Ok, so if you raise a number to a negative exponent, the way to make the exponent positive is to put it in the denominator.
For example, \(\frac{2^3}\) is \(2 \times 2 \times 2 = 8\). \(\frac{2^{-3}\) is the same as \(\frac{1}{2^3}\), which would be \(\frac{1}{8}\). Does that make sense?

No, those are just different examples of negative exponents. They aren't related to the problem except in showing what a negative exponent means.
In the case for the problem, it is 8^-2. So, if we follow the pattern above, we have:
8^-2 = 1 / 8^2
You can find 8^2 = 8 x 8 = 64.
And the result is 1 / 8^2 = 64.