The surface gravities of the Sun’s planets are all close to 1g, 0.38-2.53 (about a factor of e, by chance). The cloud-top gravity of the gas giants is not too interesting here, but I suppose that the gravity on their solid surfaces (if any) does not tend to be higher. So called super-Earth exoplanets seem likely to generally accumulate light gas atmospheres, which decreases their expected solid surface gravity relative to their size as measured during for example transits (I suppose so anyway).

Are there good reasons to expect that in the zoo of planets in the universe, our Earth scores high in the surface gravity top-list? That it is unusual with solid real estate to stand on which has substantially (as in a factor of a few tenths) greater gravity than we have here?

3 Answers
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According to this paper, fig. 4, solid planets of arbitrary mass (up to 3,000 times Earth's mass) don't grow much about three- or four-times the Earth in diameter. That's because interior parts of the planet become compressed by the high pressure. Planets heavier than 3,000 times Earth's mass are in the transition zone to stars. In the case of rocky planets they would become substellar objects, similar in their physical properties (electron degeneracy in the core) to white or black dwarfs, not capable to start nuclear fusion due to lack of light elements in their core.

Surface gravity is proportioal to the mean density $\rho$, and to the radius $r$ of the planet: $g=\frac{4\pi}{3}G\rho r$, with $G$ the gravitational constant.

A planet with roughly the composition of Earth, and 3,000 times the mass of Earth would have about 3-times the Earth's radius, hence the 27-fold volume, and the 3000/27 = 111-fold density. Its surface gravity would hence be 333 g. That's close to the upper bound of surface gravity of what would be called a planet. With a pure iron planet we could go a little beyond. Any surface gravity below this upper bound is possible for a solid planet, at least in theory.

Massive solid exoplanets of
hundreds to thousands of Earth masses may be able to form around
massive stars (B and O stars; 5-120 solar masses) where the protoplanetary
disk would contain enough heavy elements.

B and O type stars are rare (0.13% of main sequence stars) and short-lived (less than 100 million years; more accurately less than $10^{10}\cdot 18^{-2.5}$ years, for mass > 18 solar masses). Hence large solid planets of the described type will also be rare, although a priori not impossible.

The planet with the highest estimated surface gravity discovered thus far (March 8, 2014) is
CoRoT-Exo-3b (add "surface gravity" column to the exoplanets table, and sort by that column):

CoRoT-Exo-3b has a radius of 1.01 ± 0.07 R_Jup and transits around its F3-type primary every 4.26 days in a synchronous orbit. Its mass of 21.66 ± 1.0 M_Jup, density of 26.4 ± 5.6 g cm-3, and surface gravity of logg = 4.72 clearly distinguish it from the regular close-in planet population, making it the most intriguing transiting substellar object discovered so far.

The formation of planets and stars is different, and the "transition zone" you mean, does not exist (brown dwarf desert: there are no detected objects that are in that range of masses). Another problem with you answer is that for those rocky planets you talk about, they would be uncapable of doing nuclear fusion, but still become white dwarfs or black dwarfs. White dwarfs are stellar remnants (meaning they were stars before, so they have done fusion before), and black dwarfs are theoretical objects for which the universe is too young to have them.
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usethedeathstarMar 7 '14 at 8:23

Mass is proportional to the cube of the radius times the mean density. Gravity is proportional to the square of the radius. As a result, is you have two planets with the same density, the larger planet will have the higher gravity.

So Venus is both slightly smaller and slightly less dense than Earth, giving it 90% of Earth gravity. Jupiter is much larger (more than 10 times) but much less dense (about one fourth) giving it 10/4 or about 250% of Earth gravity.

My understanding is that the Earth is fairly small, but unusually dense. Of planets that we can detect with current technology, I would expect that more of them would be larger and/or heavier, as those properties would make them easier for us to detect.

Of all the planets in the universe, I expect that we will find a distribution not too unlike our own Solar System and that Earth will fall just on the high side of average.

Mercury's density is 5.4 so it fits well with its neighbours. Still, it has the same surface gravity as the larger but less dense Mars. So I thought that maybe there are more general physical processes which tend to top out planetary solid surface gravity at about 1g.
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LocalFluffMar 6 '14 at 18:34

Am i reading this wrong, or did you just call 8 datapoints a distribution? Basing the theory of planet formation on what we know of our solar system is doing small number statistics.
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usethedeathstarMar 7 '14 at 17:26

True, but it's the only complete data we have so far. The alternative would be to close the question as "primarily opinion based".
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Donald.McLean♦Mar 7 '14 at 17:45