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anonymous

7 years ago

3x^2=8x-6
3x^2-8x+6=0
A B C
-B+/_ the sq root of B^2-4(A)(C) divided by 2(A)
Now we have +8+/_ sq root 8^2-4*3*(-6) divided by 2*3
8+/_sq rt 136/6 = 8+/_4sqrt34/3 reduced to 4+/_2sq rt34/3 and as two answers one will be \[4+2\sqrt{34}/3 and 4-2\sqrt{34}/3\]