Airplane drops a package (relative motion)

1. The problem statement, all variables and given/known data
A plane flying at a speed of 275 m/s at an altitude of 3000 m drops a package. The plane doesn't change its direction or speed and there is no wind resistance.
a) Where does the package hit the ground relative to the point of release?
b) Where does the package hit the ground relative to the moving airplane?

2. Relevant equations
R = sqrt A2 + B2

3. The attempt at a solution
a. Well I know that it would land directly under it because there is no wind resistance. But I don't know how to come up with that answer.

b. I did
R = 2752 +30002 and took the square root.
I came up with 3,013m.

1. The problem statement, all variables and given/known data
A plane flying at a speed of 275 m/s at an altitude of 3000 m drops a package. The plane doesn't change its direction or speed and there is no wind resistance.
a) Where does the package hit the ground relative to the point of release?
b) Where does the package hit the ground relative to the moving airplane?

2. Relevant equations
R = sqrt A2 + B2

3. The attempt at a solution
a. Well I know that it would land directly under it because there is no wind resistance. But I don't know how to come up with that answer.

b. I did
R = 2752 +30002 and took the square root.
I came up with 3,013m.

The package fell 3000m at an acceleration of -9.8m/s^2 with a Vi of 0. Just divide the displacement (3000m) by a = -9,8m/s^2 and it give you the time it took the package to hit the ground in s^2. Then take the square root to obtain s.

The package fell 3000m at an acceleration of -9.8m/s^2 with a Vi of 0. Just divide the displacement (3000m) by a = -9,8m/s^2 and it give you the time it took the package to hit the ground in s^2. Then take the square root to obtain s.