let X~N(mu,sigma^2),Y~Gamma(alpha,Beta) . X and Y are independent , the moment generating function is e^(ut + sigma^2*t^2)/2 for X and (1-Beta)^-alpha for Y. Find mgf of X+Y....I know if you have two indp. var. you multiply them to get the answer, but what form do you leave it in. My answer is e^(ut + sigma^2*t^2)/2 ((1-Beta)^-alpha . Can this answer be broken down anymore?

2)Also how do you compute mgf for 3X? Is it just 3(e^(ut + sigma^2*t^2)/2) or do you find the differiate 3 times?

3) last question computing mgf for these types of problems 2+ Y or 2 + 2X + 3Y. Is it just 2 + (1-Beta)^ -alpha and 2 + (3X)*(3Y)?
I just need to make sure I understand how to compute the mgf.

Nov 15th 2009, 01:22 AM

Moo

Hello,

Quote:

Originally Posted by pastadee

let X~N(mu,sigma^2),Y~Gamma(alpha,Beta) . X and Y are independent , the moment generating function is e^(ut + sigma^2*t^2)/2 for X and (1-Beta)^-alpha for Y. Find mgf of X+Y....I know if you have two indp. var. you multiply them to get the answer, but what form do you leave it in. My answer is e^(ut + sigma^2*t^2)/2 ((1-Beta)^-alpha . Can this answer be broken down anymore?

It's rather

Quote:

the moment generating function is e^(ut + sigma^2*t^2/2) for X

Quote:

2)Also how do you compute mgf for 3X? Is it just 3(e^(ut + sigma^2*t^2)/2) or do you find the differiate 3 times?

The definition of the mgf is
So the mgf of 3X is , which is the mgf of X taken at the point 3t.

Quote:

3) last question computing mgf for these types of problems 2+ Y or 2 + 2X + 3Y. Is it just 2 + (1-Beta)^ -alpha and 2 + (3X)*(3Y)?
I just need to make sure I understand how to compute the mgf.

Same method as question 2) : write it in the form of the exponential.
Try it (Wink)