The slope of the line passing through the point is 4/11.
I first calculated the slope of QR, which was -11/4, and p is a perpendicular bisector of that line so it is the negative reciprocal 4/11 which is passing through the point P.

My understanding is that the slope passing through p is 4/11, yes.
The equation of a line im y=mx+b
If you plug in the co-ordinates for P you will get this
7=4/11(3)+b
i am unable to figure it out from here

My understanding is that the slope passing through p is 4/11, yes.
The equation of a line im y=mx+b
If you plug in the co-ordinates for P you will get this
7=4/11(3)+b
i am unable to figure it out from here

See Equation of any line can be written as y=mx+b.
One should know the value of m and b.you have calculated m=4/11.but still don't know b.
By 7=4/11(3)+b we can get value of b that is
b=7-12/11
now put the value of m and b in y=mx+b and you will get the desired equation.now any problem?Feel free to ask.

Ok but now we must make a final product
y=4/11+7-12/11
Is that how the final product is or do we have to simplify 7-12/11 before putting it into the final product, if so how?

Thanks

No. The final product is
y=4/11 (x)+7-12/11
don't forget 1)x and 2)completing calculation of
7-12/11.
May be you should think about the concepts like how an equation can represent a line,what parameters are needee and why.this will make your understanding very clear.