Cart down a ramp, acceleration of 0.6m/s^2

We rolled down a cart down a ramp with a tickertape. When the average velocities were calulated and they were used to calculate acceleration. But we got acceleration of like 0.6, 0.2m/s^2 etc.... shouldn't it be 9.8m/s^2..?! When i graphed the average velocity and the line of best fit was drawn and the slope calculated i got 6.5m/s^2. Why did i get an acceleration of such numbers like 0.6?? What are some explanations to account for this acceleration?????

We rolled down a cart down a ramp with a tickertape. When the average velocities were calulated and they were used to calculate acceleration. But we got acceleration of like 0.6, 0.2m/s^2 etc.... shouldn't it be 9.8m/s^2..?! When i graphed the average velocity and the line of best fit was drawn and the slope calculated i got 6.5m/s^2. Why did i get an acceleration of such numbers like 0.6?? What are some explanations to account for this acceleration?????

We rolled down a cart down a ramp with a tickertape. When the average velocities were calulated and they were used to calculate acceleration. But we got acceleration of like 0.6, 0.2m/s^2 etc.... shouldn't it be 9.8m/s^2..?! When i graphed the average velocity and the line of best fit was drawn and the slope calculated i got 6.5m/s^2. Why did i get an acceleration of such numbers like 0.6?? What are some explanations to account for this acceleration?????

Acceleration is equal to gravity only if the object is in free-fall. If the object is rolling or sliding down an inclined plane, the acceleration is dependent on friction and the angle of the incline. Remember that acceleration down an inclined plane is independent of the mass. Hope this helps!