For 1, we can divide both sides by e^x to get:
∫ 1 / (e^x + e^-x) . dX
Have you been taught that cosh(x) = 0.5 (e^x + e^-x)?
So we have:
∫ 1 / 2cosh(x) . dx
= 0.5 ∫ 1 / cosh(x) . dx
= 0.5 ∫ sech(x) . dx
Are you able to go on from here or have I just made it even more complicated?