3. The attempt at a solution
A scale is attached with wires to the circumference of the bicycle wheel and the bicycle frame. The line of the wire is at a tangent to the wheel. The measurement on the scale is: (14kg) (sin12) = 2.9kg

Another scale is attached similarly to the circumference of the cylinder, except the scale is attached to a frame mounted to the ground. The measurement of the scale is: .5 (14kg) (sin12) = 1.45kg1. The problem statement, all variables and given/known data

I'll go a little further in my interpretation to see if it sounds right.
In the bicycle there is a force, F1 = m*g*sin12, that is pulling the bicycle down the incline. The same force is pulling down the cylinder.
On the pulley there are 2 opposing forces. F2, the friction force of the ground on the cylinder and F3, the force of the ground support that is pulling the rope. Therefore F2 + F3 = F1. If this is right, I only need to find the relationship between F2 and F3 to find their values.
On the bicycle there is only 1 opposing foce, F4. Where the rope is attached to the bike frame, the rope is pulling the same direction as F1, so it does not oppose F1. Therefore F4 = F1

It's a bit difficult to follow which forces you are talking about, but if I am following them correctly your results look OK to me. For the cylinder, I am assuming the lower strap is attached to the floor, so friction is not a factor, but even if it is not attached and friction keeps it from slipping the reading on the scale would be the same. The upper and lower straps equally share the force needed to keep the bike frorm moving in order for the net torque to be zero, so F2 = F3 looks right.

For the bicycle the only force keeping the bike from moving is friction, so the magnitude of the torque at the bottom is rF1 and the magnitude at the top must be rF4 = rF1, so I agree with you that F4 = F1 and F4 is half of F2 or F3.