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At a certain university, the ratio of undergraduate students with an a
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14 Sep 2018, 23:18

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64%(02:11) correct 36%(01:46) wrong based on 78 sessions

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At a certain university, the ratio of undergraduate students with an associate’s degree to those without an associate’s degree is 1:3. Additionally, the ratio of graduate students to undergraduate students is 1:5. If all students at the university are either undergraduate or graduate students, what is the ratio of undergraduates without an associate’s degree compared with the entire student body?

Let \(S = UG+G\) ...all students at the university are either undergraduate or graduate students...

so, \(G=S-UG\)

we can rewrite eq.3 as

\(\frac{(S-UG)}{(UGA+UGWA)} = \frac{1}{5}\)

from eq.2,

\(\frac{(S-UGA-UGWA)}{(UGA+UGWA)} = \frac{1}{5}\)

from eq. 1,

\(\frac{(S-1.333UGWA)}{(1.333UGWA)}\) = \(\frac{1}{5}\)

Divide numerator and denominator by S and separate \(\frac{UGWA}{S}\) from the other terms to reach the answer.

\(\frac{UGWA}{S} = \frac{5}{8}\)

harish1986 wrote:

At a certain university, the ratio of undergraduate students with an associate’s degree to those without an associate’s degree is 1:3. Additionally, the ratio of graduate students to undergraduate students is 1:5. If all students at the university are either undergraduate or graduate students, what is the ratio of undergraduates without an associate’s degree compared with the entire student body?

For the number of undergraduates you can choose a number which is divisible by 4,6 and 5. So if a total number of undergraduates is 60, than the number of undergraduates with associates degree is 15 and the number of undergraduate students without associates degree is 45 (\(\frac{15}{45} = \frac{1}{3}\)). The ratio of graduates and undergraduates is 1/5 and from that you can calculate the number of graduates \(\frac{60}{5} = 12\). At this point you have the number of undergraduates without degree and the total number of students. The final result is \(\frac{45}{(60 + 12)} = \frac{5}{8}\)

Originally posted by shtepa on 26 Oct 2018, 10:30.
Last edited by shtepa on 27 Oct 2018, 09:29, edited 1 time in total.

For the number of Under graduates you can choose a number which is divisible by 4,6 and 5. So if a total number of Under graduates is 60, than the number of undergraduates with associates degree is 15 and the number of grad. students without associates degree is 45 (\(\frac{15}{45} = \frac{1}{3}\)). The ratio of graduates and undergraduates is 1/5 and from that you can calculate the number of graduates \(\frac{60}{5} = 12\). At this point you have the number of undergraduates without degree and the total number of students. The final result is \(\frac{45}{(60 + 12)} = \frac{5}{8}\)

Thanks. It really helped.. i think you missed 'Under' as highlighted... Thanks s much

gmatclubot

Re: At a certain university, the ratio of undergraduate students with an a &nbs
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27 Oct 2018, 09:11