Let’s call the side length of the square s. This makes the perimeter of the square 4s, which we know is 144 units. Solving 4s = 144 for
s, we get s = 36. We also can say that the perimeter of each rectangle is 2(s + 0.25s). Since we found that s = 36, we know that the perimeter of
each rectangle is 2(36 + (0.25)(36)) = 90 units

Let’s call the side length of the square s. This makes the perimeter of the square 4s, which we know is 144 units. Solving 4s = 144 for
s, we get s = 36. We also can say that the perimeter of each rectangle is 2(s + 0.25s). Since we found that s = 36, we know that the perimeter of
each rectangle is 2(36 + (0.25)(36)) = 90 units