The point slope form of a linear equation: given a point `(x_1,y_1)` and a slope `m` the equation is `y-y_1=m(x-x_1)`

The slopeintercept form is `y=mx+b` where m is the slope and b the y-intercept.

(1) If you are given the standard form, if you solve for y you will have the slope-intercept form.

`Ax+By+C=0`

`By=-Ax-C`

`y=-A/Bx-C/B` where `m=-A/B` and the y-intercept `b=-C/B`

If you are asked to write in point-slope form (and this shouldn't happen) then you can find teh slope (`m=-A/B` ), and you will have to find a point that lies on the line. (My choice would be to substitute x=0 to get the y-intercept) then use `y-y_1=m(x-x_1)` where the point you found was `(x_1,y_1)` .

(2) Given point-slope form:

Again solve for y; this is easier with an example. Given (1,2) and m=3 you have `y-2=3(x-1)`