1180 is a composite number because it has factors other than 1 and itself. It is not a prime number. The 12 factors of 1180 are 1, 2, 4, 5, 10, 20, 59, 118, 236, 295, 590…, and 1180. The proper factors of 1180 are 1, 2, 4, 5, 10, 20, 59, 118, 236, 295, and 590 or, if the definition you are using excludes 1, they are 2, 4, 5, 10, 20, 59, 118, 236, 295, and 590. The prime factors of 1180 are 2, 2, 5, and 59. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed. The 3 distinct prime factors (listing each prime factor only once) of 1180 are 2, 5, and 59. The prime factorization of 1180 is 2 x 2 x 5 x 59 or, in index form (in other words, using exponents), 2 2 x 5 x 59. NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.

As the definition of a prime number is 'a number that can only be divided by one or itself, and still leave a whole number.' Anything in the eight times table would be divisib…le by two and four. 27 can also be divided by both three and nine.

In number theory , the fundamental theorem of arithmetic , also called the uniquefactorization theorem or the unique-prime-factorizationtheorem , states that every intege…r greater than 1 either is prime itself or is the product of prime numbers , and that this product isunique, up to the order of the factors. For example, .
1200 = 2 4 Ã 3 1 Ã 5 2 = 3 Ã 2 Ã 2Ã 2 Ã 2 Ã 5 Ã 5 = 5 Ã 2 Ã 3 Ã 2 Ã 5 Ã 2 Ã 2 = etc. .
The theorem is stating two things: first, that 1200 can be represented as a product of primes, and second, no matter howthis is done, there will always be four 2s, one 3, two 5s, and noother primes in the product. .
The requirement that the factors be prime is necessary:factorizations containing compositenumbers may not be unique (e.g. 12 = 2 Ã 6 = 3 Ã 4). .
This theorem is one of the main reasons for which 1 is notconsidered as a prime number: if 1 were prime, the factorizationwould not be unique, as, for example, 2 = 2Ã1 = 2Ã1Ã1 = ...