Finding mass in a quanity of heat problem

In a heat treatment, a hot copper part is quenched with water, cooling it from 400 degrees Celsius to 30 degrees Celsius. What was the mass of the part if it loses 80 kcal of heat.

2. Relevant equations

Q=mcΔT

3. The attempt at a solution

m=c ΔT/Q m=(0.093cal/g*C°)(370 C° )/ 80Kcal

I gave this a shot but I don't feel like it's right. Any help and hints or even just setting up the formula is appreciated big time. I have a feeling this one is kind of obvious I'm just not seeing it.