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Question 1 of 40

1. Question

Madhan was 3 times as old as his daughter 10 years ago. After 10 years, Madhan will be twice as old as his daughter. Find out the present age of Madhan.

68 years

70 years

40 years

55 years

80 years

Correct

Let age of the daughter before 10 years = x

Then, age of Madhan before 10 years = 3x

After 10 years, Madhan will be twice as old as his daughter.

? 3x + 20 = 2( x+20)

? x = 20

? Present age of Madhan = 3x + 10

= 3× 20+ 10

= 70 years.

Incorrect

Let age of the daughter before 10 years = x

Then, age of Madhan before 10 years = 3x

After 10 years, Madhan will be twice as old as his daughter.

? 3x + 20 = 2( x+20)

? x = 20

? Present age of Madhan = 3x + 10

= 3× 20+ 10

= 70 years.

Question 2 of 40

2. Question

P walks around a circular field at the rate of two rounds per hour while Q runs around it at the rate of eight rounds per hour. They start in the opposite direction from the same point at 6.45 a.m. They shall first cross each other at?

6.45 a.m

6.50 a.m

7.51 a.m

6.51 a.m

7.45 am

Correct

Since P and Q move in the opposite direction along the circular field, so they will first meet each other when there is a difference of one round between the two.

Relative speed of P and Q = 8+2 = 10 rounds per hour.

Time taken to complete one round at this speed = 1/10 hr = 6 min.

6 Hrs 45 min + 6 min = 6 hrs 51 min i.e, 6.51 a.m

Incorrect

Since P and Q move in the opposite direction along the circular field, so they will first meet each other when there is a difference of one round between the two.

Relative speed of P and Q = 8+2 = 10 rounds per hour.

Time taken to complete one round at this speed = 1/10 hr = 6 min.

6 Hrs 45 min + 6 min = 6 hrs 51 min i.e, 6.51 a.m

Question 3 of 40

3. Question

Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. What is the proportion of the solution Y in the liquid in the tank after 5 minutes?

8 / 15

7 / 15

8 / 17

6 / 13

8 / 13

Correct

Part of the tank filled by pipe P in 1 minute = 1 / 40

Part of the tank filled by pipe Q in 1 minute = 1 / 15

Part of the tank filled by pipe R in 1 minute = 1/ 30

Here we have to find the proportion of the solution Y.

Pipe Q discharges chemical solution Y.

Part of the tank filled by pipe Q in 5 minutes

= 5 × 1 / 15 = 1 / 3

Part of the tank filled by pipe P, Q, R together in 1 minute

= 1/40 + 1/15 + 1/30

= (3+8+4)/120 = 15 / 120 = 1 / 8.

Part of the tank filled by pipe P, Q, R together in 5 minute

= 5 × 1/8 = 5/ 8

Required proportion = (1/3) / ( 5/8) = 8 / 15

Incorrect

Part of the tank filled by pipe P in 1 minute = 1 / 40

Part of the tank filled by pipe Q in 1 minute = 1 / 15

Part of the tank filled by pipe R in 1 minute = 1/ 30

Here we have to find the proportion of the solution Y.

Pipe Q discharges chemical solution Y.

Part of the tank filled by pipe Q in 5 minutes

= 5 × 1 / 15 = 1 / 3

Part of the tank filled by pipe P, Q, R together in 1 minute

= 1/40 + 1/15 + 1/30

= (3+8+4)/120 = 15 / 120 = 1 / 8.

Part of the tank filled by pipe P, Q, R together in 5 minute

= 5 × 1/8 = 5/ 8

Required proportion = (1/3) / ( 5/8) = 8 / 15

Question 4 of 40

4. Question

A boat running downstream covers a distance of 20 km in 5 hours while for covering the same distance upstream, it takes 10 hours. What is the speed of the stream?

2km/hr

4km/hr

1km/hr

1.5 km/hr

None of these

Correct

Rate of downstream=(20 / 5 ) kmph= 4kmph

Rate of upstream =( 20/10) kmph= 2kmph

Therefore Speed of the stream= (1/2)(4 – 2) kmph= 1 kmph

Incorrect

Rate of downstream=(20 / 5 ) kmph= 4kmph

Rate of upstream =( 20/10) kmph= 2kmph

Therefore Speed of the stream= (1/2)(4 – 2) kmph= 1 kmph

Question 5 of 40

5. Question

Two stations X and Y are 170 km apart on a straight line. One train starts from X at 6 a.m. and travels towards Y at 25 kmph. Another train starts from Y at 8 a.m. and travels towards X at a speed of 35 kmph. At what time will they meet?

