So the u above is Vo??
Not use to that letter for something, or what do you label it as?
Because it's relative to the balloon, anything going down, that was negative, is now positive then??

Yes, my u is your Vo.

If you take up as positive (which is what you seem to want to do) and note that the origin is the balloon at the time of release (I took this as the origin in my previous reply too but assumed you realised this) , then:

u = 3 m/s
d = -9.5 m
a = -9.8 m/s^2
t = ?

Note: It seems you might need to spend more than 8 minutes doing the thinking I suggested that you do.

Hey Mr,
I was not getting something, but now I understand. I had to find V, then with that I can input it into V=Vo+at and I got an answer of 1.7s.
Thank you. This is still fairly new to me, and to understand, evening reading out of my book, has me a bit confused. thank you again.