(Original post by Kameo)
If I write this word in the exam, and it turns out I was wrong, you are responsible.

What, ? NO! - ENDOTHERMIC is correct.
Well I just had a read -

"To fuse iron into heavier elements requires more energy than is released by the fusion reaction, thus making the reaction unsustainable.
Every element heavier than Iron is created in a stellar explosion (Supernova)."

(Original post by samydude)
What, ? NO! - ENDOTHERMIC is correct.
Well I just had a read -

"To fuse iron into heavier elements requires more energy than is released by the fusion reaction, thus making the reaction unsustainable. Every element heavier than Iron is created in a stellar explosion (Supernova)."

Also - Will we need to know how to many metres are in a parsec or an AU? Because my book talks about them but I was wondering if we need to convert, that they might just tell us how many metres are in them on the exam paper.

(Original post by Sasukekun)
Does anyone have the formula sheet we'll be given in the exam?

Also - Will we need to know how to many metres are in a parsec or an AU? Because my book talks about them but I was wondering if we need to convert, that they might just tell us how many metres are in them on the exam paper.

I think we will be given the value of AU if we require it.
Though we can remember it, as it's 1.5*1011m, not that difficult.
And from this we can derive the value of a parsec.

(Original post by Sasukekun)
Does anyone have the formula sheet we'll be given in the exam?

Also - Will we need to know how to many metres are in a parsec or an AU? Because my book talks about them but I was wondering if we need to convert, that they might just tell us how many metres are in them on the exam paper.

Since Fe has the highest binding energy per nucleon, making it the most stable element! therefore fusion will not proceed after producing the element Fe !
The fusion of iron would subtract energy rather than provide it

(Original post by yadas)
Definitely damping doesnt change the natural frequency.
That means damping doesnt change the frequency at which maximum energy is absorbed by the oscillating system.
Though damping decreases the frequency at which maximum amplitude occures.
So it doesnt change the frequency at which energy resonance occures,
but it does change the frequency at which amplitude resonance occures.A pic from wiki.

(Original post by yadas)
You mean part (iii), right?
We could do that, but we would first need to find the values for L and A (from Lo and Ao), and express T in terms of To.
You are free to use any way you find easier/faster.

Cant we use the values of L and A that weve just found in the previous parts? What we need is the inital T, and since weve been given the current T..just subtract?

(Original post by yadas)
Definitely damping doesnt change the natural frequency.
That means damping doesnt change the frequency at which maximum energy is absorbed by the oscillating system.
Though damping decreases the frequency at which maximum amplitude occures.
So it doesnt change the frequency at which energy resonance occures,
but it does change the frequency at which amplitude resonance occures.A pic from wiki.

Top stuff as usual but are you implying that maximum amplitude happens at a specific frequency?

(Original post by lefneosan)
Top stuff as usual but are you implying that maximum amplitude happens at a specific frequency?

Without damping this specific frequency is natural frequency of the oscillating system, obviously.
Damping reduces the frequency at which maximum amplitude is possible.
Increasing damping further reduces this frequency, as you can see from the picture.
Thought the maximum energu would still be absorbed at natural frequency, even with damping.

(Original post by kappleberry)
Cant we use the values of L and A that weve just found in the previous parts? What we need is the inital T, and since weve been given the current T..just subtract?

Am i missing something?
The way Im doing it..tis not workiing.=/

Are you taking the fourth root of T4?
Using L = 2.8*1026, A = 5.5*1018 and σ = 5.67*10-8, gives a value of T4 as 8.93*1014.
The fourth root of that is about 5470K.
(5800 - 5470 = 330, can be rounded to 300.)