What percentage of the total mass of the pendulum is in the uniform thin rod?

Christy has a grandfather clock with a pendulum that is 1.070 m long.
(a) If the pendulum is modeled as a simple pendulum, what would be the period?
Already solved

(b) Christy observes the actual period of the clock, and finds that it is 1.20% faster than that for a simple pendulum that is 1.070 m long. If Christy models the pendulum as two objects, a 1.070-m uniform thin rod and a point mass located 1.070 m from the axis of rotation, what percentage of the total mass of the pendulum is in the uniform thin rod?
Need help

(b) I don't have a clue about the equation that correspond to this part of the problem,no similar examples or anything in my textbook. To start a equation would be great, because I have percentages and meters and they want me to calculate total mass of a pendulum. Any help is great thank you.

The contribution to torque is due to rod and point mass and similarly for I. Plug them into above eq and use small angle theta to find alpha. You also know that, alpha = -(omega)^2 * theta => you have angular velocity omega and T = 2*pi / omega => percentage