Sol: According to the question the ball is yet to cover the last 6 m above the ground and the ball takes 0.2 secs to cover the distance above the last 6 meter.So we need to find the distance above the last 6 m and then add 6 to it to get the final answer.So, let the total height be `h` and the covered distance be `h-6`.As the ball is dropped freely:-Initial velocity `u` = 0Distance `x` = h-6Time `t` = 0.2 secsAcceleration `a` = `g` = 10 m/s²Now according to kinematic formula:x = ut + 1/2gt²Substituting the values:-h-6 = (0)(0.2) + (1/2)(10)(0.04)h-6 = 0.2h = 0.2 + 6h = 6.2 m Therefore, the ball was dropped from the height of 6.2m.