more algebra 1 help

I need help with this problem: "Find the equation of a line that is perpendicular to y = 6-3x and passes through the x-axis at -4." I keep getting y= 1x + 4 , which I know is wrong because the slope is supposed to be 1/3.

Re: more algebra 1 help

Originally Posted by ineedhelpwithmyhomework

I need help with this problem: "Find the equation of a line that is perpendicular to y = 6-3x and passes through the x-axis at -4." I keep getting y= 1x + 4 , which I know is wrong because the slope is supposed to be 1/3.

You are correct that the slope must equal $\dfrac{1}{3}.$

So $y = m + \dfrac{1}{3} * x.$

What does it mean that the line passes through the x-axis at - 4? It means that y = 0 when x = - 4.