Hi
What do you mean? It is rather a status message telling you why
termination occured.
If I try Travis's example I also get
In [10]: reload mytest
-------> reload(mytest)
(array([-10.33422249, 32.88295995, 3.7880052 ]), 'Both actual and
predicted relative reductions in the sum of squares\n are at most
0.000000')
My default values are:
leastsq(func, x0, args=(), Dfun=None, full_output=0, col_deriv=0,
ftol=1.49012e-008, xtol=1.49012e-008, gtol=0.0, maxfev=0, epsfcn=0.0,
factor=100, diag=None)
The 0.0000 is in fact 'ftol' = 1.49012e-008 (in my opinion).
Cheers,
Steve
Andrea Riciputi wrote:
> I see, but what I can't understand is the meaning of the error message.
> By the way, if I try the example given at page 16 of "SciPy Tutorial"
> (by Travis), I get the same error message.
>> Any other hint?
>> TIA,
> Andrea.
>> On 5 Apr 2005, at 15:58, steve schmerler wrote:
>>> Hi
>>>> Well it looks as if the algorithm met one of its termination criterias
>> ('ftol', at least mpfit (see earlier posts for mpfit) gives exactly
>> the same message).
>>>> Maybe you should post your code part which calls leastsq.
>>>> Cheers,
>> Steve
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