Quantitative Aptitude Shortcuts

Quantitative Aptitude Short cut Methods

Almost every competitive exam today is including quantitative aptitude and reasoning as the part of their entrance exam. Any one can solve aptitude problems but it takes lots of time which is not available at the time of exam. Therefore, the main concern is solve in time. If the solving method for particular problem is known , then problems can be analyzed in seconds, then you can answer the test easily. If you have such solving skills and if you know shortcut methods, then you can are good in aptitude. In aptitude for every problem or question we have short cut methods.

Short cut methods are necessary to be applied at

In bank exams like IBPS PO, IBPS Clerical , IBPS RRB etc.,\

Written test for an IT job/Software job for freshers

CAT,MAT,GRE,GATE ,railways exams,lic,all national level exams

Is Formula and Trick Same

Here you are not going to solve the problems in formula. If you hate mathematics and formulas, you can now try to solve in logical methods,which are not related to any formula. Thus, here you can find suggestions to apply tricks,which improves your logical thinking and solving

How to Learn Tricks to Solve Aptitude problems

These methods/tricks will not available in any books or any other websites,no any website providing the short cut tricks to solve the problems in less time.In this site you can learn aptitude short cut methods

IBPS EXAM SPECIAL

Learn short cut methods in aptitude to get your dream job,so for every day,apply new methods to solve the problems by using our short cut methods.Start from here,the lessons for aptitude tricks from all topics.Today we are explaining you,short cut methods in percentage topic ,which related to aptitude.

SHORT CUT METHODS/TRICKS IN PERCENTAGES

CONCEPT:

Important Points to Note:

When any value increases by
10%, it becomes 1.1 times of itself. (since 100+10 = 110% = 1.1)
20%, it becomes 1.2 times of itself.
36%, it becomes 1.36 times of itself.
4%, it becomes 1.04 times of itself.
Thus we can see the effects on the values due to various percentage increases.

When any value decreases by
10%, it becomes 0.9 times of itself. (Since 100-10 = 90% = 0.9)
20%, it becomes 0.8 times of itself
36%, it becomes 0.64 times of itself
4%, it becomes 0.96 times of itself.
Thus we can see the effects on a value due to various percentage decreases.

Note:

1. When a value is multiplied by a decimal more than 1 it will be increased and when multiplied by less than 1 it will be decreased.

2. The percentage increase or decrease depends on the decimal multiplied.

Eg: When the actual value is x, find the value when it is 30% decreased.

Soln: 30% decrease => 0.7 x.

Eg: A value after an increase of 20% became 600. What is the value?

Soln: 1.2x = 600 (since 20% increase)

ð x = 500.

Eg: If 600 is decrease by 20%, what is the new value?

Soln: new value = 0.8 X 600 = 480. (Since 20% decrease)

Thus depending on the decimal we can decide the % change and vice versa.

Eg: When a value is increased by 20%, by what percent should it be reduced to get the actual value?

Soln: (It is equivalent to 1.2 reduced to 1 and we can use % decrease formula)

% decrease = (1.2 – 1)/1.2 X 100 = 16.66%.

When a value is subjected multiple changes, the overall effect of all the changes can be obtained by multiplying all the individual factors of the changes.
Eg: The population of a town increased by 10%, 20% and then decreased by 30%. The new population is what % of the original?