My advice is that when you find them that you run off a copy of each and then refer to it each week......I myself still do not understand the "bit wise" puzzle but with clm's tables I have been able to solve many of them and with repeated use the concept will become a less daunting task

I would also suggest printing a copy of "skeeter 84"'s exponents table to help with those types of puzzles!

I hate to burst your bubble, but I deleted my 2 and 3-digit exponentiation tables a while back. The exponentiation puzzle supposedly became the extra puzzle; I have no access to it since I'm a non-subscriber. I therefore no longer saw a *need* for my tables, and so I got rid of them.

The key to solving this puzzle is to find cross pairs, if you work on looking for cross pairs the puzzle can be solved reasonably easily.I don't know if cross pairs is the correct name to use, as an example of what I mean by a 'cross pair' in this puzzle cage a1(8:)=1&8 and cage h1(10|)=2&8, so rows 1 and 2 have 8 as a cross pair and no other cell can have a value of 8 in rows 1 and 2.Sometimes cross pairs are obvious, but other times they can hide. It is worth the extra effort to find the cross pairs, they can make a big difference.

So my steps for solving this puzzle (without going into much detail) are:

Look at column c, (a lot can be done in this column).Consider cage d4(3-), with reference to adjacent cells.Then just do all the basics while remembering to look for cross pairs.

kozibrada

Posted on:Sun May 12, 2019 8:22 pm

Posts: 39Joined: Sun Feb 03, 2013 3:25 am

Re: Bitwise OR' |

michaele wrote:

The key to solving this puzzle is to find cross pairs, if you work on looking for cross pairs the puzzle can be solved reasonably easily.I don't know if cross pairs is the correct name to use, as an example of what I mean by a 'cross pair' in this puzzle cage a1(8:)=1&8 and cage h1(10|)=2&8, so rows 1 and 2 have 8 as a cross pair and no other cell can have a value of 8 in rows 1 and 2.Sometimes cross pairs are obvious, but other times they can hide. It is worth the extra effort to find the cross pairs, they can make a big difference.[…]

You probably mean an X-wing strategy – well known in the sudoku world.And I agree, this strategy is very useful in this puzzle, especially “double” X-wing in the top two rows:BC12 (#7) + EF12 (#6) eliminate G1 to candidates 4 and 5; 4 causes no position for 6 in the row 1, therefore G1 = 5, thus 8 in the column F must be placed in the row 7. The rest is already easier…