UghboyancyI don't get it.

1. A 210 N object floats with three-fourths of its volume beneath the surface of the water. What is the buoyant force on the object? Newtons

Is this a trick question? I thought that in case like this.. Fb - W = 0..thus Fb = W..so shouldn't the Fb simply equal 210?

2. A lead block is suspended from the underside of a 0.2 kg block of wood of density of 716 kg/m3. If the upper surface of the wood is just level with the water, what is the mass of the lead block?(The density of lead is 11340 kg/m3)

In this case I know you can figure out the V of the wood block..would you once again use a buoyancy equation?

You should go back and read what buoyancy is all about. I don't think you understand it quite yet.

For number 1, what is the definition of the buoyancy force?

Err...maybe I am missing something but it looks to me as if MD2000 is completely right about that question. The buoyancy force is simply mg (and the information about the volume is irrelevant which, in that sense,makes it a "trick" question).

where [tex]\gamma [/tex] is the specific weight of the fluid and V is the volume of displaced fluid.

Work from there.

Edit, I see what you're saying now. You are correct. But the force is a function of the volume.

I agree with all that but of they are asking the buoyant force and the object is floating and they give the weight of the object to be 210 N then there is no need to even know the fraction of the volume beneath the surface of the specific weight of the liquid! The answer is simply 210 N, period.

That seemed the reasoning of the OP and it seems completely right to me.

what about the second one..am i on the right track as far as the FB - W1 - W2 = 0 equation?

Yes, as long as you mean by F_B the total buoyancy force on both blocks.
So that gives
[tex] F_{B, lead} + F_{B, wood} - m_L g - m_W g =0 [/tex]

Now, using [itex] F_B = \rho_{water} V g [/itex], it should be easy to solve. (notice that you can replace the volume by mass over density, which is a useful thing to do in this problem...it will allow you to solve in one step).