For a cone of heigh H, radius R, and tipping angle from the vertical of
angle, I calculate the volume as:
(H \[Pi] R^2 (H Cos[angle] - R Sin[angle])^3)/(3 (H^2 Cos[angle]^2 -
R^2 Sin[angle]^2)^(3/2))
I have a notebook (using Presentations) giving a step by step derivation
with dynamic displays that I will send to anyone who sends a request to me.
David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/
From: Matthias Bode [mailto:lvsaba at hotmail.com]
Hola:
I completely fail to find a function that decribes the emptying of a right
cone as a function of its inclination.
To illustrate the problem:
We have a right cone (e. g. a common cocktail glass completely filled with
liquid) with a base angle alpha. When we incline the cone from its upright
position to ninety degrees minus alpha/2 - then it will be empty - what is
volume of the remaining liquid inside the cone as a function of the cone's
inclination from its originally vertical position?
(It's not homework; I'm retired and trying to teach my daughter, 10th g
rade German grammar school, the use of MATHEMATICA.)
Best regards,
MATTHIAS BODE
S 17.35775=B0, W 066.14577=B0
2'740 m
AMSL.