Since the heat of formation for 2 moles of octane is 11,200, you divide by 2 to get 5600kJ for 1 mole. According to the equation above, 1 mole of octane will give you 8 moles of CO2 and 9 moles of H2O. The heat of formation for O2 is zero because it naturally exists and has a bond energy of 0. Recall that heat of formation is=
heat of formation of products - heat of formation of reactants
So you get:
[8(393.5) + 9(285.8)] - [enthalpy of reaction]=-240kJ / 2 =>
The answer is b) -120kJ

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