I'm reading the implementation of the buddy algorithm.I was wondering what happens if someone tries to free a block of order kwhile oneof the buddies of order k-1 which make this block is already free andthe other isn't.From the implementation, it seems to me that this will lead to anincorrect behaviour but I'm not sure of my interpretation.

So I would like to know :Is this allowed ? Or should one make sure not to free already freeblocks ?

Thanks in advance.

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