For the titration of 25.00 mL of 0.150 M HCl with 0.250 M NaoH, calculate (a) the initial pH; (b) the pH when neutralization is 50% complete; (c) the pH when neutralization is 100% complete; and (d) the pH when 1.00 mL of NaOH is added beyond the equivalence point.

Here is what you need to do. Determine what you have in solution at each of the four points. To do that, determine moles HCl initially, moles NaOH added, subtract to see which is in excess and go from there. Post your work if you get stuck.