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For a given counter machine model the instruction set is tiny—from just one to six or seven instructions. Most models contain a few arithmetic operations and at least one conditional operation (if condition is true, then jump). Three base models, each using three instructions, are drawn from the following collection. (The abbreviations are arbitrary.)

The three counter machine base models have the same computational power since the instructions of one model can be derived from those of another. All are equivalent to the computational power of Turing machines (but only if Gödel numbers are used to encode data in the register or registers; otherwise their power is equivalent to the primitive recursive functions). Due to their unary processing style, counter machines are typically exponentially slower than comparable Turing machines.

The counter machine models go by a number of different names that may help to distinguish them by their peculiarities. In the following the instruction "JZDEC ( r )" is a compound instruction that tests to see if a register r is empty; if so then jump to instruction Iz, else if not then DECrement the contents of r:

Shepherdson-Sturgis machine, because these authors formally stated their model in an easily accessible exposition (1963). Uses instruction set (1) augmented with additional convenience instructions (JNZ is "Jump if Not Zero, used in place of JZ):

Minsky machine, because Marvin Minsky (1961) formalized the model. Usually uses instruction set (1), but instruction-execution is not default-sequential so the additional parameter 'z' appears to specify the next instruction after INC and as the alternative in JZDEC:

{ INC ( r, z ), JZDEC ( r, ztrue, zfalse) }

Program machine, Program computer, the names Minsky (1967) gave the model because, like a computer its instructions proceed sequentially unless a conditional jump is successful. Uses (usually) instruction set (1) but may be augmented similar to the Shepherson-Sturgis model. JZDEC is often split apart:

{ INC ( r ), DEC ( r ), JZ ( r, ztrue )}

Abacus machine, the name Lambek (1961) gave to his simplification of the Melzak (1961) model, and what Boolos-Burgess-Jeffrey (2002) calls it. Uses instruction set (1) but with an additional parameter z to specify the next instruction in the manner of the Minsky (1961) model;

{ INC ( r, z ), JZDEC (r, ztrue, zfalse ) }

Lambek machine, an alternative name Boolos-Burgess-Jeffrey (2002) gave to the abacus machine. Uses instruction set (1-reduced) with an additional parameter to specify the next instruction:

{ INC ( r, z ), JZDEC ( r, ztrue, zfalse ) }

Successor machine, because it uses the 'successor operation' of, and closely resembles, the Peano axioms. Used as a base for the successor RAM model. Uses instruction set (2) by e.g. Schönhage as a base for his RAM0 and RAM1 models that lead to his pointer machine SMM model, also discussed briefly in van Emde Boas (1990):

{ CLR ( r ), INC ( r ), JE ( rj, rk, z ) }

Elgot-Robinson model, used to define their RASP model (1964). This model requires one empty register at the start (e.g. [r0] =0). (They augmented the same model with indirect addressing by use of an additional register to be used as an "index" register.)

{ INC (r), CPY ( rs, rd ), JE ( rj, rk, z ) }

Other counter machines: Minsky (1967) demonstrates how to build the three base models (program/Minsky/Lambek-abacus, successor, and Elgot-Robinson) from the superset of available instructions described in the lead paragraph of this article. The Melzak (1961) model is quite different from the above because it includes 'add' and 'subtract' rather than 'increment' and 'decrement'. The proofs of Minsky (1961, 1967) that a single register will suffice for Turing equivalence requires the two instructions { MULtiply k, and DIV k } to encode and decode the Gödel number in the register that represents the computation. Minsky shows that if two or more registers are available then the simpler INC, DEC etc. are adequate (but the Gödel number is still required to demonstrate Turing equivalence; also demonstrated in Elgot-Robinson 1964).

Labeled unbounded integer-valued registers: a finite (or infinite in some models) set of registers r0 ... rn each of which can hold any single non-negative integer (0, 1, 2, ... - i.e. unbounded). The registers do their own arithmetic; there may or may not be one or more special registers e.g. "accumulator" (See Random-access machine for more on this).

A state register that stores/identifies the current instruction to be executed. This register is finite and separate from the registers above; thus the counter machine model is an example of the Harvard architecture

List of labelled, sequential instructions: A finite list of instructions I0 ... Im. The program store (instructions of the finite state machine) is not in the same physical "space" as the registers. Usually, but not always, like computer programs the instructions are listed in sequential order; unless a jump is successful, the default sequence continues in numerical order. Each of the instructions in the list is from a (very) small set, but this set does not include indirection. Historically most models drew their instructions from this set:

Some models have either further atomized some of the above into no-parameter instructions, or combined them into a single instruction such as "Decrement" preceded by conditional jump-if-zero "JZ ( r, z )" . The atomization of instructions or the inclusion of convenience instructions causes no change in conceptual power, as any program in one variant can be straightforwardly translated to the other.

