Chemistry is one of the chemicals, ionic compounds where the United ionic bonds ions in the structure of the formula of metal cations in general, positive ion and a polyatomic anion is the negatively charged

A chemical formula is a combination of elemental symbols and subscript numbers that is used to show the composition of a compound. Depending of the type of compound that the formula represents, the information that it provides will vary slightly. Before we go about learning how to write chemical formulas, it is important that you clearly understand the difference between molecular compounds and ionic compounds.

Ionic compounds are composed of charged ions that are held together by electrostatic forces. A typical type of ionic compound, called a binary compound because it is made up of two elements, will be composed of metallic positive ions (cations) and nonmetal negative ions (anions). Another type of ionic compound, called a ternary compound as it containthree elements, is composed of monatomic ions and polyatomic ions. When dealing with ionic formulas it is very important to remember that the formula does not show how the compound actually exists in nature. It only shows the ratio by which the individual ions combine. For example, the ionic formula for calcium chloride is CaCl2. Since calcium chloride is an ionic compound, this formula does not mean that there are actually two chlorine atoms floating around attached to one calcium atom. Ionic compounds are actually continuous, lacking the discrete units that make up a sample of a molecular substance. Rather, the formula shows that a sample of calcium chloride contains twice as many chlorine atoms as calcium atoms. Remember that ionic compounds are not molecules, so the formula CaCl2 is said to represent one formula unit of calcium chloride.

Molecular compounds are held together by covalent bonds, or shared pairs of electrons. Molecular formulas do show these molecules as they actually exist as discrete units in nature. When we say that the molecular formula of water is H2O, we can see that the molecules of water are made up of three atoms, two hydrogen atoms are covalently bonded to each oxygen atom. A special type of chemical formula, called an empirical formula, shows the composition of a molecule not as it actually exists, but in a simple whole number ratio. The difference between empirical and molecular formulas will be explained in lesson 5-5.

This lesson will concentrate on writing simple chemical formulas when given a formula name. In learning how to write chemical formulas, you will make use of the oxidation numbers that you learned about in lesson 5-2. For your convenience, print out the tables from lesson 5-2 before you continue with this lesson, as they will be referred to from time to time.

Writing Ionic Formulas

I. Binary Compounds - Binary compounds are compounds that are composed of only two elements. When you write the formulas for binary compounds, they will consist of two elemental symbols, and they may also have one or two subscript numbers, if the elements don't combine in a one to one ratio. You are probably familiar with the formula NaCl for table salt. This formula shows no subscripts because one ion of Na will be present for each ion of Cl, in any sample of table salt.

You will be given the name of a binary compound and you will be expected to be able to write the proper formula for the compound. There will be two sources of information for writing the correct formula. The compounds name will give you the elements that make up the compound. The oxidation numbers of the ions involved will show you the ratio by which they combine. Let's go through an example;

Example 1. Write the correct formula for Barium Fluoride.

Step one - Write the symbols for the elements in the compound. If you need to review the elemental symbols, see lesson 5-1. Note that the ending "ide" is used for fluoride to show that it is a negative ion of fluorine.

Barium = Ba Fluoride = F

Step two - Look up the oxidation numbers of the elements involved (in table 5-2b or some similar table), and write them as superscripts to the right of the elemental symbols.Note that when no number accompanies a charge symbol, as in the case of fluoride below, they charge value is understood to be "1".

Barium = Ba2+ Fluoride = F-

Step three - Use the correct combination of ions to produce a compound with a net charge of zero. In this case, (2+) + 2(-1) = 0. So, two fluoride ions will cancel out one barium ion. Since it would take two fluoride ions (each with a charge of negative one) to cancel out one barium ion (with a charge of plus two) we use a subscript of two after the symbol for fluorine to show the ratio.

Step one - Write the symbols for the elements in the compound.Note that the ending "ide" is used for bromide to show that it is a negative ion of bromine.

Lithium = Li Bromide = Br

Step two - Look up the oxidation numbers of the elements involved (in table 5-2b or some similar table), and write them as superscripts to the right of the elemental symbols.Note that when no number accompanies a charge symbol, as in the case of fluoride below, they charge value is understood to be "1".

Lithium = Li+ Bromide = Br-

Step three - Use the correct combination of ions to produce a compound with a net charge of zero. In this case, (+1) + (-1) = 0. so, one lithium ion will cancel out the charge of one bromide ion. This means that the two elements will combine in a one to one ratio, and know subscripts will be needed.

LiBr

II. Ternary Compounds - Ternary compounds are composed of three different elements. The most common types of ternary compounds consist of a metallic cation (positive ion) and a polyatomic anion (negative ion). The only common polyatomic ion with a positive charge is the ammonium ion. At any rate, To write these formulas you will want to have reference tables with the information provided on tables 5-2b and 5-2d.

Example 1. Write the proper chemical formula for potassium hydroxide.

