We have some good integrators here...well...let see this one done. Prove

Good luck...

June 15th 2008, 07:58 PM

topsquark

Quote:

Originally Posted by Mathstud28

We have some good integrators here...well...let see this one done. Prove

Good luck...

From the way your solution is written I am presuming m, n, and p are all positive integers?

-Dan

June 15th 2008, 08:32 PM

TwistedOne151

First step

Well, right away I see you can make the substitution . Then we have
Which takes care of the term containing a. Proving that
will require a bit more thought. I'm thinking a beta function integral may be involved at some point.

--Kevin C.

June 15th 2008, 09:43 PM

Mathstud28

Quote:

Originally Posted by topsquark

From the way your solution is written I am presuming m, n, and p are all positive integers?

-Dan

No integers just

Although you may be right due to the

It should also be noted that I do not have the solution to this, that is why I am so curious.

June 16th 2008, 08:52 AM

TwistedOne151

Next steps

Next, I see trying to find
by the substitution . Thus gives , and thus we see:.