I tried that and ended up with x/(cos(arcsin(x))). I feel like I have tried everything. I vaguely remember my prof saying something about using a triangle to solve these kinds of problems, but I have no clue what that even means.

so we can draw a right triangle with an acute angle where the opposite side is and the hypotenuse is 1. by Pythagoras, the adjacent side will be

so now, ?

ok, so i almost did the entire problem...don't complain, i left the punch line for you

So this works for all problems like this? Wow, I've never seen it explained so simply before. Thanks for this. This site is great, I'll be posting here a lot more often methinks. (I can help too, not just looking for homework answers)

I tried that and ended up with x/(cos(arcsin(x))). I feel like I have tried everything. I vaguely remember my prof saying something about using a triangle to solve these kinds of problems, but I have no clue what that even means.

Did you draw and label the triangle? The opopsite side is x. The adjacent side is . .

pretty much, there may be cases where things have to be treated differently. but definitely for any problem you will get of this type this will work. there are also ways to do them using formulas, and then there's calculus_jy's way.

Wow, I've never seen it explained so simply before.

really? i wasn't trying to explain it simple. you're just smart that's what it is. i've explained this even simpler with the aids of diagrams on this forum before. and there are other methods for doing them posted as well. do a search.

Thanks for this.

you're welcome

This site is great

yes it is!

I'll be posting here a lot more often methinks. (I can help too, not just looking for homework answers)