Initially, register #2 contains "2". Registers #0, #1 and #3 are empty (contain "0"). Register #0 remains unchanged throughout calculations because it is used for the unconditional jump. Register #1 is a scratch pad. The program begins with instruction 1.

The program COPY ( #2, #3) has two parts. In the first part the program moves the contents of source register #2 to both scratch-pad #1 and to destination register #3; thus #1 and #3 will be copies of one another and of the original count in #2, but #2 is cleared in the process of decrementing it to zero. Unconditional jumps J (z) are done by tests of register #0, which always contains the number 0:

[#2] →#3; [#2] →#1; 0 →#2

In the second the part the program moves (returns, restores) the contents of scratch-pad #1 back to #2, clearing the scratch-pad #1 in the process:

The program, highlighted in yellow, is shown written left-to-right in the upper right.

A "run" of the program is shown below. Time runs down the page. The instructions are in yellow, the registers in blue. The program is flipped 90 degrees, with the instruction numbers (addresses) along the top, the instruction mnemonics under the addresses, and the instruction parameters under the mnemonics (one per cell):

1

2

3

4

5

6

7

8

9

10

← Instruction number (address)

JZ

DEC

INC

INC

JZ

JZ

DEC

INC

JZ

H

← Instruction

2

2

3

1

0

1

1

2

0

← Register number

6

1

10

6

← Jump-to instruction number

step

IC

Inst #

reg #

J-addr

reg0

reg1

reg2

reg3

reg4

IC

start

0

0

2

0

0

1

move [#2] to #1 and #3:

1

1

JZ

2

6

0

0

2

0

0

1→2

JZ

Jump fails: register #2 contains 2

2

2

DEC

2

0

0

0

2→1

0

0

2→3

DEC

Decrement register #2 from 2 to 1

3

3

INC

3

0

0

0

1

0→1

0

3→4

INC

Increment register #3 from 0 to 1

4

4

INC

1

0

0

0→1

1

1

0

4→5

INC

Increment register #1 from 0 to 1

5

5

JZ

0

1

0

1

1

1

0

5→1

JZ

U-Jump: register #0 is empty

6

1

JZ

2

6

0

1

1

1

0

1→2

JZ

Jump fails: register #2 contains 1

7

2

DEC

2

0

0

1

1→0

1

0

2→3

DEC

Decrement register #2 from 1 to 0

8

3

INC

3

0

0

1

0

1→2

0

3→4

INC

Increment register #3 from 1 to 2

9

4

INC

1

0

0

1→2

0

2

0

4→5

INC

Increment register #1 from 1 to 2

10

5

JZ

0

1

0

2

0

2

0

5→1

JZ

U-Jump: register #0 is empty

11

1

JZ

2

6

0

2

0

2

0

1→6

JZ

Jump !: register #2 is empty

move [1] to 2:

12

6

JZ

1

10

0

2

0

2

0

6→7

JZ

Jump fails: register #1 contains 2

13

7

DEC

1

0

0

2→1

0

2

0

7→8

DEC

Decrement register #1 from 2 to 1

14

8

INC

2

0

0

1

0→1

2

0

8→9

INC

Increment register #2 from 0 to 1

15

9

JZ

0

6

0

1

1

2

0

9→6

JZ

U-Jump: register #0 is empty

16

6

JZ

1

10

0

1

1

2

0

6→7

JZ

Jump fails: register #1 contains 1

17

7

DEC

1

0

0

1→0

1

2

0

7→8

DEC

Decrement register #1 from 1 to 0

18

8

INC

2

0

0

0

1→2

2

0

8→9

INC

Increment register #2 from 1 to 2

19

9

JZ

0

6

0

0

2

2

0

9→6

JZ

U-Jump: register #0 is empty

20

6

JZ

1

10

0

0

2

2

0

6→10

JZ

Jump !: register #1 is empty

21

10

H

0

0

0

0

2

2

0

10→10

H

HALT

The partial recursive functions: building "convenience instructions" using recursionEdit

The example above demonstrates how the first basic instructions { INC, DEC, JZ } can create three more instructions—unconditional jump J, CLR, CPY. In a sense CPY used both CLR and J plus the base set. If register #3 had had contents initially, the sum of contents of #2 and #3 would have ended up in #3. So to be fully accurate CPY program should have preceded its moves with CLR (1) and CLR (2).

