Gbajabiamila has never been convicted for any crime – campaign office

The majority leader of the house of representatives, Femi Gbajabiamila, was never convicted of any crime in the US, his campaign organisation has said.

Recall that a court in the federal capital territory (FCT) had asked Gbajabiamila to appear before it on Monday, the eve of the speakership contest, over a suit filed by Action Peoples Party (APP).

APP had asked the court to disqualify Gbajabiamila from the race on the grounds that he was convicted in a $25,000 fraud case.

However, during a press conference in Abuja on Wednesday, the campaign organisation led by Abdulmumin Jibrin, a lawmaker from Kano, said the speakership aspirant has also not been accused of any corruption in any country.

He described as “outright lies” claims that Gbajabiamila was once convicted in Georgia, US.

According to the lawmaker, the accusations were meant to distract Gbajabiamila from the race to become speaker of the house of representatives.

“Femi Gbajabiamila has never been convicted for any crime in the US, Nigeria or anywhere,” he said.

“He has never been accused of corruption and has no corruption case. He never committed perjury in Nigeria or any country of the world.

“He has provided clarifications and set records straight. The allegations have been tested and struck out in court. It has been stated that he is a full member of the Bar of Georgia.”

Jibrin also displayed what he said was a letter confirming Gbajabiamila’s membership of the Bar of Georgia as well as the copy of the Nigerian court judgement striking out the case.

“We further wish to state that Femi has not been served any court summons or notified by the clerk of the national assembly. The judiciary must not allow itself to be mixed in this … campaign of calumny,” he said.