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Re:Help with Algebra??

I don&#039;t know how to do that. That was not easy it is very hard. I did not understand anything on your last post. I have to tell you something that i never told you before. I&#039;m a slow learner and i have a learning disability. How did i make it through algebra 1, 2 years ago it beats me.

Re:Help with Algebra??

Re:Help with Algebra??

Yo hold up. I got something better. Do you use yahoo messenger?? There is something called doodle it&#039;s and IMVironment where you could draw out your problems and answers. I use yahoo. I know i&#039;m going to need a tutor when it comes down to Analytic Geometry &amp; Calculus 1, 2 and 3. Also Linear algebra. Please reply back. Thanks.

-edit-
And in the end you&#039;ll end up with solving the roots of a second degree equation, like 0=ax²+bx+c
Which either can have only one solution, two solutions or no solution at all.
The way to find these is by using the formular:
-b +- sqrt(b²-4ac)
x = ------------------------
2a
If (b²-4ac) gives a negative value, it has no solution, atleast not within the number group R, but if we use Z, then it has.

Re:Help with Algebra??

I think the Z domain is a tad out of scope for the project at hand, but true it&#039;s an awesome tool.

But you are of course correct about that root solving thing, I&#039;m guessing I&#039;m chalk this up to picking a bad example, it was maybe a tad to advanced (even for me it seems - I glad stumbled into the common trap, forgetting prior knowledge)