Notes: After the execution of statement: int resultA = mBallX / mBallY;, resultA will be 20 (100 / 5). Similarly, after the execution of float resultB = mBallX / 3; the value of resultB will be 33. (Division of two integers will result in an integer. To force a floating point division the code should have been float resultB = mBallX / 3f;
The 3f would force a floating point division.)

Notes:
After the execution of statement: int resultA = mBallX % mBallY;, resultA will be 0 because 100 is divisible by 5 and there will be no remainder. Similarly, after the execution of int resultB = mBallX % 3;, resultB will be 1 because 100 = (33 x 3) + 1. That is when 100 is divided by 3, there will be a remainder of 1.