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KW is the power not the amount of energy used - you need to use kw/hour if you want the amount of energy used and this relates to BTU.
As above you can only convert apples to apples.
Thus 1kw-hour is 3412.142 BTU's
or 1BTU = 0.0002930711 kw-hours
Be very careful don't try to calculate cooling loads if you aren't experienced as mistakes are costly. Get advise off an experienced data centre heating/cooling mechanical engineer or suppler
Dave Mc

"Be very careful don’t try to calculate cooling loads" -Dave
I am trying to develop a calculator that estimates the kWh saved by installing a more efficient heat pump. Is this possible? My approach is to divide the btuh capacity of the unit, by it's EER rating to determine the W or kW, then multiplying by the # of heating and cooling hours for a specific area for one year (i.e. 34300btuh/20.40EER = 1.7kW, 1.7kW*3100hrs = 5212 kWh). For a unit that has an EER rating of 9.0, my estimated kWh is 11,814kWh. By increasing the efficiency of the unit, I have prevented 11814 - 5212 = 6602 kWh from being consumed. Is this logical? Any help is much appreciated!

All of the individuals responding here are correct. I would add a caution in that the number you are generating will not be liner. It is affected by many other factors. One of the more important is Delta T. This is the difference of the cooling unit supply temperature and it's return air temperature. A resulting number of 4 to 5 degrees F is a very poor exchange of heat while a number of 20 to 25 degrees F is much better and is closer to what your cooling equipment is sized for. If the first scenario is closer to your situation then the effect your calculating will be very minor. This is also impacted by your data center computing equipment as it's delta T F can be anything from 20 Degrees Delta T F to 60 degrees Delta T F. I am not trying to confuse you, but; it should be clear that engaging someone that has a solid understanding of the impacts is probably a good Idea.

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