Series
$$r_{eq} = r_1 + r_2 + ... r_n$$
$$V_{eq} = V_1 + V_2 + ... V_n$$
So, now we must plug that formula in. There are two sections: the series part and the parallel part. A good way to think of it is to imagine replacing the parallel part with one resistor, whose resistance would be
$$\dfrac{1}{\dfrac{1}{2} + 1} = \dfrac{2}{3}$$
The series part equals $11 + 4$. The total resistance equals
$$11 + 4 + \dfrac{2}{3} = \boxed{\dfrac{47}{3}}$$
Ohm's Law is $V = IR$. Voltage = $17$ V, resistance = $\dfrac{47}{3}$. Therefore, the current equals $\dfrac{51}{47} $ Amperes.