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http://issues.apache.org/bugzilla/show_bug.cgi?id=37704
p.mouawad@ubik-ingenierie.com changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|RESOLVED |REOPENED
Resolution|FIXED |
------- Additional Comments From p.mouawad@ubik-ingenierie.com 2006-01-11 11:09 -------
In fact I answered too fast, there is a little performance problem with what
you proposed:
Set set = validatorResults.getPropertyNames();
Map propertyMap = new HashMap();
for (Iterator iter = set.iterator(); iter.hasNext();) {
String property= (String) iter.next();
propertyMap.put(property, Boolean.TRUE);
ValidatorResult result = validatorResults.getValidatorResult
(property);
Map map = result.getActionMap();
for (Iterator iterator = map.keySet().iterator(); iterator.hasNext
();) {
String validatorName = (String)iterator.next();
if (!result.isValid(validatorName)) {
propertyMap.put(property, Boolean.FALSE);
break;
}
}
}
With my approach I don't need to get the value:
for (Iterator iterator = map.values().iterator(); iterator.hasNext();) {
ValidatorResult.ResultStatus element = (ValidatorResult.ResultStatus)
iterator.next();
if (!element.isValid())
While with yours:
Map map = result.getActionMap();
for (Iterator iterator = map.keySet().iterator(); iterator.hasNext();) {
String validatorName = (String)iterator.next();
if (!result.isValid(validatorName)) =====>>> Here
What I need and I think would be useful for others is:
Get for each field of the form whether it is in error or not.
Thank you.
Philippe.
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