11. 30 a.m

10.30 a.m

11 a.m

9 a.m

10 am

Correct

Suppose they meet z hours after 6 a.m.

Distance covered by X in z hours = 25× z km.

Distance covered by Y in (z – 2) hours = 35(z – 2) km.

Therefore 25z + 35(z- 2) = 170

60z = 240

Z = 4.

So, they meet at 10 a.m.

Incorrect

Suppose they meet z hours after 6 a.m.

Distance covered by X in z hours = 25× z km.

Distance covered by Y in (z – 2) hours = 35(z – 2) km.

Therefore 25z + 35(z- 2) = 170

60z = 240

Z = 4.

So, they meet at 10 a.m.

Question 6 of 40

6. Question

Simple interest on a certain sum of money for 4 years at 5% per annum is half the compound interest on Rs. 8000 for 2 years at 10% per annum. The sum placed on simple interest is:

Rs.4200

Rs.4250

Rs.5250

Rs.5200

Rs.4000

Correct

C.I = 8000 * (1+(10/100))2 –8000

= 8000 *110/100 * 110/100 – 8000 = 9680 – 8000 = Rs.1680

Therefore, S.I = C.I / 2 = 1680 / 2=Rs. 840

840 = sum * 4 * 5 / 100

:. Sum = Rs.(840 * 100)/ (4 *5) = Rs.4200

Incorrect

C.I = 8000 * (1+(10/100))2 –8000

= 8000 *110/100 * 110/100 – 8000 = 9680 – 8000 = Rs.1680

Therefore, S.I = C.I / 2 = 1680 / 2=Rs. 840

840 = sum * 4 * 5 / 100

:. Sum = Rs.(840 * 100)/ (4 *5) = Rs.4200

Question 7 of 40

7. Question

On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball?

10. Question

Kathir and Anand can do a work in 20 days and 30 days respectively. Kathir started the work and left after 4 days. Anand took over and completed the work. In how many days was the total work completed?

28 days

20 days

23 days

25 days

26 days

Correct

Kathir’s one day’s work= 1/20

Kathir’s 4 day’s work =4* (1/20) = 1/5

Work left= 1-1/5 = 4 /5

Anand’s one day’s work= 1/30

Anand can do work in = (4/5) *(30/ 1) = 24 days

So total days = 24+4 = 28 days

Incorrect

Kathir’s one day’s work= 1/20

Kathir’s 4 day’s work =4* (1/20) = 1/5

Work left= 1-1/5 = 4 /5

Anand’s one day’s work= 1/30

Anand can do work in = (4/5) *(30/ 1) = 24 days

So total days = 24+4 = 28 days

Question 11 of 40

11. Question

Population of a city is 1.2 lakh. If the population of male increases by 5% and the female by 10%, the population will be 1.2835 lakh. What is the number of female in the city ?

42000

45000

47000

51000

55000

Correct

Let the population of female is ‘x’.

Population of male = 1.2 – x

= (110x/100) + [(105/100) (1.2 – x)] = 1.2835

110 x + 126 – 105x = 128.35

5x = 128.35 – 126 = 2.35

x = (2.35/5) = 0.47lakh = 47000

Incorrect

Let the population of female is ‘x’.

Population of male = 1.2 – x

= (110x/100) + [(105/100) (1.2 – x)] = 1.2835

110 x + 126 – 105x = 128.35

5x = 128.35 – 126 = 2.35

x = (2.35/5) = 0.47lakh = 47000

Question 12 of 40

12. Question

A shopkeeper marks his goods 20% above the cost price but give 11% discount on it. If he sells the article for Rs.1575.30 then what is the cost price ?

Rs. 1575

Rs. 1525

Rs. 1500

Rs. 1475

Rs. 1450

Correct

Let the cost price is ‘x’

x×(120/ 100) × (89/100) = 1575.3

x = (157530 × 100) / (120×89) = 1475

Incorrect

Let the cost price is ‘x’

x×(120/ 100) × (89/100) = 1575.3

x = (157530 × 100) / (120×89) = 1475

Question 13 of 40

13. Question

If Rs. 6200 amounts to Rs. 8804 in 3 years 6 months, what will Rs. 7800 amount to in 4 years 6 months at the same rate percent per annum ?

