2012 – What comes after 2012?

I have earlier suggested that 2027 may replace 2012 as the new ”end point” or ”point of transformation”. Why? Because this is the year when the Aztec Calendar Round comes to an end the next time (it repeats every 52nd year). Aztec cosmology is far more adequate for those people who want to think in terms of cycles, destruction and world ages (like most 2012ers). The Aztec Sun Stone is also the most frequently used image to (falsely) represent 2012. It would not be hard work for most 2012ers to just switch from the Maya Long Count to the Aztec Calendar Round (maybe for the galactic alignment dude).

I read on Bast’s 2012 forum about Ray Kurzweil who claims that we will reach a technological singularity sometime between 2026 and 2040 (or 2045 according to the Youtube clip that I provide below). Well, the Aztecs may already have given us the answer.

Since Michio Kaku also weighs in on the topic (like he often does), I am sure this must be fact checked. Maybe there is a conspiracy here? Why would Kaku otherwise debunk 2012? Does he know something about the upcoming Aztec 2027 singularity that we should not know…?

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By: split cob on September 26, 2012 at 13:17

Actually the next calendar round completion will occur on Thursday March 11, 2032 – 13.0.19.9.0 4Ahau 8Kumk’u. The last one occurred on Monday March 24, 1980 – 12.18.6.14.0 4Ahau 8Kumk’u.

By: Tlalocantecutli on October 10, 2012 at 16:57

Nope, you are using the Maya Calendar round, not the Aztec. The correct date (I think it is after making some calculations), is October 2, 2027. For the Aztecs, the Calendar Round ends in the year 2 Reed (Acatl). 5 Nemontemi (the Aztec version of 5 Wayeb) is the last day of the year and the next time we have 5 Nemontemi in the year 2 Acatl is October 2, 2027. Less than 15 years before the world ends in movement (Ollin)…

Yes, that’s Maya. A calendar round completion occurs every 18980 days on a combination of a certain Tzolkin (Mexican Tonalpohualli) and Haab’ (Mexican xiuhpohualli). A year bearer is the Tzolk’in day that coincides with the first day of the Haab’ year . 2 Reed is a year bearer not a calendar round. There are four known year bearer systems, the classic, Campeche, Oxcutzcab and Mayapan, none of them will produce a year bearer of 2 Reed, although the Campeche is close. This is because the system was altered by the Aztecs shortly before the conquest so the completion wouldn’t occur on a date that had been unlucky for them in the past. It’s a lot easier to program your computer to do these calculations than use your calculator over and over again. Yack, yack, woof, woof, whatever…

By: Tlalocantecutli on October 10, 2012 at 19:31

I expressed myself poorly. I meant that the next time we have 2 Reed (which repeats every 52nd year) will happen in 2027.

Yes the same year bearer (actually the year bearer is just the Tzolk’in day but the same one with the same coefficient) will happen again every 52 Haab’ years but this is not a calendar round completion.

By: Tlalocantecutli on October 10, 2012 at 20:42

Is there any known calendar round completion for the Aztecs like the one you mention for the Classic period Maya? And did the Classic period Maya celebrate the calendar round completion on 4 Ajaw 8 Kumk’u (is there any evidence for that or is this based on its importance in the Long Count)? I wonder since 13 Ajaw is the favored tzolkin date in the highlands today.

I’m not an expert on the Aztec calendar, but for the most part it is the same as the one used by the Maya. Yes the other cultures in Mesoamerica celebrated the calendar round completion on 4 Ahau 8 Kumku. It would be interesting to read up on this. As bad as Wikipedia can be, the articles about the Maya calendar, Long Count, Aztec calendar and Mesoamerican calendars are surprisingly good. One interesting discovery by the Tedlocks is that the Maya in Guatemala are using the GMT correlation as I recall also the classic year bearer system but I would have to check this.