If a natural product was isolated and was found to have an enantiomeric excess (ee) of 84% what would be the percentages of each enatiomer in the mixture?

think about it...

how many possible enantiomers are there. hint: the number of possible enantiomers is the same for any compound.

so...let's say that the enantiomers were 50:50 in a mixture. then, the excess would be 0. if it were a 40:60 mixture, then one of the enantiomers would be in 10% excess. notice that (60 - (100 - 60) ) / 2 = 10