However, we do see that ADD would have been possible, easily. And in fact the following is summary of how the primitive recursive functions such as ADD, MULtiply and EXPonent can come about (see Boolos-Burgess-Jeffrey (2002) p. 45-51).

In general, we can build any partial- or total- primitive recursive function that we wish, by using the same methods. Indeed, Minsky (1967), Shepherdson-Sturgis (1963) and Boolos-Burgess-Jeffrey (2002) give demonstrations of how to form the five primitive recursive function "operators" (1-5 below) from the base set (1).

The authors show that this is done easily within any of the available base sets (1, 2, or 3) (an example can be found at μ operator ). However, the reader needs to be cautioned that, even though the μ operator is easily created by the base instruction set doesn't mean that an arbitrary partial recursive function can be easily created with a base model -- Turing equivalence and partial recursive functions imply an unbounded μ operator, one that can scurry to the ends of the register chain ad infinitum searching for its goal. The problem is: registers must be called out explicily by number/name e.g. INC (47,528) and DEC (39,347) and this will exhaust the finite state machine's TABLE of instructions. No matter how "big" the finite state machine is, we can find a function that uses a "bigger" number of registers.

The problems are discussed in detail in the article Random-access machine. The problems fall into two major classes and a third "inconvenience" class:

(1) Unbounded capacities of registers versus bounded capacities of state-machine instructions: How will the machine create constants larger than the capacity of its finite state machine?

(2) Unbounded numbers of registers versus bounded numbers of state-machine instructions: How will the machine access registers with address-numbers beyond the reach/capability of its finite state machine?

(3) The fully reduced models are cumbersome:

Shepherdson and Sturgis (1963) are unapologetic about their 6-instruction set. They have made their choice based on "ease of programming... rather than economy" (p. 219 footnote 1).

Minsky (1967) expanded his 2-instruction set { INC (z), JZDEC (r, Iz) } to { CLR (r), INC (r), JZDEC (r, Iz), J (Iz) } before his proof that a "Universal Program Machine" can be built with only two registers (p. 255ff).

For every Turing machine, there is a 2CM that simulates it, given that the 2CM's input and output are properly encoded. This is proved in Minsky's book (Computation, 1967, p. 255-258), and an alternative proof is sketched below in three steps. First, a Turing machine can be simulated by a finite-state machine (FSM) equipped with two stacks. Then, two stacks can be simulated by four counters. Finally, four counters can be simulated by two counters.

A Turing machine consists of an FSM and an infinite tape, initially filled with zeros, upon which the machine can write ones and zeros. At any time, the read/write head of the machine points to one cell on the tape. This tape can be conceptually cut in half at that point. Each half of the tape can be treated as a stack, where the top is the cell nearest the read/write head, and the bottom is some distance away from the head, with all zeros on the tape beyond the bottom. Accordingly, a Turing machine can be simulated by an FSM plus two stacks. Moving the head left or right is equivalent to popping a bit from one stack and pushing it onto the other. Writing is equivalent to changing the bit before pushing it.

A stack containing zeros and ones can be simulated by two counters when the bits on the stack are thought of as representing a binary number (the topmost bit on the stack being the least significant bit). Pushing a zero onto the stack is equivalent to doubling the number. Pushing a one is equivalent to doubling and adding 1. Popping is equivalent to dividing by 2, where the remainder is the bit that was popped. Two counters can simulate this stack, in which one of the counters holds a number whose binary representation represents the bits on the stack, and the other counter is used as a scratchpad. To double the number in the first counter, the FSM can initialize the second counter to zero, then repeatedly decrement the first counter once and increment the second counter twice. This continues until the first counter reaches zero. At that point, the second counter will hold the doubled number. Halving is performed by decrementing one counter twice and increment the other once, and repeating until the first counter reaches zero. The remainder can be determined by whether it reached zero after an even or an odd number of steps, where the parity of the number of steps is encoded in the state of the FSM.

As before, one of the counters is used as scratchpad. The other holds an integer whose primefactorization is 2a3b5c7d. The exponents a, b, c, and d can be thought of as four virtual counters that are being packed (via Gödel numbering) into a single real counter. If the real counter is set to zero then incremented once, that is equivalent to setting all the virtual counters to zero. If the real counter is doubled, that is equivalent to incrementing a, and if it's halved, that's equivalent to decrementing a. By a similar procedure, it can be multiplied or divided by 3, which is equivalent to incrementing or decrementing b. Similarly, c and d can be incremented or decremented. To check if a virtual counter such as c is equal to zero, just divide the real counter by 5, see what the remainder is, then multiply by 5 and add back the remainder. That leaves the real counter unchanged. The remainder will have been nonzero if and only if c was zero.