Step one - Write the symbols for the monatomic and polyatomic ions in the compound. You will find the symbol potassium on table 5-2b. Hydroxide is a polyatomic ion, which will be found on table 5-2d. Eventually you will recognize the name of a polyatomic ion, but for now if you can't find an ion on one table, look on the other.

Potassium = K Hydroxide = OH

Step two - Look up the oxidation numbers of the ions involved (in table 5-2b and 5-2d, or some similar tables), and write them as superscripts to the right of the elemental symbols.

Potassium = K+ Hydroxide = OH-

Step three - Use the correct combination of ions to produce a compound with a net charge of zero. Parenthesis must be used if you need more than one of a polyatomic ion. In this case, (+1) + (-1) = 0. So, only one of each ion is used. No subscripts are necessary. If you needed more than one hydroxide ion, it would be put in parenthesis with the subscript on the outside.

KOH

Note the importance of upper and lower case

Example 2. Show the correct formula for Calcium Nitrate.

Step one - Write the symbols for the monatomic and polyatomic ions in the compound.

Calcium = Ca Nitrate = NO3

Step two - Look up the oxidation numbers of the ions involved (in table 5-2b and 5-2d, or some similar tables), and write them as superscripts to the right of the elemental symbols.

Calcium = Ca2+ Nitrate = NO3-

Step three - Use the correct combination of ions to produce a compound with a net charge of zero. Parenthesis must be used if you need more than one of a polyatomic ion. In this case (+2) + 2(-1) = 0. We need to show two nitrate ions in our formula. The subscript is put on the outside of the parenthesis to show that the entire polyatomic ion is doubled.

Ca(NO3)2

The correct use of parenthesis will seem hard at first, but you must master this skill with practice!

III. The Stock System - Some elements, like iron and lead, have more than one oxidation number. If you were given a compound name like lead chloride, you would not know if you should used an oxidation number of +2 or +4 for the lead. The stock system is used to specify which form of an element, that shows multiple oxidation numbers, is used in a particular compound. A roman numeral is shown after the name of the positive ion (cation) to indicate the oxidation number of the positive ion.

Example 1. Show the correct formula for lead(IV) nitrate.

Step one - Write the symbols for the ions in the compound.

Lead = Pb Nitrate = NO3

Step two - Look up the oxidation number of the negative ion involved (in table 5-2b and 5-2d, or some similar tables). The positive ion will have a positive oxidation number equal to the roman numeral. Write the numbers as superscripts to the right of the elemental symbols.

Lead = Pb4+ Nitrate = NO3-

Step three - Use the correct combination of ions to produce a compound with a net charge of zero. Parenthesis must be used if you need more than one of a polyatomic ion.

Pb(NO3)4

Example 2. Show the correct formula for Copper(II) Fluoride

Step one - Write the symbols for the ions in the compound.

Copper = Cu Fluoride = F

Step two - Look up the oxidation number of the negative ion involved (in table 5-2b and 5-2d, or some similar tables). The positive ion will have a positive oxidation number equal to the roman numeral. Write the numbers as superscripts to the right of the elemental symbols.

Copper = Cu2+ Fluoride = F-

Step three - Use the correct combination of ions to produce a compound with a net charge of zero. Parenthesis must be used if you need more than one of a polyatomic ion.

CuF2

Writing Molecular Formulas

I. Binary Molecular Compounds - The standard method for naming binary molecular compounds has changed over the years. Currently, the stock system is commonly used for naming molecular compounds. Names like "carbon dioxide", "carbon monoxide", and "dinitrogen pentoxide" are really remnants of an older system that used prefixes to identify the number of elements involved. When you are writing the formula for a molecular compound using the stock system, you will not really notice any difference from the methods described above, until you study bonding. You should be aware that you are not dealing with ions when you are working with molecular formulas, rather you are looking up what might be called the apparent charge on each atom.

Example 1. Write the correct formula for nitrogen(IV) oxide.

Step one - Write the symbols for the elements involved.

Nitrogen = N Oxide = O

Step two - Use the roman numeral as the apparent charge of the first element. Find the apparent chart of the second element by looking on reference tables such as 5-2a.

Nitrogen = N4+ Oxide = O2-

Step three - Determine the ratio by which the elements will bond to show a net charge of zero. Use subscripts to indicate the number of atoms of each element present. In this case, (+4) + 2(-2) = 0.

NO2

Example 2. Write the correct formula for nitrogen(III) oxide.

Step one - Write the symbols for the elements involved.

Nitrogen = N Oxide = O

Step two - Use the roman numeral as the apparent charge of the first element. Find the apparent charge of the second element by looking on reference tables such as 5-2a.

Nitrogen = N3+ Oxide = O2-

Step three - Determine the ratio by which the elements will bond to show a net charge of zero. Use subscripts to indicate the number of atoms of each element present. In this case, 2(+3) + 3(-2) = 0.

N2O3

II. Other Molecular Formulas - There are other types of molecular formulas, besides binary, which you will eventually be required to write. These lessons will be presented at other times.