Converting to object

If an object is converted to an object, it is not
modified. If a value of any other type is converted to an
object, a new instance of the stdClass
built-in class is created. If the value was NULL, the new instance will be
empty. An array converts to an object with properties
named by keys and corresponding values. Note that in this case before PHP 7.2.0 numeric keys
have been inaccessible unless iterated.

<!--Example shows how to convert array to stdClass Object and how to access its value for display --><?php $num = array("Garha","sitamarhi","canada","patna"); //create an array$obj = (object)$num; //change array to stdClass object

echo "<pre>";print_r($obj); //stdClass Object created by casting of array

In PHP 5+, objects are passed by reference. This has got me into trouble in the past when I've tried to make arrays of objects.For example, I once wrote something like the following code, thinking that I'd get an array of distinct objects. However, this is wrong. This code will create an array of multiple references to the same object.

notice that the value at each index in the array is the same. That is because the array is just 3 references to the same object, but we change the property of this object every time the for loop runs. This isn't very useful. Instead, I've changed the code below so that it will create an array with three distinct references to three distinct objects. (if you're having a hard time understanding references, think of this as an array of objects, and that this is just the syntax you have to use.)

Notice how the creation of a new object ("$arrayItem = new myNumber();") must happen every time the for loop runs for this to work.This took me forever to figure out, so I hope this helps someone else.

In response to sirbinam.You cannot call a function or method before it exists. In your example, the global instance of stdout is just being passed around to differnet references (pointers). It however exists in the "dump" function scope via the global keyword.

The code below works fine and illustrates that "stdout" has been defined before its instantiation.

All classes and functions declarations within a scope exist even before the php execution reaches them. It does not matter if you have your classes defined on the first or last line, as long as they are in the same scope as where they are called and are not in a conditional statement that has not been evaluated yet.

If you call var_export() on an instance of stdClass, it attempts to export it using ::__set_state(), which, for some reason, is not implemented in stdClass.

However, casting an associative array to an object usually produces the same effect (at least, it does in my case). So I wrote an improved_var_export() function to convert instances of stdClass to (object) array () calls. If you choose to export objects of any other class, I'd advise you to implement ::__set_state().

Note: This function spits out a single line of code, which is useful to save in a cache file to include/eval. It isn't formatted for readability. If you want to print a readable version for debugging purposes, then I would suggest print_r() or var_dump().

In reply to the usort thing, you can access a property of an object dynamically by:<?php$obj = (object)array("Test" => "bar")$var = "Test";echo $obj->$var;?>This will output "bar", and do notice I call on ->$var and not just ->var.

If you need to force json_encode() to produce an object even when an array is empty or does not have successive 0-based numeric indices, you can simply convert the array to an object. JSON_FORCE_OBJECT does the same with ALL arrays, which might not be what you want.

//Result SET 2//array is empty => expected result ##everything is all right//object is empty => expected result ##everything is all right//EmptyClass is empty => expected result ##everything is all right

Here we have (2) two INSTANCES of User, but each instance was only INSTANTIATED once - when we used the 'new' operator.

And now looking at the printed output, you can see there are no values for their first or last names. This means that the objects themselves have NOT been INITIALIZED. To remedy this situation, rewrite the class definition by adding a __construct() method.

The __construct() method is called automatically by PHP when it sees the 'new' operator. Our __construct() method above requires the first and last names to be passed in as arguments and uses them to INITIALIZE objects when INSTANTIATING new INSTANCES.

you want to cast an object of a Bug to BugDetails like this<?php $clone = (BugDetails) clone $this;// OR$clone = (BugDetails) $bug;?>which doesn't work in PHP, you have two options:1. Copying all (including private) properties manually (you could also use get_object_vars(), but this is shorter):<?php $clone = new BugDetails(); foreach ($this as $key => $val) {$clone->$key = $val; }?>2. Serialize an object Bug, manipulate the resulting string so that it has BugDetails inside and unserialize it.See here: http://blog.adaniels.nl/articles/a-dark-corner-of-php-class-casting/

// You can type-cast in the middle of an expressionfunction customHTML($some_object) {// this function expects an object as the argument and returns some output}print '<p>Writing some output ' . customHTML( (object) array('rows'=>3, 'cols'=>4) );