More answers

anonymous

7 years ago

@AnwarA: How'd you get that answer, if I may ask?

anonymous

7 years ago

From what I've gathered, we can see that the point of intersection is at (theta)=π/4. Then we can get one integral of 1/2 * sin^2(theta) from 0 to π/4, added to an integral of 1/2 * cos^2(theta) from π/4 to π/2. Wouldn't that be enough to account for both halves of the petal-like enclosed shape?

anonymous

7 years ago

Alright, so we've gotten exactly the same answers...xD But can you show me how they're the same? I haven't done polar curves yet and I'm curious.

anonymous

7 years ago

well you're integrating twice over the same region sinx from 0 to pi/4

anonymous

7 years ago

the same area*

anonymous

7 years ago

that's why I multiplied the integral by 2.. make sense?

anonymous

7 years ago

Yep, I see now. Thanks. :)

anonymous

7 years ago

no problem :)

anonymous

7 years ago

you haven't done polar curves? you still in high school?

anonymous

7 years ago

or maybe a freshman?

anonymous

7 years ago

I'm a junior in AP Calc, polar curves is what we're doing immediately after we finish sequences & series. I skipped pre-calc, so now I'm pretty much going through the rest of the syllabus on my own to cover anything I missed.

anonymous

7 years ago

I see. wish you the best!

anonymous

7 years ago

how did you find the point of intersection?

anonymous

7 years ago

Plot the two polar curves (or set the two equations equal to each other) and based on simple trigonometry, the angle at which they both equal each other is π/4. I think you'll see exactly what I mean when you graph it though.

anonymous

7 years ago

alright thank you, it makes sense. btw im review sequences and series right now for my calculus exam can you reccemend a video or website which covers the section well?
thank you

anonymous

7 years ago

Here you have links of tons of different types of convergence tests, basic concepts; basically anything you could want to see about these. :) No problem,
http://tutorial.math.lamar.edu/Classes/CalcII/SeriesIntro.aspx