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anonymous

5 years ago

ok the answer that i have that is really not completed is correct or not?

anonymous

5 years ago

ok i will try i am kinda rusty on this i havent did this for a long time

.Sam.

5 years ago

For (a+4)^3
(a+4)^3=(a+4)(a+4)(a+4)
So, you can apply FOIL to (a+4)(a+4)(a+4) , two times.
It is not complete, you have to apply the FOIL method,
(a+4)(a+4)(a+4)
When you distribute, you will get
(a^2+8a+16)(a+4)
Then try expanding it again.

More answers

There are some examples learning FOIL here: http://www.mathsisfun.com/algebra/polynomials-multiplying.html

anonymous

5 years ago

a*a*a=a^3
4+4+4=12a

anonymous

5 years ago

no.. it is 48a

anonymous

5 years ago

48a where i have my ? at

anonymous

5 years ago

i am trying to figure out how o get that number thats all and i keep getting answers that is not helping on how to find...

anonymous

5 years ago

so could you please show me how did you get 48a?

anonymous

5 years ago

\[(a+b)^3=a^3+3a^2b+3ab^2+b^3\]

anonymous

5 years ago

Or If u knw Binomial Theorem Use it..)

anonymous

5 years ago

ok lets see here i am going to figure out how you got 48a

.Sam.

5 years ago

(a^2+8a+16)(a+4)
When you're here, there's a shortcut to look at the coefficient of a, you look at which multiples gives you 'a'.
From here you can see that 8a multiply by 4 gives you 32a
And 16 multiply by a gives you 16a
Since its adding up, 32a+16a=48a

anonymous

5 years ago

thank you so it is a^3+12a^2+48a+64

anonymous

5 years ago

ok i dont remember using that it has been years so some of this stough i remember how to....

anonymous

5 years ago

i feel old brained

anonymous

5 years ago

ohhhh k

anonymous

5 years ago

now i get it i am so sorry ppl thank you so much for bearing with me i havent been in school fo a long time and i am warming up on old math memories