Just a suggestion for future videos. Do you think you could have the
question displayed the wholeway through the walkthrough of a certain
question so that it is easier to keep track of what we are trying to find a
solution to﻿

At 24:38 mins. Why is it 12v at the left side and 0v at the right side.
aren’t the electrons flowing from negative to positive, so right side would
be 12v and it would decrease due to voltage drop going through the
resistors and then 0v at the left side..so it goes to the battery again
(positive side of it). Doesn’t the way you put in the battery effect the
answer?? ﻿

Dr Physics, thank you so much for taking the time to make these videos.
They are incredibly useful and I am so grateful that you take your time to
explain how you got to answers. It’s one thing just finding a mark scheme
but I’m glad you actually increase my understanding on the errors I have
made by explaining the steps thoroughly.﻿

I can’t help but notice 27:00 to 32:20 was somewhat overcomplicated, and
could be replaced with:
Rtotal = 30 + (50^-1 + (10 + 40)^-1)^-1 = 55ohm
Terminal current = (12)/(55) = 0.22A
As each branch of the combination has the same voltage, AB current =
(0.22)/(2) = 0.11A﻿