>2009/7/15 Scott Sinclair <scott.sinclair.za@gmail.com>:
>> 2009/7/15 Robert Cimrman <cimrman3@ntc.zcu.cz>:
>> nicky van foreest wrote:
>>> Given two vectors x and y, the (perhaps) common mathematical
>>> definition of x < y is that x_i < y_i for all i. Thus, the
>>> mathematical comparison x <y returns just one boolean, not an array of
>>> booleans for each x_i < y_i. I implemented this behavior as
>>> prod(less(X,Y)) (I use less to be able to deal with lists X and Y
>>> also). Is there perhaps a more straighforward/elegant/readible way to
>>> achieve the same behavior?
>>>> assuming x, y are numpy arrays: (x < y).all()
>> You could do the following to handle the case where they aren't:
>>>>> import numpy as np
>>>> x = range(10)
>>>> y = range(1, 11)
>>>> np.all(x < y)
> True
Scratch that
>>> x < y
True
S