Rs. 11924

Rs. 12012

Rs. 12428

Rs. 12896

None of these

Correct

S.I. = 8804 – 6200 = 2604

r = (2604 × 100) / (6200 × 3.5) = 12% p.a

Now for Rs. 7800, S.I. = (7800 × 4.5 × 12)/100 = 4212

Req. amount = 7800 + 4212 = 12012

Incorrect

S.I. = 8804 – 6200 = 2604

r = (2604 × 100) / (6200 × 3.5) = 12% p.a

Now for Rs. 7800, S.I. = (7800 × 4.5 × 12)/100 = 4212

Req. amount = 7800 + 4212 = 12012

Question 14 of 40

14. Question

The compound interest on a certain sum of money for two years at 8% p.a. is Rs. 499.20. What will be the simple interest at the same rate and for the same time period ?

Rs. 456

Rs. 472

Rs. 480

Rs. 484

Rs. 496

Correct

P[1 +( 8/100)]2 – P = 499.20

P (27/25)2 – P = 499.20

P (729-625) / 625 = 499.20

P = (499.20 × 625) / 104 = 3000

S.I = (3000 × 8 × 2) / 100 = 480

Incorrect

P[1 +( 8/100)]2 – P = 499.20

P (27/25)2 – P = 499.20

P (729-625) / 625 = 499.20

P = (499.20 × 625) / 104 = 3000

S.I = (3000 × 8 × 2) / 100 = 480

Question 15 of 40

15. Question

Certain number of persons can do a work in 50 days. If there were 7 persons more the work could be finished in 14 days less. How many persons were there initially ?

18

24

28

35

None of these

Correct

Let the original number of men ‘x’

7 person (50 – 14 = 36) days work = x persons 14 days work

x = (7 × 36)/14 = 18

Incorrect

Let the original number of men ‘x’

7 person (50 – 14 = 36) days work = x persons 14 days work

x = (7 × 36)/14 = 18

Question 16 of 40

16. Question

[7.995 + 25.96 + 13.02] ÷ 2.490 = ? What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value.)

30

4

9

19

1

Correct

? = (7.995 + 25.96 + 13.02) ÷ 2.490

= (8 + 26 + 13) ÷ 2.5 = 47 ÷ 2.5 ≈ 19

Incorrect

? = (7.995 + 25.96 + 13.02) ÷ 2.490

= (8 + 26 + 13) ÷ 2.5 = 47 ÷ 2.5 ≈ 19

Question 17 of 40

17. Question

(5.95 x 8.06) ÷ (8.03 x 2.04) = ? – 4.95 What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value.)

4

16

8

40

20

Correct

? -. 4 95 = (5.95 × 8.06) ÷ (8.03 × 2.04)

? – 5 = (6 × 8) / (8 × 2) = 3

? ≈ 3 + 5 = 8

Incorrect

? -. 4 95 = (5.95 × 8.06) ÷ (8.03 × 2.04)

? – 5 = (6 × 8) / (8 × 2) = 3

? ≈ 3 + 5 = 8

Question 18 of 40

18. Question

4.014 ÷ 1.894 x 15.011 ÷ 8.971= (?) What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value.)

9

15

3

12

10

Correct

Answer: c

(?) = 4.014 ÷ 1.894 × 15.011 ÷ 8.971

≈ 4 ÷ 2 × 15 ÷ 9 = 2 × 15 ÷ 9 = (30/9) ≈ 3

Incorrect

Answer: c

(?) = 4.014 ÷ 1.894 × 15.011 ÷ 8.971

≈ 4 ÷ 2 × 15 ÷ 9 = 2 × 15 ÷ 9 = (30/9) ≈ 3

Question 19 of 40

19. Question

(6.90)3 – (2.99)3 – (6.02)3 = (?)2 What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value.)

50

25

10

1

100

Correct

( ?)2 = (6.90)3 – (2.99)3 – (6.02)3

≈ (7)3 – (3)3 – (6)3

= 343 – 27 – 216 = 343 – 243 = 100

? = √100 = 10

Incorrect

( ?)2 = (6.90)3 – (2.99)3 – (6.02)3

≈ (7)3 – (3)3 – (6)3

= 343 – 27 – 216 = 343 – 243 = 100

? = √100 = 10

Question 20 of 40

20. Question

[(6.03 x 2.98) – (1.99 x 2.012)] / (2.053 —360.5) = ? What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value.)

1

20

10

15

5

Correct

? = [ (6.03 x 2.98) – (1.99 x 2.012) ] / [ (2.05)3 -360.5]

= (6 × 3 – 2 × 22) / [(2)3 – (36)1/2] = 10 / (8-6) = 10/2 ≈ 5

Incorrect

? = [ (6.03 x 2.98) – (1.99 x 2.012) ] / [ (2.05)3 -360.5]

= (6 × 3 – 2 × 22) / [(2)3 – (36)1/2] = 10 / (8-6) = 10/2 ≈ 5

Question 21 of 40

21. Question

The students of ABC Institute take part in various extra-curricular activities, the distribution of which is as shown below. Total number of 800

What the difference between the, total number of students taking part in Volleyball and Swimming together and the total number of students talking part in Football?

