ChemistryWhat is the pH of a 1.24 mol/L solution of HCN(aq) if its Ka = 6.2 x 10^-10? I am not sure how to this question... I did 6.2x10^-10/ 1.24?? I am not sure if it is right OR are we suppose to find the Kb value which i already did Kb= kw/ka = 1.0x10^-14/6.2x10^-10 = 1.61x10^-5 ...
April 10, 2008