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Drop an altitude from S.The point of intersection with the base (Q in diagram), because the altitude is perpendicular to the base, has the same x-coordinate as S.Coordinates of point Q are (a, 0)The height of the triangle is the difference between the y-coordinate of S and the y-coordinate of Q:b - 0 = b

So the area is

\(\frac{(c - 1)*b}{2} = \frac{b(c - 1)}{2}\)

Answer B

pushpitkc , I think you mixed up your coordinates for the height of the triangle.Where you dropped the altitude, x is not 0. x is a.
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gmatclubot

In the rectangular coordinate system above, the area of triangle RST &nbs
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12 Dec 2017, 15:41