2 years ago

Solve each system of equations with substitution
-6a-5v=46
-6a-4v=44

You can solve for -6a by adding 4v to both sides of equation 2, giving you\[-6a=44+4v\]
Plug this -6a into the first equation to give you
\[(44+4v)-5v=46\] Solve for v \[v=-2\] plug new v into the original second equation:
\[-6a-4(-2)=44\]solving for a gives you\[a=-6\]