Each array element or non-static class member, in order of array subscript/appearance in the class definition, is copy-initialized from the corresponding clause of the initializer list.

If the initializer clause is an expression, implicit conversions are allowed, except (since C++11) if they are narrowing (as in list-initialization).

If the initializer clause is a nested braced-init-list, the corresponding class member is itself an aggregate: aggregate initialization is recursive.

If the object is an array of unknown size, and the supplied brace-enclosed initializer list has n clauses, the size of the array is n

Static data members and anonymous bit-fields are skipped during aggregate initialization.

If the number of initializer clauses exceeds the number of members to initialize, the program is ill-formed (compiler error)

If the number of initializer clauses is less than the number of members, the remaining members are initialized by empty lists, which performs value-initialization. If a member of a reference type is one of these remaining members, the program is ill-formed (references cannot be value-initialized)

If the aggregate initialization uses the form with the equal sign (T a ={args..}), the braces around the nested initializer lists may be elided (omitted), in which case, as many initializer clauses as necessary are used to initialize every member or element of the corresponding subaggregate, and the subsequent initializer clauses are used to initialize the following members of the object. However, if the object has a sub-aggregate without any members (an empty struct, or a struct holding only static members), brace elision is not allowed, and an empty nested list {} must be used.

When a union is initialized by aggregate initialization, only its first non-static data members is initialized.

Notes

Until C++11, narrowing conversions were permitted in aggregate initialization, but they are no longer allowed.

Until C++11, aggregate initialization could not be used in a constructor initializer list due to syntax restrictions.