Thanks for your reply.
So in order for the statement to be true, it is necessary to eliminate the x^2 in the denominator right? Otherwise you would be dividing by zero. So could f(x) be 5(x^2)? This way the x^2 would divide out and 5 would be left?
Am I on the right track?

Thanks for your reply.
So in order for the statement to be true, it is necessary to eliminate the x^2 in the denominator right? Otherwise you would be dividing by zero. So could f(x) be 5(x^2)? This way the x^2 would divide out and 5 would be left?
Am I on the right track?

you figure out what f(x) must be on your own ... why then do you doubt your solutions to these two simple limits?

The textbook I have used a different method for a similar question earlier on and it looks far more complicated. So I just wasn't sure if guessing was correct. Therefore, both answers are indeed zero right?