As a result, an FSM with two counters can simulate four counters, which are in turn simulating two stacks, which are simulating a Turing machine. Therefore, an FSM plus two counters is at least as powerful as a Turing machine. A Turing machine can easily simulate an FSM with two counters, therefore the two machines have equivalent power.

The caveat: *If* its counters are initialised to N and 0, then a 2CM cannot calculate 2NEdit

This result, together with a list of other functions of N that are not calculable by a two-counter machine — when initialised with N in one counter and 0 in the other — such as N2, sqrt(N), log2(N), etc., appears in a paper by Schroeppel (1972). The result is not surprising, because the two-counter machine model was proved (by Minsky) to be universal only when the argument N is appropriately encoded (by Gödelization) to simulate a Turing machine whose initial tape contains N encoded in unary; moreover, the output of the two-counter machine will be similarly encoded. This phenomenon is typical of very small bases of computation whose universality is proved only by simulation (e.g., many Turing tarpits, the smallest-known universal Turing machines, etc.).

"Theorem: A 3CM [three-counter machine] can compute any partial recursive function of one variable. It starts with the argument [i.e. N] in a counter, and (if it halts) leaves the answer [i.e. F(N)] in a counter." (p. 3)

"Theorem: A counter machine can be simulated by a 2CM [two-counter machine], provided an obscure coding is accepted for the input and output" [p. 3; the "obscure coding" is: 2W3X5Y7Z where the simulated counters are W, X, Y, Z]

"Theorem: Any counter machine can be simulated by a 2CM, provided an obscure coding is accepted for the input and output." (p. 3)

"Corollary: A 2CM can compute any partial recursive function of one argument, provided the input is coded as 2N and the output (if the machine halts) is coded as 2answer." (p. 3)

"Theorem: There is no two counter machine that calculates 2N [if one counter is initialised to N]." (p. 11)

With regard to the second theorem that "A 3CM can compute any partial recursive function" the author challenges the reader with a "Hard Problem: Multiply two numbers using only three counters" (p. 2). The main proof involves the notion that two-counter machines cannot compute arithmetic sequences with non-linear growth rates (p. 15) i.e. "the function 2X grows more rapidly than any arithmetic progression." (p. 11).

The Friden EC-130 calculator had no adder logic as such. Its logic was highly serial, doing arithmetic by counting. Internally, decimal digits were radix-1 — for instance, a six was represented by six consecutive pulses within the time slot allocated for that digit. Each time slot carried one digit, least significant first. Carries set a flip-flop which caused one count to be added to the digit in the next time slot.

Adding was done by an up-counter, while subtracting was done by a down-counter, with a similar scheme for dealing with borrows.

The time slot scheme defined six registers of 13 decimal digits, each with a sign bit. Multiplication and division were by done basically by repeated addition and subtraction. The square root version, the EC-132, effectively subtracted consecutive odd integers, each decrement requiring two consecutive subtractions. After the first, the minuend was incremented by one before the second subtraction.

George Boolos, John P. Burgess, Richard Jeffrey (2002), Computability and Logic: Fourth Edition, Cambridge University Press, Cambridge, England. The original Boolos-Jeffrey text has been extensively revised by Burgess: more advanced than an introductory textbook. "Abacus machine" model is extensively developed in Chapter 5 Abacus Computability; it is one of three models extensively treated and compared—the Turing machine (still in Boolos' original 4-tuple form) and recursion the other two.

Marvin Minsky (1967). Computation: Finite and Infinite Machines (1st ed.). Englewood Cliffs, N. J.: Prentice-Hall, Inc. In particular see chapter 11: Models Similar to Digital Computers and chapter 14: Very Simple Bases for Computability. In the former chapter he defines "Program machines" and in the later chapter he discusses "Universal Program machines with Two Registers" and "...with one register", etc.

John C. Shepherdson and H. E. Sturgis (1961) received December 1961 Computability of Recursive Functions, Journal of the Association of Computing Machinery (JACM) 10:217-255, 1963. An extremely valuable reference paper. In their Appendix A the authors cite 4 others with reference to "Minimality of Instructions Used in 4.1: Comparison with Similar Systems".