Block sliding down a track

1. The problem statement, all variables and given/known data
A block of mass m=1.3 kg slides down a frictionless track, as in the attachment diagram. The block is released at height h=4m. The radius of the curvature of the track at the bottom is R=1m. What is the force of the track on the block at A?

2. Relevant equations
Fg+N=0

3. The attempt at a solution
I assumed that the track would be applying the normal force on the block, but the block does have some velocity and acceleration once it hits the bottom of the track, but I am not sure how to incorporate those.

That may be, but you're asking what happens in a point A, since I cannot see the picture I don't know exactly how the track looks like. It is doubtful that it matters though I will say it again, centripetal force!

A block of mass m=1.3 kg slides down a frictionless track, as in the attachment diagram. The block is released at height h=4m. The radius of the curvature of the track at the bottom is R=1m. What is the force of the track on the block at A?

Hi toastie!

You need to use good ol' Newton's second law in the vertical direction … F = ma …