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excel master series-Chi square-variance-test-in-excel

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How To Find Out If Your Customers Are Becoming More or Less Predictable In Their Spending With the Chi-Square Variance Test in Excel http:// blog.excelmasterseries.com /

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What Is the Chi-Square Variance Test? ● The Chi-Square Variance Test Determines Whether the Variance of a Population Has Changed ● Marketers Use the Chi-Square Variance Test To Find Out If the Range of Customer Spending Has Changed, Indicating That Something Has Affected the Customers’ Buying Habits. http:// blog.excelmasterseries.com /

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The 5 Steps of the Chi-Square Variance Test in Excel 1) Determine the Required Level of Certainty and Alpha 2) Take a Large (>30), Representative, Random Sample and Measure Its Standard Deviation 3) Calculate the Chi-Square Statistic 4) Calculate the Curve Area Outside the Chi-Square Statistic 5) Analyze Using the Chi-Square Statistic Rule

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Curve Area Outside Chi-Square Statistic in Outer Left Tail in Red Is Larger Than the 5% Yellow Alpha Region

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5) Analyze With the Chi-Square Statistic Rule The Population Standard Deviation ( σ ) Has Moved In The Direction of the Sample Standard Deviation (s) If The Curve Area Outside the Chi-Square Statistic (the Red Area) is Smaller Than Alpha Region (the Yellow Area) In Other Words If the Red Region Fits Inside the Yellow Region, the Population Standard Deviation ( σ ) Has Moved, Otherwise σ Hasn’t Moved.

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Population Standard Deviation Has Shifted to Right (Increased) Because Curve Area Outside Chi-Square Statistic in Red in Outer Right Tail Is Smaller Than the Yellow 5% Alpha Region

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Population Standard Deviation Has NOT Shifted to the Left (Decreased) Because Curve Area Outside Chi-Square Statistic in Outer Left Tail in Red Is Larger Than the 5% Yellow Alpha Region

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The Test We Ran An Internet marketing manager wanted to determine if the number of items purchased on individual orders had become more spread out (order size standard deviation had increased). She took a representative, random sample of 50 recent orders and measured the sample’s standard deviation in the number of items purchased per order to be 1.9 (n = 50 and s = 1.9). The standard deviation in number of items purchased per order had remained at 1.6 for a long time ( σ = 1.6). The Internet marketing manager wanted to determine within 95% certainty whether the population order size standard deviation had increased (Alpha = 1 – 95% = 0.05).