208

190

200

220

184

Correct

Reqd difference = (26 + 16 – 17)% of 800 = 25% of 800 = 200

Incorrect

Reqd difference = (26 + 16 – 17)% of 800 = 25% of 800 = 200

Question 22 of 40

22. Question

The students of ABC Institute take part in various extra-curricular activities, the distribution of which is as shown below. Total number of 800

What is the ratio of the total number of students taking part in Tennis and Swimming together to that taking part in Cricket and Football together?

19:18

17:7

10:9

39:35

28:19

Correct

Required ratio = (22 + 16) / (19+17) = 38/36 = 19:18

Incorrect

Required ratio = (22 + 16) / (19+17) = 38/36 = 19:18

Question 23 of 40

23. Question

The students of ABC Institute take part in various extra-curricular activities, the distribution of which is as shown below. Total number of 800

What is the number of girls who take part in Volleyball, if the ratio of boys to girls is 5 : 11?

143

130

156

65

67

Correct

Number of students taking part in Volleyball = (26 × 800)/100 = 208

Let the number of boys be 5x and girls be I I x.

Now, 5x + 11x = 208

or, I6x =.208

x = 208 /16 =13

Number of girl students who take part in Volleyball = I I x 13 = 143

Incorrect

Number of students taking part in Volleyball = (26 × 800)/100 = 208

Let the number of boys be 5x and girls be I I x.

Now, 5x + 11x = 208

or, I6x =.208

x = 208 /16 =13

Number of girl students who take part in Volleyball = I I x 13 = 143

Question 24 of 40

24. Question

The students of ABC Institute take part in various extra-curricular activities, the distribution of which is as shown below. Total number of

What is the average number of students taking part in Tennis, Cricket, Football and Swimming?

142

148

162

122

158

Correct

Reqd average [ (22+19+17+16)%of 800 ] / 4

= (74% of 800) / 4= (74 x 800) / (100×4) = 148

Incorrect

Reqd average [ (22+19+17+16)%of 800 ] / 4

= (74% of 800) / 4= (74 x 800) / (100×4) = 148

Question 25 of 40

25. Question

The students of ABC Institute take part in various extra-curricular activities, the distribution of which is as shown below. Total number of 800

If out of the number of students taking part in Tennis, 79 are girls, what is the difference between the number of boys and that of girls taking part in Tennis?

24

21

13

10

Other than those given as options

Correct

Total number of students taking part in Tennis = 22% of 800 = (22 x 800) /100 = 176

Out of the number of students taking part in tennis, 79 are girls.

The number of boys who take part in Tennis = 176 — 79 = 97

Difference = 97 — 79 = 18

Incorrect

Total number of students taking part in Tennis = 22% of 800 = (22 x 800) /100 = 176

Out of the number of students taking part in tennis, 79 are girls.

The number of boys who take part in Tennis = 176 — 79 = 97

Difference = 97 — 79 = 18

Question 26 of 40

26. Question

15, 16, 10, 33, ?, 66.25 What will come in place of the question mark :

14.50

12.50

12.25

22.25

None of these

Correct

x1+1, ÷2+2, x3+3, ÷4+4, x5+5

Incorrect

x1+1, ÷2+2, x3+3, ÷4+4, x5+5

Question 27 of 40

27. Question

2, 9, 82, ?, 32826 What will come in place of the question mark :

13130

13456

1313

2675

None of these

Correct

x2^2-2+3, x3^2-3+4, x4^2-4+5, x5^2-5+6

Incorrect

x2^2-2+3, x3^2-3+4, x4^2-4+5, x5^2-5+6

Question 28 of 40

28. Question

32, 321, 682, 1123, ?, 2277 What will come in place of the question mark :

1702

1652

1834

1567

None of these

Correct

+17^2, +19^2, +21^2, +23^2, +25^2

Incorrect

+17^2, +19^2, +21^2, +23^2, +25^2

Question 29 of 40

29. Question

84, ?, 78, 109, 72, 113, 70 What will come in place of the question mark :

109

124

144

107

None of these

Correct

+23, -29, +31, -37, +41, -43

Incorrect

+23, -29, +31, -37, +41, -43

Question 30 of 40

30. Question

11, 15, ?, 71, 333 What will come in place of the question mark :

27

36

29

25

None of these

Correct

Diff of diff is multiples of 6

Incorrect

Diff of diff is multiples of 6

Question 31 of 40

31. Question

33 ÷ 37 × (27)2 × 11.25 + 75% of 45 = ? What should come in place of the question mark (?) in the following questions?

