Collision ExampleLecture 12 2 A freight train is being assembled in switching yard. Car 1 has a mass of m1=65 x 103 kg and moves at a velocity v01=0.80 m/s.Car 2 has a mass of m2=92 x 103 kg and moves at a velocity v02=1.3 m/s and couples to Car 1. Neglecting friction, find the common velocity vfof the cars after they become coupled. m2 m1 v02 v01 initial m2 m1 vf final

ExampleLecture 12 3 Conservation of momentumPf=PiPi=m1vo1+m2v02Pf=(m1+m2)vf(m1+m2)vf=m1vo1+m2v02vf=m1v01+m2v02m1+m2vf=(65×103kg)(0.8m s)+(92×103kg)(1.3m s)(65×103kg+92×103kg)=1.1m sA freight train is being assembled in switching yard. Car 1 has a mass of m1=65 x 103 kg and moves at a velocity v01=0.80 m/s.Car 2 has a mass of m2=92 x 103 kg and moves at a velocity v02=1.3 m/s and couples to Car 1. Neglecting friction, find the common velocity vfof the cars after they become coupled.

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Center of Mass Lecture 12 4 •Suppose we want to describe the motions of these galaxies •Each galaxy may have > 1012stars •Can we understand the motion of each galaxy without analyzing the motion of each star?

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