The constant of integration C is the initial kinetic energy of the system.

UNDERSTOOD?

F * x = Work done?
ain't Work done = dE?
how come only one derivate in that equation.that violates the mightiest of the laws:"Every change is simultaneous with at least one other".
& int Fdx = F(x(2)-x(1))
but it's also
& int dE = E(2)-E(1)
and then
E(2)-F(2)x(2)=E(1)-F(1)x(1)=const=0 threrefore

E=Fx

cause

F(1)=F(2)=F
you cannot put starting condition on the staring conditions.it leads no where that's whay that const=0.

Staff: Mentor

Its just different notations in different equations, dock. Apparently wherever you got that from uses dE and E interchangeably. And its not unreasonable to do so since often times a change in E results in a conversion from one form of E to another (such as kinetic being converted to potential).