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I feel like this should be simple but i can't figure it out.
In a case statement, i know how to use ranges to compare against the
given variable. But how do i use < or > ? eg i want to do this:
age = 25
category = case age
when < 12 : "child"
when 13..17 : "minor"
when 18..24 : "young ad*lt"
when 25..49 : "ad*lt"
when 50..64 : "middle aged"
when > 65 : "senior"
else : "not an age"
end
(please don't anybody be offended by my age categories, i just made up
this example off the top of my head)
Anyway, the above doesn't work - syntax error.
Neither does this:
when age < 12 : "child"
the test doesn't pass, so if age is eg 10, i get nil back.
Can someone set me straight?
thanks
max
*******************************
postscript - it seems the word 'ad*lt* triggers the spam filter. hence
the odd wording above.

Max W. wrote:
> In a case statement, i know how to use ranges to compare against the> given variable. But how do i use < or > ?
Simplest solution is to use a Range with extreme bounds, or use an if
statement (if age < 25 ...).
The long answer is to explain that
case foo
when bar
...
end
is syntactic sugar for
if bar === foo
...
end
So you can get whatever behaviour you like by creating an object which
responds to the === method.
class Bounds
def initialize(meth,val)
@meth, @val = meth, val
end
def ===(other)
other.send(@meth, @val)
end
end
def is(meth,val)
Bounds.new(meth,val)
end
age = 70
case age
when is(:<,25)
puts "Youngster"
when is(:>,65)
puts "Oldie"
end
If you wanted this to be more efficient, you could define constants like
UNDER_25 = is(:<,25)
OVER_65 = is(:>,65)
case age
when UNDER_25
... etc
end

2009/6/2 Brian C. <removed_email_address@domain.invalid>:
> Max W. wrote:>> In a case statement, i know how to use ranges to compare against the>> given variable. Â But how do i use < or > ?> end> end
I've attached a similar but more general approach - and a few others as
well.
Kind regards
robert

Wow, that's a lot more complicated than i thought. I think for the sake
of ease and readability i'd stick with doing a more longwinded version,
like
category = case
when age < 12 : "child"
when (13..17).include? age : "minor"
when (18..24).include? age : "young ad*lt"
when (25..49).include? age : "ad*lt"
when (50..64).include? age : "middle aged"
when age > 65 : "senior"
else : "not an age"
end
thanks for the insight though!
cheers
max

thanks for your in-depth answer robert! i'll chew over that. but, in
terms of readability, i think my solution of not passing age into the
block and instead testing it on every line is fine.
thanks a lot though.
max

Max W. wrote:
> Wow, that's a lot more complicated than i thought. I think for the sake> of ease and readability i'd stick with doing a more longwinded version,> like>> category = case> when age < 12 : "child"> when (13..17).include? age : "minor"> when (18..24).include? age : "young ad*lt"> when (25..49).include? age : "ad*lt"> when (50..64).include? age : "middle aged"> when age > 65 : "senior"> else : "not an age"> end>> thanks for the insight though!
If you want to allow for the possibility of fractional ages:
when (13...18).include? age
when (18...25).include? age
when (18...50).include? age
.. etc

Le 2 juin 2009 à 11:12, Max W. a écrit :
> category = case age> when < 12 : "child"> when 13..17 : "minor"> when 18..24 : "young ad*lt"> when 25..49 : "ad*lt"> when 50..64 : "middle aged"> when > 65 : "senior"> else : "not an age"> end
As the others pointed out, there's no easy way to do what you want to.
On the other hand, if you know the bounds of your inputs, your method
isn't bad ; I'd write :
category = case age
when 0...12 then "child"
when 12...18 then "minor"
when 18...25 then "young ad*lt"
when 25...50 then "ad*lt"
when 50...65 then "middle aged"
when 65...999 then "senior"
else "not an age"
end
Note that the use of : within if's and case's has been deprecated in
Ruby 1.9 and the next versions.
Fred

Clifford H. wrote:
> Brian C. wrote:>> Simplest solution is to use a Range with extreme bounds,>> ... such as a range that ends in Infinity:>> 65..(1/0.0)> => 65..Infinity>> ;-)>> Clifford H..
haha, i thought about that but it seemed kind of crazy. It surprises me
a little that Infinity isn't a singleton class like NilClass in ruby.

On Jun 2, 2009, at 3:32 PM, Max W. wrote:
>>>> Clifford H..> haha, i thought about that but it seemed kind of crazy. It> surprises me> a little that Infinity isn't a singleton class like NilClass in ruby.
I guess that is because there are actually 2 infinities and both are
valid
values with well-defined operations in IEEE754.
Regards,
Florian
--
Florian G.
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