16. Correct. The answer is false. Let's define the following events: A:
low-quality gold ore, and B: non-precious ore. We can write the probability as
follows: P(A∩B). The problem is that in this
case both events are not independent According to Schaums'
Outline the probability of such an event is: P(A∩B) = P(B/A)*P(A) where
P(B/A) is the conditional probability
(the probability of B given that A has occurred). So, we have that: P(A) = 1/18 and P(B/A) = 12/17. Therefore
P(A∩B) = (1/18)*(12/17) = 12/306 ≈ 0.04 or 4%.