Posted by ted rees
a resident of Waverly Park
on Jul 7, 2011 at 10:43 pm

Why not have AT&T provide a few calculations to prove the radiation intensity point? At least we should know how much power a cell phone transmits, and how much power a tower transmits.
The power per unit area at a distance depends on how the power spreads out. One would expect that the cell phone power spreads out over a wide angle since it needs to strike a tower. One would also expect that a towers power spreads out widly since it needs to find a cell phone anywhere near the ground. One would expect the tower power to be at least as high as the phone power, since it needs to travel just as far as the phone's power. The tower power might be higher since it is not limited by battery drain, or danger from being next to an ear.
What are the numbers?