Binomial Distribution

A binomial random variable is the number of successes x in
n repeated trials of a binomial experiment. The
probability distribution of a binomial random variable is called
a binomial distribution.

Suppose we flip a coin two times and count the number of heads (successes). The
binomial random variable is the number of heads, which can take on values of 0,
1, or 2. The binomial distribution is presented below.

Binomial Formula and Binomial Probability

The binomial probability refers to the probability that a
binomial experiment results in exactlyx successes. For example,
in the above table, we see that the binomial probability of getting exactly one
head in two coin flips is 0.50.

Given x, n, and P, we can compute the binomial probability
based on the binomial formula:

Binomial Formula. Suppose a binomial
experiment consists of n trials and results in x successes. If
the probability of success on an individual trial is P, then the
binomial probability is:

Suppose a die is tossed 5 times. What is the probability of getting exactly 2
fours?

Solution: This is a binomial experiment in which the number of trials is
equal to 5, the number of successes is equal to 2, and the probability of
success on a single trial is 1/6 or about 0.167. Therefore, the binomial
probability is:

b(2; 5, 0.167) = 5C2 * (0.167)2 * (0.833)3
b(2; 5, 0.167) = 0.161

Cumulative Binomial Probability

A cumulative binomial probability refers to the probability
that the binomial random variable falls within a specified range (e.g.,
is greater than or equal to a stated lower limit and less than or
equal to a stated upper limit).

For example, we might be interested in the cumulative binomial probability of
obtaining 45 or fewer heads in 100 tosses of a coin (see Example 1 below). This
would be the sum of all these individual binomial probabilities.

Binomial Calculator

As you may have noticed, the binomial formula requires many time-consuming
computations. The Binomial Calculator can do this work for you - quickly,
easily, and error-free. Use the Binomial Calculator to compute binomial
probabilities and cumulative binomial probabilities. The
calculator is free. It can found in the Stat Trek
main menu under the Stat Tools tab. Or you can tap the button below.

What is the probability that the world series will last 4 games? 5 games?
6 games? 7 games? Assume that the teams are evenly matched.

Solution: This is a very tricky application of the binomial
distribution. If you can follow the logic of this solution, you have
a good understanding of the material covered in the tutorial, to this
point.

In the world series, there are two baseball teams. The series
ends when the winning team wins 4 games. Therefore, we define a success as a
win by the team that ultimately becomes the world series champion.

For the purpose of this analysis, we assume that the teams are evenly matched.
Therefore, the probability that a particular team wins a particular game is
0.5.

Let's look first at the simplest case. What is the probability that the series
lasts only 4 games. This can occur if one team wins the first 4
games. The probability of the National League team winning 4 games
in a row is:

b(4; 4, 0.5) =
4C4 * (0.5)4 * (0.5)0 = 0.0625

Similarly, when we compute the probability of the American League team
winning 4 games in a row, we find that it is also 0.0625.
Therefore, probability that the series ends in
four games would be 0.0625 + 0.0625 = 0.125; since the series would end if
either the American or National League team won 4 games in a row.

Now let's tackle the question of finding probability that the world series
ends in 5 games. The trick in finding this solution is to recognize that
the series can only end in 5 games, if one team has
won 3 out of the first 4 games. So let's first find the probability
that the American League team wins exactly 3 of the first 4 games.

b(3; 4, 0.5) =
4C3 * (0.5)3 * (0.5)1 = 0.25

Okay, here comes some more tricky stuff, so listen up. Given that the
American League team has won 3 of the first 4 games, the American League team
has a 50/50 chance of winning the fifth game to end the series.
Therefore, the probability of the American League team winning the
series in 5 games is 0.25 * 0.50 = 0.125. Since the National League
team could also win the series in 5 games, the probability that
the series ends in 5 games would be 0.125 + 0.125 = 0.25.

The rest of the problem would be solved in the same way. You should find
that the probability of the series ending in 6 games is 0.3125; and
the probability of the series ending in 7 games is also 0.3125.