More answers

Because the idea is that as the function approaches +- infinity it approaches a certain y value.

askme12345

6 years ago

can you explain how to so that with 5/x-2

anonymous

6 years ago

I'm not sure what you're asking. Is 5 / (x-2) = f(x)?

anonymous

6 years ago

If that was the case, you would write the problem like this:
lim 5/(x-2) = x(5/x / 1 -2/x/1) = 0
x->\[\infty\]

anonymous

6 years ago

Because as x approaches infinity, the denominator gets bigger and bigger causing the y value to get smaller and smaller (when you divide a number by a larger number it makes it smaller). Therefore, it would be the same for negative infinity. So you have a horizontal asymptote at y = 0