Well it's a way of rewarding those who paid more with more chances to get them. Someone like swingman who bought 20 slots should have a much better chance than someone who only bought 1 slot

I feel it should be done by how many slots were purchased. Just 1 random for a 10 cases all at once. So if 20 slots purchased, 20 slots in the random. 1 slot purchased, 1 slot in the random. Keep it simple.

1) Re-random each case, and the top 5 people (no duplicates per case) get 9 codes each. I would keep whatever's left.

2) Give everybody the same number of codes that they purchased slots for (i.e. jusrelax would get 1...hobbiewt would get 9...Swingman would get 20), for a total of 300, then re-random each case and give the top 2 people 5 each. I would keep whatever's left.

Either option is fine with me. My personal vote would go for option #1. I think for those who purchased between 1-5 slots the 1st option would give them a better chance at codes so that might be the way to go. Also you need at least 8 cards for a full lineup, and the only way to guarantee that for anyone who purchased less than 3 slots is option #1. I don't see much of a point in getting codes if won't even be able to field a full team (except for the slight chance of winning the blue wave redemption).

Figure if someone bought 1 slot they would get 1 code (which 1 code by itself is useless in this), and they have a 2 (top 2 people)/30 or 6% chance of getting 5 more codes. In option 1 if they bought 1 slot they would have a 5 (top 5 people)/30 or a 17% chance of getting 9 codes (a full lineup). I think that should give everyone a good perspective

I like option 2. reward those that bought in to the break with more spots.

Personally I think option 1 does. I own 10 slots as well, in option 2 you'd be guaranteed 10 slots and then have a 2/30 chance in each case of getting just 5 more. With option 1 you dont have any guarantees but if you're in every case you have a 5/30 chance in each one of getting 9 codes. Better chance of hitting it big with the 1st option, especially if you have 20 slots. I'd say option 1 is a win win for all kinds of buyers... But my vote only counts for 1

Ok, I need to get up about 2 hours before sunrise tomorrow, so I'm hitting the sack.

Here is what I think I'm going to do:

1) Random all 10 cases again;
2) Top 4 names (no duplicates in each case) get 10 codes (400 codes);
3) Random the names of people that didn't get codes, and the top 5 people get 10 codes (50 codes);this is where it may get confusing
4) (Should have 30 codes left) If any of the 30th pick people in any case did not get a lot of 10 codes, those people will be put into a random to receive a lot of 10 codes;
5) I'd like to hang on to the rest as compensation.

Feel free to discuss, but the only way I'm not going to go this route is if someone has a VERY strong reason and argument against it, and proposes an equally fair plan.

Also might help to place a rule that if you're gonna allow trading of the code cards that each person must keep at least 1-2 codes in their possession, just in case we get shorted from the odds with them so that it doesn't create a chaos of tracking down the traded ones... Topps first year doing this with bowman, something tells me to expect some flaws

Ok, I need to get up about 2 hours before sunrise tomorrow, so I'm hitting the sack.

Here is what I think I'm going to do:

1) Random all 10 cases again;
2) Top 4 names (no duplicates in each case) get 10 codes (400 codes);
3) Random the names of people that didn't get codes, and the top 5 people get 10 codes (50 codes);this is where it may get confusing
4) (Should have 30 codes left) If any of the 30th pick people in any case did not get a lot of 10 codes, those people will be put into a random to receive a lot of 10 codes;
5) I'd like to hang on to the rest as compensation.

Feel free to discuss, but the only way I'm not going to go this route is if someone has a VERY strong reason and argument against it, and proposes an equally fair plan.