Author
Topic: "Flee the Mekillot", a game of dice (Read 182 times)

"Flee the Mekillot" is a gambling game. One player is the Mekillot, and the rest are called Grebbers, Mercenaries, or whatever such pleases the particular crowd playing.

An ante is determined. Each Grebber antes up, and the Mekillot matches each ante. So, for example, if the ante was 10 coins and there were three Grebbers, each Grebber would put in ten coins and the Mekillot thirty coins.

Play is conducted with a pair of numbered dice. The Grebbers' goal is to reach the city gates (a tally of 50 or higher) before the Mekillot does.

Each Grebber rolls twice, adding the two rolls. That is their head start. The Mekillot and then the Grebbers each roll in turn after that. However, the Mekillot adds one to each roll! If the Mekillot reaches the same or higher tally as a Grebber, the Grebber is eaten and eliminated from the game!

At the end, the Mekillot receives two antes worth of coins for each Grebber eaten. The surviving Grebbers divide the rest.

An example game with two Grebbers and an ante of 10. the salt (pot) is 40 coins:

Do you mean from a gambler's point of view? Someone here actually wrote a computer program to simulate 10,000 games. It turns out that the Mek has the advantage with the city gates set to 50. The break even point is actually 42 (tiny Grebber advantage) or 43 (tiny Mek advantage).

If the Mek catches half of the Grebbers, the player of the Mek makes his/her ante back. More and the Mek profits.