On 2011-07-28 at 18:55 -0400, TJ Luoma wrote:
> the script "foo.sh" read .source like this:
>
> . $HOME/.source
>
> and then I did
>
> echo "$NAME"
>
> it would give me
>
> foo.sh
>
> but in zsh I get
>
> zsh
Are you sure?
% cat -v foo
. $HOME/bar
% cat -v bar
echo $0
% zsh -f foo
/home/me/bar
% bash foo
foo
The point is that in bash, sourcing a script does not change $0 while in
zsh it does by default, because FUNCTION_ARGZERO is set.
% cat -v foo2
unsetopt function_argzero
. $HOME/bar
% zsh -f foo2
foo2
If you want to be portable to both bash and zsh, then:
[[ -n $ZSH_VERSION ]] && unsetopt function_argzero
This does, unfortunately, have to be done in the script which does the
including, so you can't have a common library used by both shells which
assumes that $0 is the name of the original file and which can just be
simply included.
-Phil