Pulses in wire - waves

A wire 5.0 m long and having a mass of 130 g is stretched under a tension of 220 N. If two pulses, separated in time by 30.0 ms, are generated, one at each end of the wire, where will the pulses first meet?

m (distance from the left end of the wire)

From my deduction the each wave starts from the opposite side.
I figured out the v=91.9866 b/c the square root of 220/(.13/5)=91.9866 m/s

I then set up equations
t=time x=distance
91.9866t=x
91.9866(t-3*10^-3)=5-x

I got x to equal 2.6379799 m
However, I am not certain if this is the correct answer and I am down to my last submission. I was wondering if anyone could agree with what I got.

A wire 5.0 m long and having a mass of 130 g is stretched under a tension of 220 N. If two pulses, separated in time by 30.0 ms, are generated, one at each end of the wire, where will the pulses first meet?

m (distance from the left end of the wire)

From my deduction the each wave starts from the opposite side.
I figured out the v=91.9866 b/c the square root of 220/(.13/5)=91.9866 m/s

I then set up equations
t=time x=distance
91.9866t=x
91.9866(t-3*10^-3)=5-x

I got x to equal 2.6379799 m
However, I am not certain if this is the correct answer and I am down to my last submission. I was wondering if anyone could agree with what I got.

I disagree with your answer and agree with Hootenanny. Your mistake is the sign of the 3*10^-3 in the second line. It should be a plus sign.

(it's easy to see. In the first 30 ms, the first pulse travels 2.76 m. There is still a distance of 5-2.76 to travel for both pulses when the second pulse will be emitted. They will obviously meet halfway through this remaining distance, therefore the answer is x= 1/2(5-2.76).