Summation of forces in the x & y directions is zero since the ladder is in static equilibrium.

3. The attempt at a solution

I'm practically stuck at how to approach this problem. I understand that the summation of forces is zero since its in static equilibrium. But what's really confusing me is how the man standing at that particular area will change the distribution of the forces.

Will there only be a reaction in the y component at the bottom and reaction in the x component at the top?

Where is your diagram? Wall is smooth or not !! Read the problem carefully. The man is standing 60% of the ladder means 60%* length of the ladder.
Draw the force diagram.
You must consider Normal reaction forces at the wall and the floor.
If the wall and floor are rough, you must consider friction.
Then use three equilibrim equations.