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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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08 Dec 2019, 03:03

Rahim bought 100 kg potato from market & 99% of its are water so he dried it whole night to make it 98% water. In the morning How many kilogram of potato left to him?A) 25B) 40C) 50D) 65E) 80

Initially, we have 99 Kg of water in 100 Kg of potato and 1 Kg of potato by weight. Let w = the amount of water that evaporates, and we can create the equation:(99 - w)/(100 - w) = 98/100100(99 - w) = 98(100 - w)9900 - 100w = 9800 - 98w100 = 2w50 = wAs 50 Kg of water evaporated, new weight of the potatoes will be 100 - 50 = 50 Kg.

Since there is no change in the potato pulp quantity,Therefore initial quantity of pulp = final quantity of pulpOr, 2% potato pulp = 1 kg potato pulpOr, 100% potato pulp = 50 kg potato pulp.Therefore, he is left with 50 kg of potatoes.

Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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09 Dec 2019, 05:08

100kg potatoes will have 99kg water & 1kg potatoes

When Rahim dried the potatoes, only the water quantity was reduced by evaporation but the original quantity of potatoes stayed the same.

Let x be the amount of water evaporated. From 99kg water, if x kg is evaporated, the remaining amount of water will be (99-x)kg. Also, the total weight is reduced by x i.e. (100-x)

(99-x)/(100-x) = 98/100

The above equation says the remaining amount of water, upon the remaining amount of the original quantity is 98%

Solving it we get x = 50.

Since the amount evaporated is 50kg, the remaining weight is 50kg of which 49kg is water and 1kg is potatoes.

Kindly note that this could easily be a trick question on GMAT. Co-incidentally x=50 and the final answer is also 100-x = 50. If the original quantity was something different, say 120, and the equations solved to give x=50, the amount remaining would be 100-50=70. In the haste, a lot of people would mark 50. Remember to check the question being asked and answer that question.