Math Joke

So there's this party, right? A party of functions! All of the functions are there: ex, i2, even some old-school guys like abs(x). Anyway, poor ex is alone in a corner, acting all morose. His good friend 2x comes over and says, "What's the problem? Come on, integrate yourself into the party!" And ex looks at him and says, "Why? It's not going to make a difference!"

I'd like to propose the following riposte:

2x replies, "Are you kidding? C over there has had her eye on you all night long!"