Using TMP36 with AD8362 at 1 MHz

I have a design that is using the TMP36 to compensate for temperature changes of the AD8362 Log Amp. The input to the AD8362 is 1 MHz. The chart in the application note only goes down to 900 MHz when selecting the resisters shown in the application. How do I calculate the resistors for 1 MHz operation of this log amp?

You need to first figure out the native drift of the devices at 1 MHz by applying a fixed input power and cycling the device over temperature. You can go from -40 to +85 or a subset of this temperature range. Ultimately, you need to figure out the drift in mV/degC. Once you have that number, you can use the equations in AN-653 to figure out what resistor values to use.

I should note that there are now newer and better parts than AD8362 with better temperature drift. Take a look at HMC1120 for example. You will get as good if not better temperature drift from this device without any external temperature compensation.

You need to first figure out the native drift of the devices at 1 MHz by applying a fixed input power and cycling the device over temperature. You can go from -40 to +85 or a subset of this temperature range. Ultimately, you need to figure out the drift in mV/degC. Once you have that number, you can use the equations in AN-653 to figure out what resistor values to use.

I should note that there are now newer and better parts than AD8362 with better temperature drift. Take a look at HMC1120 for example. You will get as good if not better temperature drift from this device without any external temperature compensation.