2006-04-23T12:40:54ZFluxBBhttp://www.mathisfunforum.com/viewtopic.php?id=3457What about

y=xlnxy'=lnx+1

y'-y/x-1 -> lnx+1-xlnx/x-1 =lnx+1-lnx-1=0?

]]>2006-04-23T12:40:54Zhttp://www.mathisfunforum.com/viewtopic.php?pid=33764#p33764instead of ]]>http://www.mathisfunforum.com/profile.php?id=31922006-04-23T11:33:36Zhttp://www.mathisfunforum.com/viewtopic.php?pid=33762#p33762And how did you integrate the sides? Is there a formula for this? For future reference.]]>2006-04-23T07:51:19Zhttp://www.mathisfunforum.com/viewtopic.php?pid=33758#p33758ganesh wrote:

Integrating both sides,

logy=log(x-1).

Thats what I get

I'm rather unfamiliar with these concepts. (Beginner) What does dx stand for?