2005-09-17T22:17:17ZFluxBBhttp://www.mathisfunforum.com/viewtopic.php?id=1597Hmmm ... without the power of 1.1 it is fairly easy to calculate the "cumulative sum" - it is the average times the count.

For example, the cumulative sum of 1,2,3,4,5 is the average value (3) times the count (5) = 3x5 = 15, and the average of a series of numbers can be worked out by just averaging the first and last (ie (1+5)/2 = 3)

But the " ^1.1 " makes it a geometric series, not linear ...

So I think we are looking at "Power Sums", a slightly tricky area of mathematics that I don't have enough knowledge of.

]]>http://www.mathisfunforum.com/profile.php?id=22005-09-17T22:17:17Zhttp://www.mathisfunforum.com/viewtopic.php?pid=14467#p14467I've always been terrible at working backwards from a formula.

units = 300 * (growingNumber^1.1)

The above formula determines how many units a certain item requires to complete. Each additional item increases in unit consumption to complete. My task is to determine a formula that will return the total number of items that can be built, given a certain number of units.