Homework Help:
Equilibrium of a Rigid Body, a boom of a crane

The boom in the figure below weighs 2600 N and is attached to a frictionless pivot at its lower end. It is not uniform; the distance of its center of gravity from the pivot is 35.0 % of its length.

2. Relevant equations
Find the tension in the guy wire.
Find the vertical component of the force exerted on the boom at its lower end.
Find the horizontal component of the force exerted on the boom at its lower end.

3. The attempt at a solution

I have already found the correct answers for the tension in the guy wire=3412N, the vertical component of the force on the boom=7600N, but i'm so confused and cant read my notes and what I did to find the Horizontal component. I wrote down "horizontal=guywire plus jasdlkfjas;dlj" so I just dont know what the jaskdfljs is! please advise!!!!!!!!!!!!!!!!!