The mole ratio is a follows 0,023:0,046:0,0153 which can be reduced to 3:6:2.

The emperical formula for the substance is then [itex]C_{3} H_{6}
Br_{2}[/itex]

Next I need to find the molecule's formula : [itex](C_{3} H_{6} Br_{2})_n[/itex]
This is done by calculating the n-value(which is the ratio between the moler masse of [itex](C_{3} H_{6} Br_{2})_n[/itex] and of the actual substance).

The actual molar mass is calculated as follows:
3,006 grams of the actual substance is placed in a container with a volume 500 mL. This is inturn heated to temperature of 150 degress celcius which generates a pressure within the container of 1,047 bars.

NOTE: In South America, for example, people use the opposite notation. Points separate thousands, while a comma separate the integer part from the decimal one.

2. Let's go down one more decimal place. We approximately have: 0.02306. Since the last digit is [tex] N = 6 \geq 5 [/tex], we must add 1 to our last decimal place. Otherwise, you would not need to add anything.

3. You may have noticed I used scientific notation up there. Try to stick to it.

Apply the same method to the remaining ones. Keep in mind it's better to use fractions when using results in further calculations.