Nassim Haramein's theory of the proton having a discrete mass of8.9x10^11kg is interesting because it exhibits some aspects of theSchwarzschil/Compton opposites phenomena I have recently been mailingabout. The main difference being that the opposite of the proton hasa diameter equal to the proton's Compton wavelength of 1.32141x10^-15mmaking its mass 4.45039x10^11kg not 8.9x10^11kg. Therefore, its radiusis half the wavelength and its Gm product 29.6906036. The theory seemsto suggest that the mass has turned itself inside out in some way.There are some suggestions that can go some way to explain why.

In gravitational free fall onto a Schwarzschild surface measured inPlanck time units, the rate of fall is half the Compton length(of thegravitating body)per Planck time unit. So in the case of the Sun therate of fall would be half the Compton length of the Sun per Plancktime unit by the falling object. But this rule only applies down toand including a Planck sphere. After that the rule no longerapplies. The Schwarzschild radius of a proton is 2.483176x10^-54m.Half its Compton wavelength is 6.60705x10^-16m, some 2.66072482x10^38times bigger. If an object was subjected to this amount ofacceleration it would have to travel faster than light.Clearly, a new set of rules is needed. What about relativistictransfer? what about the primordial black holes that were abundantafter the Big Bang? These were estimated to be around the size of theproton opposite. The surface g at the Planck limit is1.109439913x10^51m, which must be equivalent to c. If the primordialblack hole's surface g exceeded this it would go into relativisticmeltdown or gravitational relativistic spacetime contraction. Ifradius contracted so would surface area, so would length, so wouldtime.A four dimension meltdown. For a 2.66x10^38 mass contraction we wouldneed a 4.038776x10^9 contraction rate to effect that.

The Rydberg energy is 2.179874166x10^-18J. We're not sure what theproton nucleus poential is. What the nucleus does do, however, isexert a force on the wave structure of another particle. The mass-time equivalence of a wave can be whittled down to h/c^2 or7.3725x10^-51kg. 2.95676257x10^32x7.3725x10^-51=2.17987x10^-18J.2.95676257x10^32 is c^3 multiplied by the Rydberg constant.So something in the nucleus is generating all that power,2.95676x10^32.

In recent posts mention has been made of the constant 3.62994678 fomthe Gn model. If we take half the proton wavelength, 6.060705x10^-16mand divide by 3.62884678 we get 1.82015064x10^-16m. If we divide thisinto the Rydberg energy of 2.179874166x10^-18J we get the figure1.1973731534x10^-2. This is the discrete Gm equivalence of thenucleus. So our formula could be:

(1.1973731534x10^-2)(7.37250325x10^-51)/4.05049049x10^-35m=2.179874166x10^-18J. The radius or distance, here, is measured by thePlanck radius. The situation.here, is nucleus/wave structure whichcould be construed as zero separating distance. As nothing can beconsidered smaller than the Planck radius it must be Planck.