131

132

133

134

135

Correct

? = 33 ÷ 37 × (33)2 × 11.25 + [(75 × 45) / 100]

= (3)3 + 6 – 7 × 11.25 + 33.75

= 9× 11.25 + 33.75

= 101.25 + 33.75 = 135

Incorrect

? = 33 ÷ 37 × (33)2 × 11.25 + [(75 × 45) / 100]

= (3)3 + 6 – 7 × 11.25 + 33.75

= 9× 11.25 + 33.75

= 101.25 + 33.75 = 135

Question 32 of 40

32. Question

144% of 185 – 44% of 85 = 200 + ? What should come in place of the question mark (?) in the following questions?

37

33

29

23

17

Correct

[(144 × 185) / 100] – [(44 × 85) / 100]

= 266.7 – 37.4 = 229 = 200 + 29

Incorrect

[(144 × 185) / 100] – [(44 × 85) / 100]

= 266.7 – 37.4 = 229 = 200 + 29

Question 33 of 40

33. Question

(17.35)2 – (8.85)2 = 200 + ? What should come in place of the question mark (?) in the following questions?

13.7

17.7

19.7

22.7

26.7

Correct

(17.35)2 – (8.85)2 = (17.35 + 8.85) (17.35 – 8.85)

= 2.62 × 8.5 = 222.7

Incorrect

(17.35)2 – (8.85)2 = (17.35 + 8.85) (17.35 – 8.85)

= 2.62 × 8.5 = 222.7

Question 34 of 40

34. Question

(1 / 13) × 3237 + (3 / 14) × 5362 + 200% of 1 = ? + 1335 What should come in place of the question mark (?) in the following questions?

15

35

55

65

75

Correct

(3237 / 13) + [(3 × 5362) / 14] + [ (200 × 1) / 100]

= 249 + 1149 + 2 = 1400

? = 1400 – 1335 = 65

Incorrect

(3237 / 13) + [(3 × 5362) / 14] + [ (200 × 1) / 100]

= 249 + 1149 + 2 = 1400

? = 1400 – 1335 = 65

Question 35 of 40

35. Question

(11 / 7) of (5 / 8) of (13 / 9) of 8568 = ? What should come in place of the question mark (?) in the following questions?

12310

12155

12265

12450

12255

Correct

Incorrect

Question 36 of 40

36. Question

200.1 × 9.9 – 25 × 62.5 + 12 × 144 = ?– 26.49 What should come in place of the question mark (?) in the following questions?

1627.98

1842.28

1958.8

1972.88

2172.98

Correct

200.1 × 9.9 – 25 × 62.5 + 12 × 144 = ?– 26.49

Or, 1980.99 – 1562.5 + 1728 = ?– 26.49

Or, ? = 1980.99 + 1728 + 26.49 – 1562.5

= 3735.48 – 1562.5 = 2172.98

Incorrect

200.1 × 9.9 – 25 × 62.5 + 12 × 144 = ?– 26.49

Or, 1980.99 – 1562.5 + 1728 = ?– 26.49

Or, ? = 1980.99 + 1728 + 26.49 – 1562.5

= 3735.48 – 1562.5 = 2172.98

Question 37 of 40

37. Question

√48 +√80 + √176 + √324 – √121 = ? + 7 + 4√11 What should come in place of the question mark (?) in the following questions?

4(√5 + √7)

6(√3 + √5)

4(√3 + √5)

3(√5 + √7)

9(√2 + √3)

Correct

? + 7 + 4√11 =√48 + √80 + √176 + √324 – √121

Or, ? = 4√3 + 4√5 + 4√ + 7 – 7 – 4√11

= 4 (√3 + √5 )

Incorrect

? + 7 + 4√11 =√48 + √80 + √176 + √324 – √121

Or, ? = 4√3 + 4√5 + 4√ + 7 – 7 – 4√11

= 4 (√3 + √5 )

Question 38 of 40

38. Question

1265 ÷ 25.3 + 102 × 98 – (23)2 = ? What should come in place of the question mark (?) in the following questions?

8517

9517

8717

7087

9087

Correct

1265 / 25.3 + 102 × 98 – (23)2 = ?

= 50 + 9996 – 529 = 9517

Incorrect

1265 / 25.3 + 102 × 98 – (23)2 = ?

= 50 + 9996 – 529 = 9517

Question 39 of 40

39. Question

3√12167 + 3√21952% of 280 – 3√704969% of 56 = ? What should come in place of the question mark (?) in the following questions?