දැනුම සොයන අය

දැනුම සෙවූවන්

ලියන අපි

From the previous lesson we learnt about the three
main trigonometrical ratios. Lets see how we can find the values of
trigonometrical ratios of some commonly used angles.

The triangle above is an equlateral triangle which means all three sides
are equal in length. So AB = AC, hence ABC angle is equal to ACB angle. AC =
CB, hence CAB angle is equal to CBA angle thus all three angles are equal. Let
the value of an angle be x, then x + x + x = 180°So the ABC angle is
60 degrees whilst the AN perpendicular drawn to BC from A eually divides the
BAC angle so that, BAN angle is 30 degrees.

Let AB = BC = CA = 2a then,

BN = a and

AN = √3a , according to the pythagoras theorem (apply
pythagoras theorem to the triangle ABN) .

Now from BAN triangle we can see
than sin BAN is equal to the ratio, BN/BA.

Thus sin30° = a/2a = 1/2

Likewise we can develop the sine, cosine and tan values of 30°and
60

°.

Now lets consider a right angled isoceles triangle.

Let the two equal sides be of length a then according to the pythagoras
theorem the hypotaneuse of the triangle will be square root(2)a.

So easily we can see that sin45° = cos 45° = 1/√2 and tan 45° = 1.

The table
below will sum up all the trignometrical ratios we have considered above and
you are expected to memorize them for the O/L exam.

From above table we can roughly deduce that from 0 - 90° the sine
and tangent values of an angle increases with the angle while the cosine value
of an angle decreases with the angle.