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The average (arithmetic mean) of the multiples of 6 that are greater than 0 and less than 1,000 is

499 500 501 502 503

Could someone explain what the quickest way to solve this is?Thanks!

Multiples of 6 represent arithmetic progression (aka evenly spaced set). In any evenly spaced set the arithmetic mean (average) is equal to the median and can be calculated by the formula \(mean=median=\frac{a_1+a_n}{2}\), where \(a_1\) is the first term and \(a_n\) is the last term.

First term is 6 and last term is 996 (the last even multiple of 3 below 1000). So \(mean=\frac{6+996}{2}=501\).

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09 Nov 2014, 02:58

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29 Sep 2016, 02:12

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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