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Unformatted text preview: i).
(iv). Is there a 1 in every pivot position?
Matrix (d) fails this test, so it is only in echelon form. Finally, ask:
Does each leading 1 have all zeros above it (and below it)?
Matrices (a) and (b) pass all four tests, so they are in reduced echelon form. 3. This final matrix is in reduced echelon form and the pivot positions are circled. Original matrix: The pivot columns are 1 and 3. 7.
The associated system of equations for the last matrix is: So the general solution is 11. The associated system of equations for the last matrix is: So the general solution is 13. The ass...
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