Hi,
Here is my code so far.
$${3x^2-27 \over 4\cancel{(x+2)}} \cdot
{{{\stackrel{1}{\cancel{(x+2)}}}(x-2)} \over {3x+7}}$$
What I wan to do is show a 1 directly underneath the cancelled x+2 in
the denominator of the left hand rational factor. I have not been able
to get \underset to work in this context. Do I have to go to picture?
I'd rather not, but if I have to I will. Thank you. I guess I owe some
dues. Please let me know what they are. I am using Bluesky textures if
that is important.
--
George McCormack, Ed.D.,
Higher Education Associate
Mathematics Department, E-214
LaGuardia Community College
31-10 Thomson Avenue
Long Island City, NY 11101-3007
gmccormack at lagcc.cuny.edu
(718) 482-5733