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qn 3d
r=(I+7j-5k)+(lambda)(3i-j-2k)
find the ratio AC:CB
co-ords of A -5,9,-9 B 25,-1,11 C 4,6,-3
I thought I could do (-5+9-9)*(4+6-3):(4+6-3)*(25-1+11) and workout the ratio that way I get 1:7
but mark scheme gets 3:7 how and why