Let yn = the sqrt(n+1)-sqrt(n).
Prove that both yn and sqrt(n)yn converge.

Could someone help me?

We note that,
{y_n} is a postive sequence because,
n+1>n thus, sqrt(n+1)>sqrt(n) thus, sqrt(n+1)-sqrt(n)>0
Thus it has a lower bound.

The sequence is also strictly decreasing.
Because,
y_{n+1}<y_n
If and only if,
y_{n+1}-y_n<0
If and only if,
sqrt(n+2)-sqrt(n+1)-sqrt(n+1)+sqrt(n)<0
If and only if,
sqrt(n+2)-sqrt(n)<2sqrt(n+1)
Which is true (square both sides).