A long jumper leaves the ground at an angle of 20 degrees and travels a horizontal distanceof 7.0m before landing. What is the takeoff speed of the jumper?
To be honest I really don't know how to solve it. A step-by-step explantion would be helpful.

Vertical:
hf=hi+ViSin20*t-4.9t^2
put the timeinair expression in for time
0=0+ViSin20(7/cos20)-4.9(49/cos^2 20)

compute Vi

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