Solving for x

hi, I was wonderin how i would solve for X in the following equation...

[tex] 0 = 60x^2 - 90x^4 [/tex]

If i do add 90x^4 from both sides....and then go about solving for x, i get 1/x, which is the same as -x...and then i have to take the square root of a number, and i cant do that with a negative number. So.. yeah, i need help. my algebra skills are very rusty...thanks

When two quantities multiplied together equal zero that implies that one or both of them is zero.

So you have 30x^2 being multiplied to (2-3x^2).

This implies that if 30x^2 = 0 it would be a solution to your equation.

But also if 2-3x^2=0 that would also be a solution to your equation.

You can also think of it this way: You 30x^2 multiplied to some garbage, but it isn’t going to mater what that garbage is if 30x^2 = 0, likewise you also have 2-3x^2 being multiplied to some junk. Who cares what that junk is if 2-3x^2=0, because than that junk is being multiplied by zero, and anything multiplied by zero is zero.