Ok guys, here it is:
48% carry H gene. That means that the other 52% do not have the H dominant gene, which means that they are homozygotus recessive. From here we can find out the value of q(the frequence of h recessive gene) since hh=q^2. Using windows calculator we get q=0.7211. Since q+p=1 then p=0.2789.
Now the frequence of Hh heterozygotus is: 2pq=2*0.7211*0.2789=0.4022. So 40,22% of your individuals are heterozygotus.
Sorry i missread it the first time
PS: I hate this populational genetics things, never could stand them!!
Regards,
Andrew

"As a biologist, I firmly believe that when you're dead, you're dead. Except for what you live behind in history. That's the only afterlife" - J. Craig Venter