With a final speed of 50.833m/s after 100m, this is equalivent to 183KmHHowever, the car has three acceleration stats: From 0-100, 100-200 and 200-300KmH

I need to find the distance/point at which the car hits 100KmH as when it hits 100KmH its acceleration changes from 12.9199m/s^2 to 12.34568m/s^2It hits 100KmH (27.777m/s) after 2.15secs so the distance is 0.5*(0+27.777)*2.15 = 29.86111111111111 metres, is this right?So now we do 100m-29.861m=70.1388888888888m and the car accelerates this remaining distance at 12.34568m/s^2So final speed = sqrt(27.777m/s^2 + 2*12.34568*70.138m) = 41.9m/s = 151KmH

So as we can see the original 183KmH compared to the 151KmH makes sense because the second one the car accelerates at a slightly slower pace after 29.8m so it the final speed would be slower.

With a final speed of 50.833m/s after 100m, this is equalivent to 183KmHHowever, the car has three acceleration stats: From 0-100, 100-200 and 200-300KmH

I need to find the distance/point at which the car hits 100KmH as when it hits 100KmH its acceleration changes from 12.9199m/s^2 to 12.34568m/s^2It hits 100KmH (27.777m/s) after 2.15secs so the distance is 0.5*(0+27.777)*2.15 = 29.86111111111111 metres, is this right?So now we do 100m-29.861m=70.1388888888888m and the car accelerates this remaining distance at 12.34568m/s^2So final speed = sqrt(27.777m/s^2 + 2*12.34568*70.138m) = 41.9m/s = 151KmH

So as we can see the original 183KmH compared to the 151KmH makes sense because the second one the car accelerates at a slightly slower pace after 29.8m so it the final speed would be slower.