So closer to the Earth center the weight of the said mass will be 3449kg.

4.8. Validity of planets gravitation constant As per the third Kepler’s law the distance between the Earth and the Sun equals to revolution period Н3 = Т2 and cubic radius of revolution related to gravitation multiplied by the squared revolution period: θ = ???????? (14) ???? Т???? The coefficient θ for all planets is constant and corresponds to gravitation constant, it’s positioning to revolution and rotation of satellites on orbit. As for Jupiter: θ = ????????.9.932 h2 ) = 0.02533 ???? Т???? =718800003 m3 / (11.46.1015 m3/s2 where R is Jupiter radius, G final Jupiter gravitation, Т – period of Jupiter spins around its axis. о The coefficient θ for the Io moon revolving on orbit. θ = ???????? = 4200000003 . m / (127.809.1015 m3/s2 422 h2 )= 0.02535 ???? Т????

where Н is the distance from Jupiter center to Io orbit, G is Jupiter gravitation constant, T revolution period of Io about own orbit. As for the Earth: θ= ???????? ???? Т???? = 63780003 m / (1.37.1012 m3/s2 242 h2 ) = 0.02537 where R is the Earth radius, G is final gravitation, Т is the rotation period around own axis. . As for the Moon at revolution about own orbit: θ = ???????? = 3840000003 m/(398.6.1012 m3/s2 5563560038400 s2 ) = 0.02553 ???? Т???? where Н is the distance from the Earth center to the Moon orbit, G is the Earth gravitation constant, Т is revolution of the Moon about its orbit. Identically validation of gravitation constant correlation is check up for the Earth central core: θ= ???????? ???? Т???? = 12500003 m/(398.6.1012 m3/s2 439.62 s2) =1.953.1018 m3 / 77.028.1018 m3 = 0.02535 The derived average coefficient θ = 0.02535 is used to check up on gravitation constant of each celestial body that makes it to spin around its axis and satellites to revolve about orbit. Coefficient θ – 0.02535 is the ratio of volumetric gravitation constant to squared revolution period which is equalized to all celestial bodies with own gravitation and proves its validity in this gravitation theory θ = ???????? ???? Т???? = 0.02535 (15) Therefore calculate gravitation constant of celestial bodies having data on distance and revolution of satellites which is equal to ratio of volume to squared revolution period multiplied by coefficient 0.02535. G = ???????? (16) ???? Т???? = ???????? ????.???????????????????? Т????4.9. Specific character of the solar gravitation Calculations of gravitation influence on planets revolution about their orbit and their rotation around own axis have shown that central core of gravitating body, where thermonuclear synthesis occurs, is a basis of gravitation formation. Depending on dimension of the central core planets of the solar system and the Sun have specific characters reflected on their main characteristics. Due to strong gravitation of the Sun all planets revolve about it on remote orbit. To hold planets on different orbits the Sun should have strong and stable gravitation that is easily determined by known formula. Revolution period of planet and distance to the Sun are known therefore the Sun gravitation constant is follows: (16): G = ???????? , ???? Т???? = ???????? ????.???????????????????? Т???? gravitation constant is derived: 32

as for Mercury G = ???????? =(580.108 m)3 / 0.02535 . 76001672 s=133.25 . 1018 m3/s2 ; ????.???????????????????? Т???? as for Venus G = ???????? ????.???????????????????? Т???? = (1080.108 m)3 / 0.02535 . 193946402 s = 132.11. 1018 m3/s2 ; as for the Earth G = ???????? = (1500.108 m)3 / 0.02535 . 315360002 s = 133.87. 1018 m3/s2 ; ????.???????????????????? Т???? as for Mars G = ???????? = (2280.108 m)3 / 0.02535 . 593192162 s = 132.87 . 1018 m3/s2; ????.???????????????????? Т???? as for Jupiter G = ???????? = (7780.108 m)3 / 0.02535 . 3740169602 s = 132.79 . 1018 m3/s2; ????.???????????????????? Т???? as for Saturn G = ???????? = (14260.108 m)3 /0.02535 . 9290505602 s = 132.52. 1018 m3/s2; ????.???????????????????? Т???? as for Uranium G = ???????? = (28690.108 m)3 / 0.02535 . 26493393602 s =132.72 . 1018 m3/s2; ????.???????????????????? Т???? as for Neptune G = ???????? = (44960.108 m)3/0.02535 . 51939792002 s = 132.89 . 1018 m3/s2. ????.???????????????????? Т???? Average gravitation constant of the Sun is G = 132.87.1018 m3/s2 and it is the most powerful within the solar system. This fact proves by itself that the Sun has got strong magnetic field and huge central core. With gravitation constant and having magnetic field the Sun shall get a central core and will revolve with a definite speed. To provide such a high gravitation constant the Sun shall have a core of enormous dimensions. Data analysis carried out by SOHO shown that by the core the Sun spinning speed significantly exceeds the speed derived by its surface. [49][50] The time of existence of separate spots is of several months it means separate groups of spots can be seen during several turns made by the Sun. Exactly this fact (motion of spots on the Sun disc) have given the occasion for proof that the Sun rotates and made possible to measure the Sun spinning period. Sidereal (in relation with stars) period of the Sun is 25.38days (2 192 400s) on the equator and of around 33 days close to poles. With given parameters the Sun surface rotation speed on the equator equals to V = 2 π r / Т = 4370880000m / 2192400s = 1993.65 m/s. SS S Data collected by spacecraft Ulysses has shown that waves are produced deeply inside the Sun and enforce the Earth to tremble in unison as it is reported by European Space Agency (ESA.) Ulysses manufactured by NASA in association with ESA start off in 1990 to observe the Sun and Jupiter. The craft has detected the said changes in the Sun. Observatories have been constantly studied the data received. For ESA lots of earth systems show clear changes that frequently are considered to be an accidental noise. But indeed such trembling is produced by changes occurred in the Sun. Statistic analysis of a big amount of data has shown that such changes are met in geological structures as well as in magnetic field, atmosphere and even in voltage of transoceanic cable lines. In spite of this the changes in atmosphere are taking a form of sound waves that are not heard by a person. Often these waves are not exceeding 5000microhertz, it is of around 18 vibrations per hour while the near threshold of reading is of 16hertz. How the waves are transferred from the Sun to the Earth has not been defined yet. Researchers guess that gravitation field disturbance is caused in the depths of the Sun, transferred to magnetic field and that solar wind which flies away to the interplanetary space (those trembling has been detected by Ulysses.) Then magnetic field of solar wind interacts with the Earth magnetic field and its pulsing is transferred to the planet.[29] Under this theory this event is explained by the following. Waves in the Sun subsurface are produced by the central core. It rotates with a tremendous speed and makes 18turns per hour. The vibration takes place with each turn of the core wherein the T=200. The vibration leads to changes in solar DGDI. This probably creates similar vibrations in all other planets and satellites of the solar system. ???????? Given that coefficient of total average density is known for cosmic gravitation Y = = 8.29 ref ???? ????????