by
Blitzer, Robert F.

Answer

$\frac{89}{142}$

Work Step by Step

The probability that an event E will not occur is equal to 1 minus the probability that it will occur.
P(not E)= 1 - P(E)
E: is in the Army or the Navy.
A = Neither in Army nor in Navy
P( is in the Army or the Navy) = 1 - P( Neither in Army nor in Navy)
P( Neither in Army nor in Navy) = $\frac{530000}{1420000}$ = $\frac{53}{142}$
P( is in the Army or the Navy) = 1 - $\frac{53}{142}$
= $\frac{142 - 53}{142}$ = $\frac{89}{142}$