question is asking for a specific number of Y values right? with Statement 2 we can say that we can find the value of y. but here we get multiples with different values of A B and C right????