Question

A 2.0 kg box rests on a plank that is inclined at an angle 65
degrees above the horizontal. The upper end of the box is attached
to a spring with a force constant of 240 N/m. If the spring is
stretched 0.158 m, and then released from rest, and the coefficient
of kinetic friction between the box and the plank is 0.180, what is
the magnitude of the initial acceleration of the block as it starts
moving up the incline?

This is how I attempted to answer the question: The force
responsible for the box's movement is the restorative force of the
spring (O.158m x 240 N/m) and the forces opposing that are kinetic
friction (0.180 x 2kg x 9.81m/s^2 x cos(65)) and the x component of
gravity (2kg x 9.81m/s^2 x sin(65)). These forces together equal
ma. Therefore, to my understanding, (0.158m x 240 N/m) - (0.180 x
2kg x 9.81m/s^2 x cos(65)) - (2kg x 9.81m/s^2 x sin(65)) = 2kg x a.
However, the answer I find when I solve for acceleration is
incorrect. Am I completely out to lunch in my logic?