Intermediate Algebra (6th Edition)

by
Martin-Gay, Elayn

Published by
Pearson

ISBN 10:
0321785045

ISBN 13:
978-0-32178-504-6

Chapter 2 - Cumulative Review: 21

Answer

23, 49, and 92

Work Step by Step

We are give that the second number is 3 more than twice the first number. So, we assume the first number is x.
The second number is three more than two times x, or 3+2x.
The third number is four times the first number, or 4x.
$x+(3+2x)+4x=164$
$7x+3=164$
$7x=161$
$x=23$
So the numbers are:
$23$
$3+2\times23=49$
$4\times23=92$