kirchoffs current law states that sum of currents entering a node =0 |dw:1340289589176:dw|
so that will be\[i_2-i_1+35=0\]
now to find i2
u apply kirchoffs voltage law around the loop i marked with an arrow
|dw:1340289675976:dw|
\[-10+10i_2+20=0\]\[10i_2=-10\]\[i_2=-1A\]the minus only means its in the opposite direction than its supposed to be
substitute i2=-1 in the first equation
\[-1-i_1+35=0\]\[-i_1=-34\]\[i_1=3\]