i being the imaginary number of sqrt(-1)I'm not sure it is correct though

For the second one, I can't seem to get the factors to add up to 7y (the middle term) so I'm stuck hereI want to do (2z+1) (z+6) but doing the "smiley face" check it does not match to the 7y in 2y^2+7y+6=0

For the last one, I also get stuck at factoring

2x-9sqrt(x)+4=02y^2-9y+4=0(2y )(y )=0

1 and 4 or 2 and 2 as the factorals don't match the middle term once again... can u tell me what I'm doing wrong? Thanks

As you'll learn when you read the lesson, no, when the leading coefficient is something other than 1, the rules are changed a bit. For the second exercise, you need to find factors of (2)(6) = 12, not just of 6; for the third, you need factors of (2)(4) = 8, not just of 4.