Re: Sketching regions in the complex plane

|z- 3i| is the distance from z to 3i and |x- 2| is the distance from z to 2 so S consists of points that are equally distant from 3i and 2. Geometrically, the set of all points equally distant from point P and Q is the perpendicular bisector of the segment PQ.

Algebraically, taking z= x+ iy, |z- 3i|= |z- 2| is the same as which is the same as .