1 Answer

This problem can be solved using the heat capacity.Inside the calorimeter, the temperature equilibrates. Meaning, when the water (30 degrees) is added to a hot silver (350 degrees) there will come a time that their temperature will be the same. That same temperature is called the final temperature.

Heat capacity has the formula

q = mc delta T

inside the calorimeter, we can assume that

qwater = -qsilver

applying the formula we can have;

(mc...

This problem can be solved using the heat capacity.Inside the calorimeter, the temperature equilibrates. Meaning, when the water (30 degrees) is added to a hot silver (350 degrees) there will come a time that their temperature will be the same. That same temperature is called the final temperature.

Heat capacity has the formula

q = mc delta T

inside the calorimeter, we can assume that

qwater = -qsilver

applying the formula we can have;

(mc delta T)water = -(mc delta T)silver

where m= mass of the material

c = specific heat constant for the material

delta T is the change of temperature (in Kelvin)

We can substitute the values now. (remember we convert Celsius to Kelvin)