2 years ago

log[3](x-2)=log[3] 27 - log[3](x-4) -5^(log[5]1)
I have tried this out and right now all I am getting is
log[3] (x-2)(x-4)/27= -5^(log[5] 1)
Is this somewhat right so far? I'm not sure what to do with the "log[3] 27"
the answer is supposed to be- 3+sqrt(10)

okay...
to get solution of (x-2)(x-4) = 9
simplify, frist. then use quadratic formuka :
x = {-b +- sqrt(b^2-4ac)}/2a
if u got 2 solution's, that one positive and the other negative, just take that positive value, because for x negative undefined for log[3] (x-2)