Two like-charged balloons, placed at a distance of .5 meters, experience a repulsive force of .32 N. What is the force if the distance between the two balloons is doubled?

If you use Coulomb's Law, the equation used to find .32 N was Force = the constant of K multiplied by the product of the charges divided by the square of the distance. Therefore, I think to solve this, you need to double r, which would mean that force is one-fourth of what it originally was. Following that, I think you divide .32 N by 4 and the answer would be .08 N.

Please let me know if this is correct.
Thank you very much!
=)
Your help is very much appreciated!

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