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19 Mar 2007, 10:07

My answer is 3.

Since avg is 7 the total is 21
median is 9
so one value is above 9 and other below it.
The value 'below' will be max when value 'above' is min
thats possible when value above is same as median 9
so max possible weight of lightest box is 21 - 9 -9 = 3

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19 Mar 2007, 14:49

Tuneman wrote:

interesting so the median of 8,9,9 is 9?

The median of the set is literally the number in the middle, given that the numbers are arranged from the smallest to the biggest and the number of integers in the set is odd. If the number of integers is even, to find a median, you will need to divide 2 numbers in the middle by 2.