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(1) The median of {a!, b!, c!} is an odd number.(2) c! is a prime number.

A. Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficientB. Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficientC. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficientD. EACH statement ALONE is sufficientE. Statements (1) and (2) TOGETHER are NOT sufficient
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(1) The median of {a!, b!, c!} is an odd number. This implies that b!=odd. Thus b is 0 or 1. But if b=0, then a is a negative number, so in this case a! is not defined. Therefore a=0 and b=1, so the set is {0!, 1!, c!}={1, 1, c!}. Now, if c=2, then the answer is YES but if c is any other number then the answer is NO. Not sufficient.

(2) c! is a prime number. This implies that c=2. Not sufficient.

(1)+(2) From above we have that a=0, b=1 and c=2, thus the answer to the question is YES. Sufficient.

(1) The median of {a!, b!, c!} is an odd number. This implies that b!=odd. Thus b is 0 or 1. But if b=0, then a is a negative number, so in this case a! is not defined. Therefore a=0 and b=1, so the set is {0!, 1!, c!}={1, 1, c!}. Now, if c=2, then the answer is YES but if c is any other number then the answer is NO. Not sufficient.

(2) c! is a prime number. This implies that c=2. Not sufficient.

(1)+(2) From above we have that a=0, b=1 and c=2, thus the answer to the question is YES. Sufficient.

The correct answer is C

I think only B is ok because - c! is prime number -> c = 2- a < b < c and a, b, c is integers -> a = 0, b= 1

(1) The median of {a!, b!, c!} is an odd number. This implies that b!=odd. Thus b is 0 or 1. But if b=0, then a is a negative number, so in this case a! is not defined. Therefore a=0 and b=1, so the set is {0!, 1!, c!}={1, 1, c!}. Now, if c=2, then the answer is YES but if c is any other number then the answer is NO. Not sufficient.

(2) c! is a prime number. This implies that c=2. Not sufficient.

(1)+(2) From above we have that a=0, b=1 and c=2, thus the answer to the question is YES. Sufficient.

The correct answer is C

I think only B is ok because - c! is prime number -> c = 2- a < b < c and a, b, c is integers -> a = 0, b= 1

Can you give me explanation? tks alot.

The problem with statement 2 alone is that a and b can be negative too. c we know is 2 but a can be -2 and b can be 1 or many other cases.Only statement 1 uses a! and b! which implies that a and b cannot be negative and hence should be 0 and 1. Therefore, we need both statements to get the answer.