RD Sharma 2019 Solutions for Class 7 Math Chapter 3 - Decimals

RD Sharma 2019 Solutions for Class 7 Math Chapter 3 Decimals are provided here with simple step-by-step explanations. These solutions for Decimals are extremely popular among class 7 students for Math Decimals Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the RD Sharma 2019 Book of class 7 Math Chapter 3 are provided here for you for free. You will also love the ad-free experience on Meritnation’s RD Sharma 2019 Solutions. All RD Sharma 2019 Solutions for class 7 Math are prepared by experts and are 100% accurate.

Page No 3.4:

Question 3:

Answer:

∴2310=2.3
ii) Let us first convert the given fraction to a proper fraction. We get:

2518= 2018
To convert 2018 into decimals, let us multiply the numerator and denominator separately by 125. We get:

201×1258×125=251251000=25.125

iii)By simplifying 39735 we get

39735=3915
Now let us first convert the fraction to a proper fraction. We get: 3915=1965
Now to convert 1965 into decimals, let us multiply the numerator and denominator separately by 2. We get:196×25×2=39210=39.2

iv) Let us first convert the given fraction to a proper fraction. We get:

15125 = 37625
To convert 37625 into decimals, let us multiply the numerator and denominator separately by 4. We get: