Dual power supply HF coil driver

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a basic push-pull circuit.
any reason why this would not work? the inductor is around 1.0uH, plan to run oscillator in the 10k-200kHz area.

the power supply T1 can handle ~200A w/o blinking an eye, but to drive fet gates I need about 10v to get the fet to saturate.

i know some components are missing, but the center-tap has me a tad confused. i suspect T2 does not need center-tap. so how does the output on 555 look like +12v and -12v to the fet gates (what's the reference point)? i suspect my 555 pwer supply is just a +24v supply as there is nothing referencing that center-tap.

a basic push-pull circuit.
any reason why this would not work? the inductor is around 1.0uH, plan to run oscillator in the 10k-200kHz area.

the power supply T1 can handle ~200A w/o blinking an eye, but to drive fet gates I need about 10v to get the fet to saturate.

i know some components are missing, but the center-tap has me a tad confused. i suspect T2 does not need center-tap. so how does the output on 555 look like +12v and -12v to the fet gates (what's the reference point)? i suspect my 555 pwer supply is just a +24v supply as there is nothing referencing that center-tap.

I think this is what you want instead of the bridge rectifiers
That would give you a 1 volt and a 12 volt supply. You will need to regulate the 12 volt supply because the 555 is only good for 15 volts.

A 100 A power MOSFET has a very large gate capacitance. Driving the FET fast enough that it doesn't spend much time "unsaturated" can take 5 or 10 *amps* of dynamic gate current. Linear Tech et. al. make special gate drive chips for this.

At Digi-Key, a 200 A MOSFET has a gate capacitance of 12 nF. If you start with a 200 kHz frequency, that is a period of 5 us and a half-cycle period of 2.5 us. If the transistor ramps up or down for 10% of that, and stays saturated or off for the other 90%, the risetime is 250 ns. Using the linear ramp approximation:
EC=It
I = (E x C) / t = (9 V x 12 nF) / 250 ns = 0.44 A

Note that a 10% risetime might be way too slow to prevent transistor overheating.

It's very difficult to say. Please redraw the schematic with all +12V's across the top pointing up, and all GND's across the bottom, pointing down. I'm not being overly-picky here. Making the schematic show the overall energy flow will go a long way to "seeing" how the circuit functions. You are trying to show what is called and H-bridge. Hint: place the inductor horizontally in the center; it is the crossbar of the H.

you just want me to rotate the coil 90 degree and then drag connectors so that the +12v is on one side with all the GND's on the other? i can do that, but the positions of the fets will remain the same.

as is, with a "1" the current is 12v-->Q4-->L1-->Q2-->GND
with a "0" the current is 12V-->Q1-->L1-->Q3-->GND
Q5 and Q6 are just fets to flip the logic around to make it work (pFet and nFet have their challenges, etc)

you just want me to rotate the coil 90 degree and then drag connectors so that the +12v is on one side with all the GND's on the other? i can do that, but the positions of the fets will remain the same.

Semantically, I'm not comfortable with power flowing through a resistor. Electrons (not current) flow; power is dissipated. But the main reason I responded is that I misread your post and missed the word "also". oops.