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Servlet Tutorials

What is the difference between init() and init(ServletConfig) ?

Before start we have to understand the servlet flow.
For example you have servlet LoginServlet which extends HttpServlet
public class LoginServlet extends HttpServlet{
}
And your HttpServlet internally extends GenericServlet.

Now servlet container flow
Step 1. Loads the servlet class and create instance of the servlet class (LoginServlet).
LoginServlet login = new LoginServlet();
Step 2. Then servlet container create ServletConfig object for that servlet and
Call login.init(ServletConfig);
Case 1 :
If you have overridden init(ServletConfig) method in your servlet then call goes to your
init(ServletConfig) method .
public void init(ServletConfig config) throws ServletException {
System.out.println("\n**** Initializing LoginServlet Init Servlet ********** \n"); super.init(config);
}
It will print ?Initializing LoginServlet Init Servlet? and call goes to supper class GenericServlet init(ServletConfig) method.
In the GenericServlet init(ServletConfig) method there is code
This.config= config // initialize the Servlet config object and it is available to you.
Case 2 :
If you overridden init() method and not overridden init(ServletConfig) method.
Servlet container call login.init(ServletConfig);
There is no method like init(ServletConfig) in your servlet so call directly goes to super class GenericServlet init(ServletConfig) method.
This.config= config // initialize the Servlet config object and it is available to you.
You can get the Servlet config object using getServletConfig() method.

Conclusion: It is BETTER to use init(). If you use init() you have no such worries as calling super.init().
If you use init(servletconfig) and forgot to call super.init(config) then servletconfig object will not set and you will not get the servletconfig object.