(c) vertical components of the force exerted on her shoes by the ground.

I understand that the force of the horizontal is equal to the force of the wall, and the force of the vertical components is equal to the woman's weight, but I am not sure what is wrong with my equation, because F wall is incorrect.

Do you have to find the torque on the woman? Torque about which axis? Wall is smooth. Is the floor smooth too?
Could you explain the meanings of symbols you have used in the equations?
Is the woman at rest? If yes, then don't you think that the net torque is zero?

You have to calculate Fn. Right?
Take torques about the point where her feet touch the floor. Torque of force by floor = 0
Take counterclockwise as positive.
Torque by Fn = Fn * (1.10 + 0.400) * sin(60deg)
Torque by weight = - 496 * 1.10 * cos(60 deg)
Net torque = 0
How much do you get for Fn?