Replace Part Of A Cell (first Two Digits)

Nov 21, 2007

I am wanting to replace part of a cell ( the first two digits) with nothing - blank

eg cell contains 441298871657 and i want it to read 1298871657
I am looking for a function to do this, i have tried using the finf and replace function but if 44 appears somewhere else in the value this will also be replaced.

In some cases the letters in the beginning of the cells have been misread as a number (above S as 8), so I want to search and replace those numbers with the correct letter without changing the correct numbers at the end of the cells to letters too. Is there any way to write a search-and-replace code in VBA that will only implement the search-and-replace in (for example) the first five letter-spaces of the cell?

As part of a macro i do a find and replace on a range cells that replaces "/1" with nothing (""). Therefore 2/1 becomes 2, what i don't want though is if the de-nominator includes a 1 but not only 1 to keep the whole of the de-nominator, say 8/11 does not want to become 8/1.

I need a macro that will change the part of the formula that is "CI10001G" to the value of cell A2 which would basically be something along the lines of "CI10004D" so the formula would change to the following:

='H:Folder[CI10004D.xlsm]Sheet'!$C$5

And then this formula will then successfully look in the newly directly file path.

I've recorded a macro to replace the Australian telephone number area codes (at the beginning of each phone number) with international dialling codes. I also need to replace the first two digits ONLY of mobile ( cell) phone numbers which, in Australia, all begin with "04" (see last part of macro code below - column L:L).

With the code the way I've recorded it, if it finds "04" in another part of the number (e.g. 0411 104 111), the second occurrence of the "04" will automatically be replaced with "614" as well which I don't want. So I need some code to add so that the macro only searches and replaces those first two digits in that column. I hope I'm making sense?!

I am trying to filter my excel sheet based on certain digits in a column of part numbers. The part number has 10 characters. I would like to filter it so that all part numbers where the 4th character is the number 5 or 7 is listed and where the 5th character is a zero. (i.e. R4X5831310 is a part number where 5 is the 4th character; I would like the filter to show this part number)

I am looping in Excel to find "NUMBER OF EMPLOYEES". IF found I want to go up one row and replace the first 4 digits with " 9ZZ". The Line 1 data will alway be different so I just want to replace the first 4 digits. I don't want it to effect the rest of the line.

I am working with a lot of data and have been making a table of statistical analysis for several rock types. I have it worked out to where i can filter the data and with the use of a bunch of IF functions, below, and it keeps everything the way I want.

{=MAX(IF($H$2:$H$22="sedimentary rocks",$W$2:$W$22))}

The problem is I have to introduce new rock types, but if I just copy the formulas over i then have to go through hundreds of cells and switch sedimentary rocks to volcanic or whatever new class i have.

How this can be done faster. Maybe some way to say "find "text" within this range and replace" i can do it for actual values but when its embedded in a function im not sure.

I'm trying to 'find and replace' part of a filepath which is buried in hundreds of formula, but when I hit 'Replace All' a file navigation window appears. Hitting cancel simply bring up another window, and again and again, each time a replace is executed.

Is there a formula where it will find all that reads 07-06 and be able to change it to 08-06? Below are samples of formulas where I am looking to change 07-06 to 08-06 without having to go into each cell and manually changing 07-06 to 08-06:

I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).Is there a way to remove this vintage year form the string?

to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.

I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.

Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).

Is there a way to remove this vintage year form the string?

to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.

I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.

I have had some luck with the left side, as in:=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).

I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!

Does anyone have an idea on how to help with this?

Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.

However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.

I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.

I am trying to create a macro where it finds a a certain word in a column for example C. What i want it to do is find anything that says FWD_EUR and then replace that cell (e.g C2) with CASH_EUR_FWD and after it has done that it replaces the adjacent cell (e.g. D2) with EUR_FWD. I then want this to do the same with FWD_USD to CASH_USD_FWD and adjacent cell to USD_FWD.