Chem 2

A mixture containing KCLO3, K2CO3, KHCO3, and KCL was heated, producing CO2, O2, and H2O (water) gases according to the following equations:

2KCLO3 -> 2KCL + O2
2KHCO3 -> K2O + H2O + 2CO2
K2CO3 -> K2O + CO2

The KCL does not reacnder the conditions of the reaction. If 100.0g of the mixture produces 1.8g of H20, 13.2g of CO2, and 4g of O2, what was the composition of the original mixture?(assume complete decomposition of the mixture)

someone please show me how to do this!
* all O's in the equations stand for oxygen, nothing means 20, its 2O, 2 then oxygen comes after.

You are given 1.226 g of a mixture of KClO3 and KCl. When heated, the KClO3 decomposes to KCl and O2, 2 KClO3 (s) → 2 KCl (s) + 3 O2 (g), and 246 mL of O2 is collected over water at 24 °C. The total pressure of the gases in the …