(c) The rate of heat addition, Step 1--2:Qdot12mdot H2H1−()⋅:=Qdot121.931103×=(kJ/s)(d) The rate of heat rejection, Step 3--4:H3Hliqx3 HvapHliq−⋅+:=H4Hliqx4 HvapHliq−⋅+:=H4699.083=H31.919103×=Qdot34mdot H4H3−⋅:=Qdot341.22−103×=(kJ/s)(e)Wdot120:=Wdot340:=Wdot23mdot H3H2−⋅:=Wdot23873.222−=Wdot41mdot H1H4−⋅:=Wdot41161.617=(f)ηWdot23Wdot41+Qdot12:=η0.368=Note that the first law is satisfied:ΣQQdot12Qdot34+:=ΣWWdot23Wdot41+:=ΣQΣW+0=8.2mdot1.0:=(kg/s)The following property values are found by linear interpolation in Table F.1:State 1, Sat. Liquid at TH:H1860.7:=S12.3482:=P13.533:=State 2, Sat. Vapor at TH:H22792.0:=S26.4139:=P23.533:=State 3, Wet Vapor at TC:Hliq112.5:=Hvap2550.6:=P31616.0:=State 4, Wet Vapor at TC:Sliq0.3929:=Svap8.5200:=P41616.0:=(a) The pressures in kPa appear above.(b) Steps 2--3 and 4--1 (Fig. 8.2) are isentropic, for which S3=S2 and S1=S4.Thus by Eq. 6.82):x3S2Sliq−SvapSliq−:=x30.741=x4S1Sliq−SvapSliq−:=x40.241=267