SAT: How to Solve IMPOSSIBLE Math Problems!

SAT, Study and Triumph: How to Solve IMPOSSIBLE Math Problems! Have you ever seen a math question that just seemed like it was too impossible to solve? Whether it was during a practice test, or during some assigned homework, you saw that problem and just thought, “Wait…what??” With this first webisode of “Study and Triumph”, Cambrian will help show you how those “impossible” math problems might not be so difficult after all, so you can walk in on test day confident that you’ll triumph in the Math section!

Cambrian Thomas-Adams is a 99th percentile SAT instructor for Veritas Prep. He recently graduated cum laude from Yale University with distinction as a Theater Studies major. He is happy to be able to continue the long tradition of teachers in his family and help students tackle the SAT!

Take advantage of Veritas Prep’s free SAT resources at http://www.veritasprep.com/free-sat-resources/

If you’d like to learn more about Veritas Prep’s SAT prep program and find a friendly tutor like Cambrian, go to http://www.veritasprep.com/sat/

That's…wrong…I'm pretty sure. The answer is 1 because the sequence ends its loop on 7, making 9 remainder 1, 3 remainder 2, and finally 1 on remainder 3. This is why 7^1 is 7. In your case 1 would never be reached.

OK, so I have a question. Why did you start with 7^1 and not 7^0? If you start with 7^0, then the pattern would be 1, 7, 9, 3. The answer to the math question is the third number in the pattern, which in this case is 9.