Calculus 10th Edition

by
Larson, Ron; Edwards, Bruce H.

Chapter 1 - Limits and Their Properties - 1.4 Exercises: 35

Answer

A vertical asymptote at $x=0.$
This discontinuity is not removable.

Work Step by Step

The only restriction on the domain is that $x$ cannot be equal to $0.$
$\lim\limits_{x\to0^-}=-\infty$ and $\lim\limits_{x\to0^+}=+\infty$ hence there is a vertical asymptote at $x=0.$
Vertical asymptotes are not removable.