Correct Answer: B

Explanation:

A switch is a layer 2 device and doesn#39;t use network layer for packet forwarding. The IP address may be used only for administrative purposes such as Telnet access or for network management purposes.

Question No.55

Refer to the exhibit. The internetwork is using subnets of the address 192.168.1.0 with a subnet mask of 255.255.255.224. The routing protocol in use is RIP version 1. Which address could be assigned to the FastEthernet interface on RouterA?

A.

192.168.1.31

B.

192.168.1.64

C.

192.168.1.127

D.

192.168.1.190

E.

192.168.1.192

Correct Answer: D

Explanation:

Subnet mask 255.255.255.224 with CIDR of /27 which results in 32 hosts per.

192.168.1.31 is the broadcast address for sunbet #39;0#39; 192.168.1.64 is the network address for subnet #39;2#39; 192.168.1.127 is the broadcast address for subnet #39;3#39; 192.168.1.192 is the network address for subnet #39;6#39;

Question No.56

Which option is a valid IPv6 address?

A. 2001:0000:130F::099a::12a

B. 2002:7654:A1AD:61:81AF:CCC1

C. FEC0:ABCD:WXYZ:0067::2A4 D. 2004:1:25A4:886F::1

Correct Answer: D

Explanation:

IPv6 Address Notation

IPv6 addresses are denoted by eight groups of hexadecimal quartets separated by colons in between them.

Following is an example of a valid IPv6 address: 2001:cdba:0000:0000:0000:0000:3257:9652

Any four-digit group of zeroes within an IPv6 address may be reduced to a single zero or altogether omitted.

Therefore, the following IPv6 addresses are similar and equally valid: 2001:cdba:0000:0000:0000:0000:3257:9652

Correct Answer: C

Explanation:

Add them up and you get 255. Add one for the all zeros option, and the total is 256. Now, take away one of these for the network address (all zeros) and another for the broadcast address (all ones). Each octet represents 254 possible hosts. Or 254 possible networks. Unless you have subnet zero set on your network gear, in which case you could conceivably have 255.

The CIDR addressing format (/20) tells us that 20 bits are used for the network portion, so the maximum number of networks are 2^20 minus one if you have subnet zero enabled, or minus 2 if not.

You asked about the number of hosts. That will be 32 minus the number of network bits, minus two. So calculate it as (2^(32-20))-2, or (2^12)-2 = 4094

Question No.60

R1 is configured with the default configuration of OSPF. From the following list of IP addresses configured on R1, which address will the OSPF process select as the router ID?

A.

192.168.0.1

B.

172.16.1.1

C.

172.16.2.1

D.

172.16.2.225

Correct Answer: A

Explanation:

The Router ID (RID) is an IP address used to identify the router and is chosen using the following sequence.

The highest IP address assigned to a loopback (logical) interface. If a loopback interface is not defined, the highest IP address of all active router#39;s physical interfaces will be chosen.

The router ID can be manually assigned

In this case, because a loopback interface is not configured so the highest active IP address 192.168.0.1 is chosen as the router ID.