WHomework set 9_solns_2011 - Homework set # 9 Problems:...

Homework set # 9 Problems: 19.20, 22; 20.1, 3 Solutions: 19.20The magnitude of the torque is sinNBIA, where is the angle between the field and the perpendicular to the plane of the loop. The circumference of the loop is 22.00mr, so the radius is 1.00 mrand the area is 1mAr. Thus,  32311 0.800 T 17.0 10 Amsin90.04.33 10 N m19.22Note that the angle between the field and the perpendicular to the plane of the loop is 90.030.060.0. Then, the magnitude of the torque is      sin100 0.80 T 1.2 A0.40 m0.30 msin60.010 N mNBIAWith current in the –ydirection, the outside edge of the loop will experience a force directed out of the page (+zdirection) according to the right hand rule.

This is the end of the preview. Sign up
to
access the rest of the document.