Why is it common base of 9? I don't think you can get 27 from any exponents of 9?

Dec 9th 2007, 04:52 PM

colby2152

Quote:

Originally Posted by Macleef

Why is it common base of 9? I don't think you can get 27 from any exponents of 9?

$\displaystyle 9^x9^{(2x-1)} = 9^{(3x-1)}$

That is what I was referring to. As far as 27, that is equal to 3^3

Dec 9th 2007, 04:55 PM

Macleef

Quote:

Originally Posted by colby2152

$\displaystyle 9^x9^{(2x-1)} = 9^{(3x-1)}$

That is what I was referring to. As far as 27, that is equal to 3^3

What happens to the rest of 27? I still don't know how you get a common base of 9... (I know $\displaystyle 3^{3} $ ) then wouldn't it be $\displaystyle (3)9^{x}$ instead of just $\displaystyle 9^{x}$?

Dec 9th 2007, 05:26 PM

colby2152

Quote:

Originally Posted by Macleef

What happens to the rest of 27? I still don't know how you get a common base of 9... (I know $\displaystyle 3^{3} $ ) then wouldn't it be $\displaystyle (3)9^{x}$ instead of just $\displaystyle 9^{x}$?