Use distributive property for number 1 to solve for "v" because I am assuming that's what you want?
8v-64 + 3v
11v-64
if you're asked to solve for v, set it equal to zero and your answer should be:
\[v = \frac{ 64 }{ 11 }\]
You can check by plugging in your new found v into your original equation and it should equal zero, which it does.