Physics93 km/h=93000/3600=25.8 m/s Centripetal acceleration is a=v²/R=25.8²/1350 =0.49 m/s² The average acceleration = =Δv/Δt = (v₂-v₁)/Δt Since velocity is vector, vecor Δv can be found as vector difference (taking into account that ...
January 21, 2013

Physicstanα=0.55/0.4 =1.375. α=54⁰ The distance between the charges d = sqrt(0.4²+0.55²) = 0.68 m The electric field at the disired point is zero => kq₁/0.68+r)²=kq₂/r², 0.86r²-1.36r-0.46=0, r ={1.36±sqrt(1.85...
January 11, 2013