I can get the first term, however, in the last term I get a factor of $ \quad - \frac{1}{2} \quad$ out the front, i.e.
$$ \mathcal{L}~=~\det(e)\bar{\Psi}\Bigg (\frac{i}{2}\gamma^{a}\stackrel{\leftrightarrow}{\partial_{a}}-m-\frac{1}{2}B_{a}\gamma^{a}\gamma^{5}\Bigg)\Psi $$
I've tried deriving it in several different ways and always end up with the above expression. The problem is, in all of the papers that I've read on the subject, it is given in the form as presented at the top of this page.
If it helps, here is a link to my derivation in full: http://we.tl/mUgiw0BkMh