Code #1, #2 & #3

Observations

If you get all three codes together you have 15 numbers and the rest is all letters. 15 numbers is exactly what you need for 3 passcodes.

ekh9clutc78xqj6iraro38dsg22myre84uub99appi777yrh

A 12×4 grid reveals interesting things

e

k

h

9

c

l

u

t

c

7

8

x

q

j

6

i

r

a

r

o

3

8

d

s

g

2

2

m

y

r

e

8

4

u

u

b

9

9

a

p

p

i

7

7

7

y

r

h

In the first column you can see a good start for a passcode. Then in other columns you can see “cryp” which could lead to the keyword crypto. Let’s rearrange the columns as if we were using a skip of 3: 1, 4, 7, 10, 2, 5, 8, 11, 3, 6, 9, 12

e

9

u

7

k

c

t

8

h

l

c

x

q

i

r

8

j

r

o

d

6

a

3

s

g

m

e

u

2

y

8

u

2

r

4

b

9

p

7

y

9

p

7

r

a

i

7

h

Read going down from the upper left E

eqg99impure778uykj29crypto878durh62alaric347xsbh

Still need a bit of tweaking but let’s split the string in 3 equal parts

eqg99impure778uykj29crypto878durh62alaric347xsbh

The first row is a valid passcode, for the 2nd row move the r at the begining and for the 3rd row move bh to the begining

eqg99impure778uy

rkj29crypto878du

bhh62alaric347xs

If you get all three codes together you have 15 numbers and the rest is all letters. 15 numbers is exactly what you need for 3 passcodes.

ekh9clutc78xqj6iraro38dsg22myre84uub99appi777yrh

A 12×4 grid reveals interesting things

e

k

h

9

c

l

u

t

c

7

8

x

q

j

6

i

r

a

r

o

3

8

d

s

g

2

2

m

y

r

e

8

4

u

u

b

9

9

a

p

p

i

7

7

7

y

r

h

In the first column you can see a good start for a passcode. Then in other columns you can see “cryp” which could lead to the keyword crypto. Let’s rearrange the columns as if we were using a skip of 3: 1, 4, 7, 10, 2, 5, 8, 11, 3, 6, 9, 12

e

9

u

7

k

c

t

8

h

l

c

x

q

i

r

8

j

r

o

d

6

a

3

s

g

m

e

u

2

y

8

u

2

r

4

b

9

p

7

y

9

p

7

r

a

i

7

h

Read going down from the upper left E

eqg99impure778uykj29crypto878durh62alaric347xsbh

Still need a bit of tweaking but let’s split the string in 3 equal parts

eqg99impure778uykj29crypto878durh62alaric347xsbh

The first row is a valid passcode, for the 2nd row move the r at the begining and for the 3rd row move bh to the begining