hi mach.. i followed your method, since my variables are the same, but it gives me wrong answer!! can you check PLZ...

anonymous

5 years ago

give me ur values !

anonymous

5 years ago

what is the value of your vout machu ?

anonymous

5 years ago

Write the answer for A=100, load 500 many errors when calculate this, because answer is in to within 0.1% of the exact answer

anonymous

5 years ago

I'll be more clear with
H12 P1
part c)
my values are v=5v A=100, load resistance =500
First Solve two equations to find value of vx
equation 1 : vx/R=(vOut–vx)/500,with R=answer from Part1.
equation 2: vx=5–(vOut/100)
Solving two equations we get Vx
equation 1 :vout =1.5vx
substitute the value of vout in equation 2 and u get vx
Final Answer : Current = Vx/R

anonymous

5 years ago

Thank you for H12P1 part c).
After calculate my answer is 0.00883218771969

anonymous

5 years ago

h12p2 ans plzzz

anonymous

5 years ago

m nt getng rite ans frm this equatio...plz help mee out

anonymous

5 years ago

Write your R1, v, A and load to calculate if problem in HP12P1 c).
For H12P2 first two is
a) vin*(R1+R2)/R2
b) vz*(R1+R2)/R2
for other 4 question I have too many work to calculate and do many error after 2-3 may be have time to give you answers.

Qaisersatti

5 years ago

HW12 QNo 2 Part 3 4 5 and r any help please

anonymous

5 years ago

h12p2 part c,d..help

anonymous

5 years ago

H12P2
a) vin*(R1+R2)/R2
b) vz*(R1+R2)/R2
c) 700
500
500
d) 0.15

anonymous

5 years ago

H12P1: CURRENT SOURCE
if
A=100
v=5V,
i=5mA
±VS=20V
500Ω
within 0.1% of the exact
What is ans of
c=????

anonymous

5 years ago

try 4.92/R
R = first R (a)

anonymous

5 years ago

For example, suppose that we need to put precisely i=8mA through a load that presents a resistance but the value of the resistance is not well controlled. Suppose also that we have a precision voltage source of v=5V, but this voltage source is pretty wimpy: it cannot supply more than 0.1mA without smoke coming out of it. With the circuit shown above we can choose a resistor of resistance R that can accomplish this goal.
First, assuming that the op amp is ideal (A=∞) give the value of the resistance R, in Ohms, that we need.

anonymous

5 years ago

Our specification is that we want there to be two break frequencies for this filter: 12Hz and 18kHz. We also want midband frequencies, such as signals around 1kHz, to be amplified by about a factor of 2.
We have available a 1.2μF and a 390pF capacitor. We also have a variety of resistors between 100Ω and 100kΩ. However, our op amp really likes RS=20kΩ.
Your job is to fill in the remaining details of this design.

anonymous

5 years ago

i need answers for H12p2

anonymous

5 years ago

H12P1: CURRENT SOURCE if A=100 v=5V, i=9mA ±VS=17V 500Ω within 0.1% of the exact.
I got:
a)555.555555556
b)1333.33333333
c) ???????
What is ans of c=????