Mathematics for the interested outsider

Isomorphism Theorems for Lie Algebras

The category of Lie algebras may not be Abelian, but it has a zero object, kernels, and cokernels, which is enough to get the first isomorphism theorem, just like for rings. Specifically, if is any homomorphism of Lie algebras then we can factor it as follows:

That is, first we project down to the quotient of by the kernel of , then we have an isomorphism from this quotient to the image of , followed by the inclusion of the image as a subalgebra of .

There are actually two more isomorphism theorems which I haven’t made much mention of, though they hold in other categories as well. Since we’ll have use of them in our study of Lie algebras, we may as well get them down now.

The second isomorphism theorem says that if are both ideals of , then is an ideal of . Further, there is a natural isomorphism . Indeed, if and , then we can check that

so is an ideal of . As for the isomorphism, it’s straightforward from considering and as vector subspaces of . Indeed, saying and are equivalent modulo in is to say that . But this means that for some , so and are equivalent modulo in .

The third isomorphism theorem states that if and are any two ideals of , then there is a natural isomorphism between and — we showed last time that both and are ideals. To see this, take and in and consider how they can be equivalent modulo . First off, and are immediately irrelevant, so we may as well just ask how and can be equivalent modulo . Well, this will happen if , but we know that their difference is also in , so .

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This is mainly an expository blath, with occasional high-level excursions, humorous observations, rants, and musings. The main-line exposition should be accessible to the “Generally Interested Lay Audience”, as long as you trace the links back towards the basics. Check the sidebar for specific topics (under “Categories”).

I’m in the process of tweaking some aspects of the site to make it easier to refer back to older topics, so try to make the best of it for now.