Is there a way to specify the where T:new() restriction but with internal constructor?

I've created a generic class that needs to instantiate its implementation type, so the implementation type has to have an accessible parameter less constructor. Looks like the new() restriction could do the job but its enforcing the implementation type to have a public constructor when I have it internal (but accessible as both are on the same assembly).

Is there a reason to force it to be public rather than "accessible"?

Is there a way to do what I need?

Thanks in advance.

EDIT: The reason to do this is that I have a class X that must be used through a Singleton. The Singleton class is a generic class and I want to make the class X constructor internal to avoid external users accessing the object in a wrong way (calling the constructor).

This is disallowed by the C# language as outlined in section 4.4.3 of the specification Bound and Unbound Types.

If the constraint is the constructor constraint new(), the type A must not be abstract and must have a public parameterless constructor. This is satisfied if one of the following is true.

A is a value type, since all value types have a public default constructor

A is a type parameter having the cosntructor constraint

A is a type parameter having the value type constraint

A is a class that is not abstract and contains an explicitly declared public constuctor with no parameters

A is not abstract and has a default constructor.

A compiler error if any one of these conditions are not met. If you find yourself having types that are public but only with internal constructors, then most likely they should actually be internal types with public constructors.

I would recommend changing your types accessor to internal and its constructor's to public, and make it parameterless. Your public parameterless constructor could then call through to a non-parameterless private or internal constructor to do any additional initialization work.