Re: Lottery Probability Question

Hey clairescanlon.

Can you show us what you tried?

Hint for first one: The total number of possibilities for the number of permutations of tickets is 49*48*47*46*45*44. If you have different numbers on both then it means that you will have less possibilities since they can't over-lap.

This translates into the second set having only 43 choices to start since we can't duplicate the numbers in the first and this means we have 43*42*41*40*39*38 possible permutations if we can't repeat numbers.

So these events are disjoint so we add up the probabilities to get the total of 1/(49*48*47*46*45*44) + 1/(43*42*41*40*39*38)

The above assumes that you need to get all numbers correct to win: if this is not the case then you need to point this out.