A mixture initially consisting of 0.250 N2 (g) and 0.500 M H2 (g) reacts to form NH3 (g) which is 0.15 M NH3 (g) at equilibrium. Calculate the concentration of N2 (g) at equilibrium for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g) can someone help me find the concentration of N2? Above is everything that i...

For a reaction, when OH conc. was doubled, the rate doubled. When the CH3OH concentration alone was increased by a factor of 1.2, the rate increased by a factor of 1.2. Write the rate law for the reaction. The answer key says "rate is 1st order in both reactants." But I thought it would be...

In order to find n (the number of electrons transferred) write down both half reactions and balance them. You always want to make sure that the number of electrons being transferred is the same amount for both half reactions.

yes, I believe so. When bonds break, energy is required to break the bond so it is positive. However, when bonds are formed, energy is released that is why it is negative. So breaking a bond is endothermic while forming a bond is exothermic.

A calorimeter was calibrated with an electric heater, which supplied 22.5 kJ of energy as heat to the calorimeter and increased the temperature of the calorimeter and its water bath from 22.45 degrees C to 23.97 degrees C. What is the heat capacity of the calorimeter? What equation is used in order ...

(a) Calculate the heat that must be supplied to a 500.0-g copper kettle containing 400.0 g of water to raise its temperature from 22.0 degrees C to the boiling point of water, 100.0 degrees C. Why do we need to account for the copper kettle and not just the water in order to find the amount of heat ...

Although some bases or acids are not on the tables, you can look at their conjugate acid or base and then use the equation Ka x Kb = Kw to find the opposite. For example if you have the conjugate base Kb you would manipulate the equation in order to solve for ka and vice-versa. ka=1.00x10^-14/kb

Are we supposed to know how the equilibrium equation looks off the top of our heads when given a solution. For example, in the 6th edition book, problem number 12.69 asks to find the ph for the solution .19 M NH4Cl only. And we obviously need the equilibrium equation to set up the ice table. For hom...

I don't have the 7th edition book but the 6th edition has a similar problem that only gave the initial concentration. What I did was first find ka using the equation ka x kb= kw. Once you find ka you can use the ice table to solve for x. Once you find your x you can plug that into -log(x) which equa...

I believe you use Q when you are not sure whether or not the reaction is at equilibrium. Or when K is given and you calculate the ratio and it is a different value than K, therefore you would be using Q.