You have $\displaystyle 4x+12-12=12-3x-12\implies 4x+(12-12)=-3x+(12-12)$

Note that I put some terms in parenthesis to make the next step in the process easier to see. Can you continue?

switching 12 around doesnt make the answer 0
4x +12 -12 = -3x + 12 -12
= 4x = -3x
=4x +3x = -3x + 3x
=7x not 0 plus the only rule is that whatever you do to the left you have to do to the right. the right in this equation is -3x so -3x -12, which is 3x -12 ,would be -9

You have $\displaystyle 4x+12-12=12-3x-12\implies 4x+(12-12)=-3x+(12-12)$

Note that I put some terms in parenthesis to make the next step in the process easier to see. Can you continue?

Originally Posted by Leona_Marie

switching 12 around doesnt make the answer 0
4x +12 -12 = -3x + 12 -12
= 4x = -3x
=4x +3x = -3x + 3x
=7x not 0 plus the only rule is that whatever you do to the left you have to do to the right. the right in this equation is -3x so -3x -12, which is 3x -12 ,would be -9

masters , please explain to me how 7x = 0 or x = 0 the only thing I would know how to do is to devide 7x/7 0/7 = 0 ? plus Ive never seen wher you can swap + -3x + 12 or visa versa is this the case or am I missing something again. in other words the question was written out12 -3x so shouldnt the number come off the right. I think I just got it please verify.

masters , please explain to me how 7x = 0 or x = 0 the only thing I would know how to do is to devide 7x/7 0/7 = 0 ? plus Ive never seen wher you can swap + -3x + 12 or visa versa is this the case or am I missing something again. in other words the question was written out12 -3x so shouldnt the number come off the right. I think I just got it please verify.

yes 0/7 is what masters did.. which = 0 and you can always swap to other sides of the equation to collect like terms(as long as you change the sign)