and many more benefits!

Find us on Facebook

GMAT Club Timer Informer

Hi GMATClubber!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Searched for this multiple times before posting but couldnt find it...

What is the value of |x| ?(1) x = –|x|(2) \(x^2\) = 4

It is not mandatory to solve it algebraically. I have seen modulus question can be solved using PIN quite well.

Here,Say; x=0; |x|=0; -|x|=0; x=-|x|; So, x can be 0.x=1; |x|=1; -|x|=-1; x<>-|x|; So, x can't be 1.x=2; |x|=2; -|x|=-2; x<>-|x|; So, x can't be 2.We see that the modulus of a +ve number is always +ve. When we flip the sign of it we get a -ve. Thus, x can't be +ve because a +ve will not be equal to -ve.

-----------------------------------------------------------------------------------------What you do TODAY is important because you're exchanging a day of your life for it!-----------------------------------------------------------------------------------------

Searched for this multiple times before posting but couldnt find it...

What is the value of |x| ?(1) x = –|x|(2) \(x^2\) = 4

It is not mandatory to solve it algebraically. I have seen modulus question can be solved using PIN quite well.

Here,Say; x=0; |x|=0; -|x|=0; x=-|x|; So, x can be 0.x=1; |x|=1; -|x|=-1; x<>-|x|; So, x can't be 1.x=2; |x|=2; -|x|=-2; x<>-|x|; So, x can't be 2.We see that the modulus of a +ve number is always +ve. When we flip the sign of it we get a -ve. Thus, x can't be +ve because a +ve will not be equal to -ve.

Searched for this multiple times before posting but couldnt find it...

What is the value of |x| ?(1) x = –|x|(2) \(x^2\) = 4

It is not mandatory to solve it algebraically. I have seen modulus question can be solved using PIN quite well.

Here,Say; x=0; |x|=0; -|x|=0; x=-|x|; So, x can be 0.x=1; |x|=1; -|x|=-1; x<>-|x|; So, x can't be 1.x=2; |x|=2; -|x|=-2; x<>-|x|; So, x can't be 2.We see that the modulus of a +ve number is always +ve. When we flip the sign of it we get a -ve. Thus, x can't be +ve because a +ve will not be equal to -ve.