On 24 Mrz., 14:42, William Hughes <wpihug...@gmail.com> wrote:> On Mar 24, 12:13 pm, WM <mueck...@rz.fh-augsburg.de> wrote:>> > On 24 Mrz., 11:02, William Hughes <wpihug...@gmail.com> wrote:>> > > On Mar 24, 10:23 am, WM <mueck...@rz.fh-augsburg.de> wrote:>> > > > On 23 Mrz., 23:58, William Hughes <wpihug...@gmail.com> wrote:> > > > > WH: this does not mean that one can do something> > > > > WH: that does not leave any of the lines of K> > > > > WH: and does not change the union of all lines.>> > > > This does not mean that one can really do so>> > > It does, however, mean that you have not shown> > > that one can or cannot.>> Have you shown that "one can or cannot".>> Yes or no please.

This question shows that you have not understood or pretend so atleast.

Given actual infinity, namely more naturals than are in any FISON, itis obvious that any FISON can be removed. Your conter arguments areinvalid. So I have shown, that all can be removed without change.

Atual infinite not given (but potential infinity) the list is nothingmore than all its lines. Of course nothing can remain if all lineshave gone. In this case it is obvious that not all lines can beremoved without ending at the empty set whcih is not |N.

So what I have shown depends on the circumstances. The correct resultshould be obvious to everybody, and so shoult the circumstances.