Tutor profile: Saharnaz S.

Questions

Subject: Basic Math

If you multiple the last digit from left in 5 and add the answer to other digits, it should be dividable to 7.
(7*5) + 5 +3= 43
(3*5) + 4 =19
so this number is not dividable to 7.

Subject: Economics

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Question:

How can we decide as a decision maker of a company if to reject or accept a project?

Inactive

Saharnaz S.

Answer:

by calculating IRR, MIRR, PV, IP, and the payback period and comparing it with WACC we can decide.

Subject: Statistics

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Question:

How many 3 digit numbers can we make with 0123456 which is dividable by 2 and the numbers can not be repeated ?

Inactive

Saharnaz S.

Answer:

The answer is 105. in the first condition we assume that we would not choose 0 for the last digit so first we choose one number out of 3 even numbers except 0 for the last digit from left. Then we choose 1 between 5 remaining numbers except 0 for the first digit from left. and finally we choose one from 5 remaining numbers for the middle digit. the answer is 75. In the second condition we chose 0 for the last digit and then choose one out of 6 remaining numbers for the middle and one out of 5 remaining numbers for the first digit so the answer here is 30. total conditions is 75+30=105

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