I have the following inverse Laplace -
f = (11s^2 + 172s + 700)/((s + 2)(s^2 + 12s + 100))
InverseLaplaceTransform[f, s, t]
but the answer is in exponential form.
I understand the ExpToTrig command but I want to get the
answer in "cos theta in degree" form -
5Exp[-2t] + 10Exp[-6t]cos(8t - 53.13°)
How do I do that because when I use the ExpToTrig I get
(3 - 4 \[ImaginaryI]) Cosh[(6 + 8 \[ImaginaryI]) t] - (3 - 4 \[ImaginaryI])
Sinh[(6 + 8 \[ImaginaryI]) t]
and don't know what to do to get it to my "cos theta in degree" form.