then subtraact that new value to the -7 and divide by 7 and that should give you your x.

anonymous

5 years ago

wait so 8*2 is 16 then adding it to -15 would be 1 right
then you subtract that from -7 would be 8 and dividing it would 1.14 right? it says i have to have two decimals though so what do i do after that?

sanchez9457

5 years ago

it would be -8 not 8. so it should give you -1.14 if you did your calculuations correctly.
1.14 is two decimal places. you have the tenths and the hundredths places.

anonymous

5 years ago

no like 1.14 as one answer than there should be another answer for it

anonymous

5 years ago

I think this is supposed to be a quadratic and you're going to want to use the quadratic formula...

anonymous

5 years ago

first write it in the form ax^2 +bx +c =0
then plug the values of a b and c into the quad. formula

sanchez9457

5 years ago

I don't quite understand this then. So that is not a multiplication like you said it's 8x?

anonymous

5 years ago

it is from the lessons linear and quadratic functions

sanchez9457

5 years ago

Oh so then that is not 8 times 2 , it's 8x^2

anonymous

5 years ago

im so confused guys

sanchez9457

5 years ago

Forgetting that little carrot is a huge thing.

anonymous

5 years ago

it didnt have the carrot thingy

anonymous

5 years ago

re-write it in the form ax^2 +bx +c =0
plug the values of a b and c into the quad. formula

anonymous

5 years ago

where do i find the a b c thing

anonymous

5 years ago

a=8 b =7 c=...?

anonymous

5 years ago

or are you talking about the quadratic formula?

anonymous

5 years ago

i have no clue honestly i am so confused right now

sanchez9457

5 years ago

@Algebraic! : i'm not sure it's a quadratic equation sine he just said there was nothing squared. so the qudratic formula would render usless he made a mistake in copying the problem.

anonymous

5 years ago

it's in your book or everywhere on the internet

anonymous

5 years ago

im a girl first and second the problem is right in front of me it is right. and it is on my homework online