Introductory Algebra for College Students (7th Edition)

by
Blitzer, Robert F.

Published by
Pearson

ISBN 10:
0-13417-805-X

ISBN 13:
978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set: 42

Answer

$4-s^{10}$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the special product of the sum and difference of like terms, the product of the given expression, $
(2-s^5)(2+s^5)
,$ is
\begin{array}{l}\require{cancel}
2(2)-s^5(s^5)
\\\\=
4-s^{10}
.\end{array}