(1 x 2 x 3) x (1 x 2) = 6 x 2 = 12 So having worked this out, it appears that the formula is produced by multiplying the number of times the letters are repeated factorial together, and this is the number that you divide into the

formula that can be used to find the number of different arrangements for words that have one letter repeated any amount of times. I have already worked out that if you want to find out how many different arrangements there are for a 5-letter word for example, you would calculate 5!.

X 2 ! X 2 ! 8 This is due to the fact that the six different letters can be arranged in any order, and because all of them are different, it dose matter which order they go in. However, with more than one letter repeated more than once, the total number of arrangements is reduced

Formulae 1 letter same (ABC) n!/1! 2 letters same (AAB) n!/2! 3 letters same (AAA) n!/3! For each sector (1 letter the same, 2 letters the same, etc) the factorial needs to be divided by something. For example, if you were looking at 2 letters the same and words with 4 letters in them, you would find 4!