Given: abc > 0 which implies that,Out of a,b,c either two of the variables can be negative or all of the three variables can be positive.Suppose a=1, b=2 and c=3.We get, A > B ( A=9 and B=6)Suppose a= -1, b=-2 and c=3We get, B > A ( A=-9 and B=3)Hence, the answer is D.Please rectify if the process is wrong.

A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.

A very straight forward solution, even if we take all as positive..(1) Let \(a=b=c=3\)A=(c(a + b))=\(3(3+3)=18\)B=(abc)=\(3*3*3=27\)so B>A(2) Let \(a=b=c=1\)A=(c(a + b))=\(1(1+1)=2\)B=(abc)=\(1*1*1=1\)so A>B