Hyper Mega Net Case Study Solution

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The case study is about CPM and PERT model. It comprises of two assignments. The first assignment requires construction of network diagram, expected time to complete each activity, earliest and latest times that each activity can start and probability to complete project on a specified time. The second assignment requires use of simulation tool, @Risk, SimTools or Triangular Distribution to complete project simulation and derive probability to complete project in specified time.

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Hyper Mega Net Case Study Solution

Загружено:

Описание:

The case study is about CPM and PERT model. It comprises of two assignments. The first assignment requires construction of network diagram, expected time to complete each activity, earliest and latest times that each activity can start and probability to complete project on a specified time. The second assignment requires use of simulation tool, @Risk, SimTools or Triangular Distribution to complete project simulation and derive probability to complete project in specified time.

HYPER MEGA NET CASE STUDY

CPM and PERT - Project Management

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Total Project Time  XXX days (decimals have been ignored)

All activities, as highlighted above, which fall on the critical path are important and hence needs to be completed on schedule in orderto avoid project delay. Activities not falling on the critical path are non-critical activities and resources required for these activities canbe shifted without any project delay, unless critical path is changed.Activity and Expected Time TIME (In Days)

Probability that project will take longer than 210 days (Z>210)Z = (210 – XXX) / 8 = XXThe value of Z at X.XX is X.XX. We need the area to the right of X.1X, hence the probability is (1 – X.X) = X.XX%Probability that project will be completed within 182 days (Z<182)Z = (182 – XXX) / 8 = - X.XXThe value of Z at (-) XXX is XXX. We need the area to the left of XXX, hence the probability is XXX%Calculation for each non critical activity, the total float, free float, and independent float (days)

Expected project completion time  XXX days; Standard Deviation  XX

Probability that project will take longer than 196 days (Z>196)Z = (196 – XX) / 9 = -X.XXThe value of Z at -XXX is XXX. We need the area to the right of – XXX, hence the probability is XXX%Probability that project will done within 168 days (Z<=168)Z = (168 – XXX) / 9 = -XXXThe value of Z at -XX is XXXX. We need the area to the left of -XXX, hence the probability is XXX.Please note detail output of @Risk Simulation is attached.