Since i will assume you already know the Standard we can convert as following , Convert your number to base 2 1011.01000 Shift this binary number 1.01101000 2**3 (shifted by 3) add exponent 127+3=130 convert 130 to binary format 10000010 And so we have sign * 2^exponent * mantissa Sign...

For the sizeof operator to give the actual size of the array, you need to: Allocate the array statically Refer to the array within its scope of declaration For example: void func() { int arr[10]; int total_size = sizeof(arr); int num_of_elements = sizeof(arr)/sizeof(*arr); ... } An example of when the...

C and C++ have no idea what an "a20 gate" is and how to enable it. Same for "32 bit protected mode". This will need to be done through specific machine code. Now, the right question would be how to call this code from your C++ program. Depending on the...

An integer constant always has type int. Therefore, in 32 bits mode, t.tv_usec, t.tv_sec and 1000000 are all 32 bits and the result, which overflows, too. Only after the computation is the result converted to 64 bits. If you cast the constant to 64 bits, then t.tv_sec is promoted to...

Relying on the current directory (by using a relative path) in PowerShell is dangerous when interop'ing with Windows. Just execute this sometime: [environment]::CurrentDirectory You will see that PowerShell's notion of current directory doesn't always match the Windows notion of current directory. This is because you can have multiple scripts running...

Hans Passant answered correctly. The push/pop opcodes can be broken down into two micro-ops which do a memory move and an increment/decrement of the stack pointer. If the stack pointer - or any pointer - is updated and then immediately used in the next opcode, an execution stall generally occurs....

It seems that the 2nd arg is being interpreted (either in rust or c) as sizeof string, rather than the value passed from the Rust code. Correct. You are experiencing undefined behavior here. Your C-Function has a different signature from the extern function you declared in Rust-Code. First of...

You want to add 3 to each letter of a string ? The following code is not tested, but it should work. Assuming that your string is a NUL-terminated string, of course. I'm simply checking to see if we're at the end of the string, if we're not it adds...

First I read the address are in .data and .text hold string literals (plus machine code I suppose) after in some other article someone said it's changed and lo longer string literals live in .text but .rodata instead of It's up to the compiler to decide where it wants...

Thanks to everyone that helped me to find a solution (essentially by correcting the grammar in my question). I used py2app, now everything works (no one suggested to try other modules, why?). I hope someone will find this "solution" useful. I know i haven't really found a solution, but that's...

2^32 = 4294967296 - so on a 32 bit architecture you can reach 4 billion addresses in memory. And one byte (8 bit) is stored at each address. So your "maximum memory" is indeed 2^32 bytes or 4 x 2^30 bytes or 4 GiB....

Issue #1: You forgot exit at the end of main and ret at the end of ValidatePIN Issue #2: Irvine32.lib has a CRLF-function. Insert call CrLf, where you wish to have a new line. Issue #3: Typically a function returns a result in EAX. This value in EAX can be...

You need nothing to speed up sqrt for 32-bit values. HotSpot JVM does it automatically for you. JIT compiler is smart enough to recognize f2d -> Math.sqrt() -> d2f pattern and replace it with faster sqrtss CPU instruction instead of sqrtsd. The source. The benchmark: @State(Scope.Benchmark) public class Sqrt {...

assume you are trying to multiple two 32-bit int to a 64-bit result manually, in your macro, ((HIGH_WORD(a) * HIGH_WORD(b)) << 32 shifts beyond the length of a int, so you have that error. if you want to make it work, first change BIG_MULL to a function, and: cast to...

As you noticed, the problem is in your check for the NUL terminator: cmp $0, (%edx,%edi) On 32-bit, the default operand size is a 32-bit word, therefore you'd need to end the string with 4× \0 in order for it to stop (or be lucky and encounter a zero-filled garbage...

Yes it's at&t syntax and if you are confused by it, then switch gdb to intel syntax (set disassembly-flavor intel). You would see something like: add edx, [ecx + esi*4] Anyway, this fetches an operand from memory, from address ecx + esi*4. You can see what that is using x/d...

As I found out the 64 Bit Java Runtime Installation does not override the registry keys of the 32 bit Version. If you use the 32 bit Version of regedit.exe you will find the registry keys which belong to the 32 bit Java Runtime Environment Installation. So the following Batch...

Among two popular instruction set architectures I've worked with (x86 and MIPS), there are no machine instructions to insert bits into the middle of an integer like you described. However, the functionality can be implemented in terms of bitwise shifts, AND, OR, NOT, which are available on all processors and...

All DOS style executables have an 'MZ' as the first two bytes. To identify an MSDOS executable vs. the multitude of other variants the best bet seems to be to read the position of the relocation table at offset 0x0018 in the file, if this is greater than 0x0040 (into...

What's happening is, setreuid returns a zero on success and a -1 on error. You're probably running as a regular user, who isn't allowed to set the user id of the process. For that reason, the return value of setreuid is -1, which in binary is all bits set for...

I found the solution. Under "HKEY_LOCAL_MACHINE/SOFTWARE/Wow6432Node/ODBC/ODBCINST.INI/SQL Anywhere 12" The Strings "Driver" and "Setup" were missing. I added the path to the 32-bit ODBC drivers. Now everything works again....

The program sums up the array correctly. The problem is with returning the result. [Answer corrected, thanks to Jester.] You pass the return value to sys_exit() (this is what mov eax, 1; int 0x80 does). sys_exit() leaves only the lower 8 bits of the return value (other bits are used...

The "2024" means as part of Windows 8. The link says the VB6 runtime is part of Windows and therefore will be supported in the same way as the rest of Windows. For example Windows 8 will be supported until 2024 because that's the support lifecycle for Windows 8. Microsoft...

This happened to me too after I updated Android Studio from a beta version to 1.0. After trying all sorts of things including uninstalling and reinstalling, what finally worked for me was to modify find_java.bat to be hard-coded for 32-bit as described in this message: https://code.google.com/p/android/issues/detail?id=82603 I just modified it...

Well, it seems that debugging on the emulator with a 32 bit OS could only work when working with the Windows Phone 7. As of now, owning a 32 bit OS with Windows 8.1 means that we can only debug with an actual device. The 32 bit does not support...

I hate to answer my own question in such a short time. But for people who has a similar problem like mine, this link shows a method that totally worked for me: http://askubuntu.com/questions/322624/how-do-i-convert-a-x86-rpm-to-a-x86-deb-within-a-x64-system thank you...