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weighted average of interest is \((5.25*4+8.25*5)/9 = 62.25/9\), slightly less than 7

I tried a variation of this method (alas after doing the sum in the normal way first )

Here goes my attempt to solve this quickly:

Data: 2k @5.25% and 2.5 @ 8.25%Q1: what can i interpret quicklyInference 1: the amount with higher interest is higher hence the overall interest will be greater than 5.25%this doesnt help with reducing options

Q2: can i get more such data points that help me to reduce options.inference 2: What if the amounts were equal, the avg return would be the average of the percentagesoverall Rate of interest = i(5.25 + 8.25)/2 < i

assuming interest as 2K @5.25% and 2K @ 8.25

=> i >6.75

Eliminate option 3, 4, and 5

Now what about the options 1 and 2 (all options are uncomfortably close)

Q3. What is the differential %

as we accounted for 2K @5.25% and 2K @ 8.25we need to account for 500 @ 8.25 %

Differential interest = 500 * 8.25% = 41.25this would translate into overall % as = 41.25*100/(2K + 2.5K)=41.25/45 almost 1% but greater than 0.9% (this sucks as i now have 7.25%)