The official 53 drinking game

http://www.fiftythree.orgShould every drinking game have its own website, or should every
website have its own drinking game?

Authors:

One, Zero, PKH, and bluto.
HTML Markup by: Lloyd Worthnone, drunkard

The Rules:

You roll 4 dice.

You have to achieve 53 out of them or you must take a drink
and roll again to make 53.

Each of the dice can only be used once for Valueness.

Each of the dice can only be used once for Pairness/Tripleness/Quadness.

You don't have to use all of the dice, but you have to take one
drink for each of the remaining unused dice.

When you make 53, you do not have to drink, and dice are given
to the next player to make 53.

If you roll a 5 and a 3, this is called 53 the easy way. It is
a social. You still must drink for the remainder, if any.

If you roll 5 5 3 3, this is a waterfall.

There is a one drink penalty for using one pairness, however Tripleness and Quadness is free.

If a player makes 53 the hard way, everyone one else must drink

Valueness and pairness:

These 4 dice have 2 different properties. One which is the most
familliar is to use the number on top of the dice as they are
rolled. This is called the Valueness property. The 2nd way
dice can be used is through multiple occurances of a particular
number such as a pair or triple of a number. You can use this
property called the pairness concurrently with valueness to
reach 53.
Pairness of 2 dice is '2'. Pairness (or tripleness) of 3 dice is
3. Beginning players often make the mistake of using "one pair"
or '1' when the value of a pair is in fact '2'. Remember the
penalty for using pairness, however Tripleness or Quadness is free.

How to reach 53:

To get 53 out of 4 dice, you have 2 options.
One is to add, subtract, multiply, and divide the valueness and
pairness of the dice to reach the number 53. This is called 53
the hard way. The other and more
commonly used option is to add, subtract, multiply, and divide the
valueness and pairness of the dice to achieve and individual 5 and
an individual 3 while still only using each of the dice in accordance
with rules #3 and #4.

Examples:

The authors of 53 realize this may not be the easiest game to grasp
offhand, and so many examples are included.

First off, it's a social since there is a '5' and a '3' rolled. As it stands,
the player must take 2 additional drinks because of the leftover dice.
But the more intellegent player would notice the pairness of the 5's (which
then gives us a '2') and divide it by the remaining '2' to give us a '1'
that we can multiply against 53. So the player only has to take one
additional drink because of the penalty for pairness.
But the even more experienced player would add the 5's together to reach
10, and divide by 2 to get 5. Then with the '3' we have 53 without any
penalty drink since all of the dice were used without pairness.

Solution: 2 + 3 is 5, and use the other '3' for 53. Take a penalty drink
because of the unused '6'.
Better solution: '6' minus a '3' gives us 3. '2' plus the other '3' is the 5.