Ques 2.

H ≥ M > F <A = B> S

Conclusion:

I. H > B
II. F < S

Solution:

To solve Conclusion
I. H > B
Consider the statement from H to B
H ≥ M > F <A=B
Symbols between H and B are mixer of both lesser than and greater than the symbol which implies H cannot be greater than B.Therefore conclusion I doesn’t follow

To solve conclusion
II. F<S
Consider the statement from F to S i.e. F <A=B> S
Symbols between F and S are mixer of lesser than and greater than symbol implies F can’t be definitely lesser than STherefore Conclusion 2 doesn’t follow

Ques 3.

B > T > Q > R = F

Conclusion:

I. Q ≥ F
II. T> F

Solution:

To solve conclusion
II. T>F
Consider the statement from T to F i.e.
T>Q>R=F
Symbols between T and Fare uniform which consist of only > symbol which implies Twill be definitely greater than FTherefore Conclusion 2 follows

Ques 4.

H < J, F < H, I ≤ J = K

Conclusion:

I. H > I
II. I ≥ F

Solution:

To solve Conclusion
I. H>I
Since it is split statements combine statement with H and I variable
H < J ≥ I
Symbol between H and I are mixer of both > and < which implies H can’t be definitely greater than I.Therefore conclusion 1 doesn’t follow

To solve conclusion
II. I ≥ F
Combine the statement of I and F
F < H < J ≥ I
Symbols between T and Fare not uniform which consist of both < and > symbol which implies I can’t be ≥ FTherefore Conclusion 2 doesn’t follow

Direction (Q5-Q7): Read the information given below and solve the questions that follow.

Statements:

Conclusion:

Solution:

To solve Conclusion I
R < T, consider statement from R to T
T ≤ M > R
Since it is the mixer of both < and > symbolConclusion 1 is false

To solve Conclusion 2
F = M, consider statement from F to M
F = T ≤ M
From the above statement, It is possible that F can be equal to MConclusion II may be True

To solve Conclusion 3
F < M, consider statement from F to M
F = T ≤ M
From the above statement, it is possible that F can be lesser than MConclusion III may be TrueTherefore Either Conclusion 2 or 3 can be true