Urgent Help...Graphs of Sine and Cosine

Please help! I need to find the equation for each of these....I do not understand how to do so...please help...
The Amplitude on 67 looks like it is 3...
How do I solve for the period...If I know that, then I can put it in the equation...

Please help! I need to find the equation for each of these....I do not understand how to do so...please help...
The Amplitude on 67 looks like it is 3...
How do I solve for the period...If I know that, then I can put it in the equation...

On 68, the amplitude is 2
And 70 also appears to be 2

look for when the graph begins to repeat itself. you will realize that for 67 the graph repeats itself twice between and . use that to figure out the period. in 68, the graph has only one oscillation between and , and for 70, we have one and a half periods between and

look for when the graph begins to repeat itself. you will realize that for 67 the graph repeats itself twice between and . use that to figure out the period. in 68, the graph has only one oscillation between and , and for 70, we have one and a half periods between and

Well, since you have the amplitude, to figure out the period, as someone already said, you figure out where it repeats. In 67, it looks like it stops at pi. I got this because it repeates twice between 0 and 2pi, so divide that in half, and you get pi for the period. However, when you put it into you equation you must use:

2pi/K = Period (K is the number in your equation)
2pi/K = pi
Therefore, k = 2, because the two's would cancel out leaving you with just pi. So your equation would be y = 3sin(pi)x . Hope that helps and makes the rest of them easier.

Well, since you have the amplitude, to figure out the period, as someone already said, you figure out where it repeats. In 67, it looks like it stops at pi. I got this because it repeates twice between 0 and 2pi, so divide that in half, and you get pi for the period. However, when you put it into you equation you must use:

2pi/K = Period (K is the number in your equation)
2pi/K = pi
Therefore, pi = 2, because the two's would cancel out leaving you with just pi. So your equation would be y = 3sin(pi)x . Hope that helps and makes the rest of them easier.

you mean k = 2

i don't think the poster was having problems with writing the formula. it was actually identifying the period here that was the issue

i don't think the poster was having problems with writing the formula. it was actually identifying the period here that was the issue

Yup, you're right, I meant K.
I didn't mean to quote you there, I meant to quote the original question.
And yes, it may have been the period, but I always forget or get a little confused once trying to figure out K, so I thought I would throw that in there.