Lenses are a very powerful and practically useful functional construct. They represent “first class” fields for a data structure.

Lenses arose in work on bidirectional programming (for example, in Boomerang), and in Haskell, people have given manydifferentdefinitions of lenses, but the simplest and easiest to replicate in type theory is probably the one based on getters and setters.

Given types and , a lens from to is given by the following data:

a function , the “getter”;

a function , the “setter”;

subject to the following laws:

says that we get what we put in, says that updating with the current value doesn’t do anything, says that if we update twice, only the last update counts.

This definition makes sense for general types and , and it’s straightforward to define composition for those lenses. However, as soon as we try to show – say – that composition is associative, we stumble upon “coherence” issues.

The problem with this definition becomes apparent if, following Russell O’Connor, we think of the pair as a coalgebra of the costate -comonad defined by:

The laws that we specified are only enough to show that is a -coalgebra, which is not a well-behaved notion, unless we restrict our attention to sets (i.e. 0-truncated types).

Unfortunately, it is not yet clear how to define -categorical concepts internally in HoTT, but we can try to restructure the definition to work around the need to deal with higher coherences.

One possible idea is the following: a function is the getter of a lens if we can “coherently move” between any two fibres of . This can be made precise by asking that is the pullback of some map along the projection .

So we arrive at the following definition: a higher lens is a function such that the family of fibres of :

factors through .

At this point, we need to show that for any two sets and , a higher lens from to is the same as a lens.

Suppose is a higher lens, and let be a morphism that factors . Given , we have that

By applying we get an equivalence between and .

Therefore, for any and , we get:

We can now define:

and obtain the setter and the first law at the same time.

To get the other laws, we observe that the are coherent, i.e. given ,

from which the third law follows easily. For the second law, it is enough to observe that coherence implies that is the identity.

So, any higher lens is also a lens, regardless of truncation levels.

Now, let and be sets, and a lens from to . The family of fibres of can be thought of as having values in the universe of sets, which is a 1-type. We are now left with the problem of factoring the map from to a 1-type through .

Nicolai Kraus and I are currently working on a paper on precisely the topic of factoring maps through truncations, where we give, for any and , a necessary and sufficient condition for a map from some type to an -type to factor through .

In our case, we have and , and in this particular example, the condition is as follows: we first need a “0-constancy” proof for :

and then a “coherence” property for :

Together, and form what we call a “1-constancy” proof for .

To show that is 1-constant, we begin by defining a map between any two fibres of :

and showing that it is functorial, in the sense that we have functions:

These can be obtained simply by reversing the above derivation of a lens from a higher lens and using the fact that both and are sets. Now, is easily seen to be an equivalence (its inverse being ), giving , and then follows directly from .

We haven’t shown that these two mappings are inverses of each other. I haven’t checked this in detail, but I think it’s true. To prove it, one would need to rearrange the above proof into a chain of simple equivalences, which would directly show that the two notions are equivalent.

17 Responses to Higher Lenses

Where Iso represents isomorphisms. The lens laws are equivalent to the laws of isomorphisms.

In HoTT the Iso could be replaced with equivalence or even equality (by univalence). I haven’t given it much thought, and I don’t understand much of the category theoretic language used in this post, so I don’t know what happens to higher paths. Also one problem of this definition is that it is large.

In any case, the lenses I defined in this post are non-dependent. I’m actually not sure what dependent lenses should actually be, since any function could be considered as the getter of one (you can always express as a sigma type of the fibres of ).

For , the fibres are all equivalent to , so is just , corresponding to the map constant at .

I don’t think this is an instance of a general technique. Sometimes, there really is no way of avoiding coherences, which usually means that you cannot work internally anymore, at least not until we figure out a way to internalise semi-simplicial sets or similar constructions.

In this case, we are lucky, since we can reduce the particular tower of “coherence properties” we want to asking that a certain map be “constant” in a strong sense (i.e. factor through the -1-truncation of its domain). In practice, however, expressing such a constancy property explicitly would require you to go back to the infinite tower of coherences (at least in the case where you make no assumptions on the truncation levels of the types involved).

The idea (for ) is as follows: given a type , we can construct a corresponding semi-simplicial type in two ways. One is to make it into a 0-coskeletal semi-simplicial type (whose component at level is simply ). The other is to take the constant presheaf at and then take a Reedy fibrant replacement (for which we use an explicit construction). Let’s denote this by .

Then, a function factors through if and only if it can be extended to a presheaf morphism . This turns into a tower of coherence conditions for , which can be simplified to a finite one when is -truncated.

We still have to work out some of the details of the proof, so I’m currently not particularly confident about the exact requirements. We definitely need Reedy limits of towers, and the general case uses certain HITs. We also use strict functoriality of path objects quite liberally, but that could possibly be avoided.

Right, that’s what I would expect. That construction for n=-1,0 and m=0,1 can essentially be found in the book (m=0 via exactness of the category of sets, so that can be constructed as the set-coequalizer of , and m=1 via the Rezk completion, with 1-types viewed as groupoids). Mainly I was wondering whether you’d found a way to express the infinitely many coherence conditions for internally; but if you can express the case of finite m as an internal function of m, that’s pretty impressive too!

How do you use the Rezk completion to prove the factorization property for ? I’m afraid don’t see it. I’m also not sure about the argument for , because doesn’t need to be a set for to factor through , but maybe I just misunderstood what you meant.

Unfortunately, we cannot express the case of finite as an internal function of . Actually, I think that if we had that, we could easily express the case as well, since Reedy limits of “internal” towers do always exist.

We have been toying with the idea of writing some code generator that would give us the statement (and proof!) for any fixed and , so that you could plug it into a proof assistant and use it in practice, assuming the truncations levels are known statically. I don’t know how useful/interesting that would be.

To have a proper internal formulation of this result, I think we really need something like the universe of semi-simplicial types. I have been experimenting with adding ad-hoc rules into the syntax that would allow us to take Reedy limits over arbitrary (countable) inverse categories (as I briefly mentioned in a comment to your own post), but I’m still not sure if and how that would work.

I’m also not sure about the argument for , because doesn’t need to be a set for to factor through

Just 0-truncate it first: since B is a set, f automatically factors through .

How do you use the Rezk completion to prove the factorization property for ?

For and , let A be the codiscrete precategory with A as its type of objects, i.e. for all x,y. Then the Rezk completion of A is the (-1)-truncation of A. Let B be the “discrete” category with B as its type of objects, i.e. for all x,y. Since B is a category, a functor can be induced by a functor , which is basically what you called a “1-constancy proof”.

For and , let A be instead the “discrete” precategory on A, with . Now the Rezk completion of A is the 0-truncation of A.

Unfortunately, we cannot express the case of finite as an internal function of . Actually, I think that if we had that, we could easily express the case as well

Oh, of course! Thanks. That’s exactly the specialization of our proof, by the way. I didn’t recognize the Rezk completion in there.

I don’t see that; can you elaborate?

Well, I meant that one can use coinduction to take the limit of such a tower of coherences. I’m not sure what is known about the existence of coinductive types in models of HoTT, so this might not be a big improvement, but at least we have some syntax to talk about such things.

In fact, suppose the property is expressed by a term
P : (n : Nat) -> E n -> Type

Okay; I look forward to seeing the proof! I can’t think of a way to prove that without having a “geometric realization” for untruncated simplicial objects, which at least naively would be a HIT with infinitely many constructors.