Essential University Physics: Volume 1 (3rd Edition)

by
Wolfson, Richard

Published by
Pearson

ISBN 10:
0321993721

ISBN 13:
978-0-32199-372-4

Chapter 6 - Exercises and Problems: 69

Answer

Please see the work below.

Work Step by Step

We know that
$P=\frac{mgh}{t}$
$\implies P=\frac{mgdsin(\theta)}{t}$
$P=mgsin(\theta)(\frac{d}{t})$
$P=mgsin(\theta)(v)$
This can be rearranged as:
$v=\frac{P}{mgsin(\theta)}$
We plug in the known values to obtain:
$v=\frac{35000}{(1750)(9.8)sin(4.5)}$
$v=26\frac{m}{s}$