1)A pocket of gas is discovered in a deep drilling operation. The gas has a temperature of 480c and is at a pressure of 12.8 atm. What volume of gas is required to provide 18.0 L of gas at the surface where the conditions are 22 C and 1.00 atm?

2)What is the volume of 45.0g of nitrogen monoxide, NO, at 20 C and a pressure of 740 mm Hg?

2) The molar mass is 16 + 12 = 28.00, so
45.0 g is n = 1.61 moles. That number of moles would occupy
22.4 x 1.61 = 36.06 liters at 1.00 atm and 273 K. At 20 C and 740 mm Hg(which corresponds to 0.974 atm), the volume has to be multiplied by (299/273)(1.000/0.973).
OR you could just use V = n R T/p, with R = 8.206*10^-2 l-atm/(mole K)