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Surviving on $100

Keno Lil | Our question this week is, given a $100 bankroll, a certain
house percentage, and a certain priced ticket, how many games can we play before
our bankroll is consumed?

The answer is easily computed using the formula: Bankroll
divided by PC x amount bet equals Average games to depletion

For those of you who do not want to do this calculation, I have
provided a chart here to save work:

PC=

25%

26%

27%

28%

29%

30%

Bet

Games to Bankruptcy

$1.00

400

385

370

357

345

333

$1.50

267

256

247

238

230

222

$2.00

200

192

185

179

172

167

$2.50

160

154

148

143

138

133

$3.00

133

128

123

119

115

111

$3.50

114

110

106

102

99

95

$4.00

100

96

93

89

86

83

$4.50

89

85

82

79

77

74

$5.00

80

77

74

71

69

67

$5.50

73

70

67

65

63

61

$6.00

67

64

62

60

57

56

$6.50

62

59

57

55

53

51

$7.00

57

55

53

51

49

48

$7.50

53

51

49

48

46

44

$8.00

50

48

46

45

43

42

$8.50

47

45

44

42

41

39

$9.00

44

43

41

40

38

37

$9.50

42

40

39

38

36

35

$10.00

40

38

37

36

34

33

The above figures represent mathematical averages over millions
of games and do not necessarily reflect the real life experience of keno
players. Although it is true that a keno player playing a $1 (30 percent) ticket
on a $100 bankroll can expect to play 333 games before going broke, it is highly
unlikely that he will.

It is indisputable that the more games of keno you play, the
higher your chance of hitting a big winner.

Keno Lil rates low cost, low PCT tickets:

on a scale of five, with five being highest!

The above formula will work for any casino game. If you are
playing a 25-cent video poker game with a 2 percent house edge, $1.25 per hand,
and your bankroll is $100, you can expect, on average, to play 4,000 hands
before going broke.

For any Keno questions, write me c/o GamingToday,
or email me on the web at [email protected].