well in the first problem is 3a=30. so a would equal 10 because 30 divided by 3a is 10. so on the next problem 1a plus 8b is equal to 18. so if a=10 then you can take away ten from both sides. so that would leave 8b =8. so b would = 1 because 8 divided by 8 is 1. so on the next problem 4b -2c= 2. so if b = 1 than 4b = 4. so 4-2c=2. and 4-2=2. so 2c=2. 2 divided by two is one. so c=1. on the next problem 1c+1a+3b=???. if c=1 a=10 and b=1. then 10+1+3=14