i meant the & as the address operator.my question s that for all other data type for reading the input we are using &(ampersan) in the scanf function,but while we are reading strings we are not using &.can i know the reason for that
eg;

n C, a string is stored as a null-terminated char array. This means that after the last truly usable char there is a null, hex 00, which is represented in C by '\0'. The subscripts used for the array start with zero (0). The following line declares a char array called str. C provides fifteen consecutive bytes of memory. N.B. Only the first fourteen bytes are usable for character storage, because one must be used for the string-terminating null.

char str[15];

The following is a representation of what would be in RAM, if the string "Hello, world!" is stored in this array.

The name of the array is treated as a pointer to the array. The subscript serves as the offset into the array, i.e., the number of bytes from the starting memory location of the array. Thus, both of the following will save the address of the 0th character in the pointer variable ptr.

ptr = str;
ptr = &str[0];

As because the name of the array is treated as a pointer you do not need to use the address-of operator because the pointer is itself an address.
I hope I was able to help you out.